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Groups > comp.lang.python > #27777

Built-in open() with buffering > 1

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Please, can anyone explain me the meaning of the
"buffering > 1" in the built-in open()?
The doc says: "...and an integer > 1 to indicate the size
of a fixed-size chunk buffer."
So I thought this size was the number of bytes or chars, but
it is not:

 >>> f = open('myfile', 'w', buffering=2)
 >>> f.write('a')
1
 >>> open('myfile').read()
''
 >>> f.write('b')
1
 >>> open('myfile').read()
''
 >>> f.write('cdefghi\n')
8
 >>> open('myfile').read()
''
 >>> f.flush()
 >>> open('myfile').read()
'abcdefghi\n'

Regards,
Marco

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Built-in open() with buffering > 1 Marco <marco_u@nsgmail.com> - 2012-08-24 06:35 +0200
  Re: Built-in open() with buffering > 1 Marco <marco_u@nsgmail.com> - 2012-08-24 07:21 +0200
    Re: Built-in open() with buffering > 1 Ramchandra Apte <maniandram01@gmail.com> - 2012-08-24 07:32 -0700
  Re: Built-in open() with buffering > 1 Hans Mulder <hansmu@xs4all.nl> - 2012-08-26 10:25 +0200
    Re: Built-in open() with buffering > 1 Marco <marco_u@nsgmail.com> - 2012-08-30 17:39 +0200

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