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Re: Built-in open() with buffering > 1

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`f._CHUNK_SIZE = 5` is modifying Python's internal variables - don't do that
google buffering to find out what it is
buffering is how much Python will keep in memory
f.read(1) will actually read `buffering` bytes of memory so that when you read later, the reading can be done from memory
On Friday, 24 August 2012 10:51:36 UTC+5:30, Marco  wrote:
> On 08/24/2012 06:35 AM, Marco wrote:
> 
> > Please, can anyone explain me the meaning of the
> 
> > "buffering > 1" in the built-in open()?
> 
> > The doc says: "...and an integer > 1 to indicate the size
> 
> > of a fixed-size chunk buffer."
> 
> 
> 
> Sorry, I get it:
> 
> 
> 
>  >>> f = open('myfile', 'w', buffering=2)
> 
>  >>> f._CHUNK_SIZE = 5
> 
>  >>> for i in range(6):
> 
> ...     n = f.write(str(i))
> 
> ...     print(i, open('myfile').read(), sep=':')
> 
> ...
> 
> 0:
> 
> 1:
> 
> 2:
> 
> 3:
> 
> 4:
> 
> 5:012345

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Built-in open() with buffering > 1 Marco <marco_u@nsgmail.com> - 2012-08-24 06:35 +0200
  Re: Built-in open() with buffering > 1 Marco <marco_u@nsgmail.com> - 2012-08-24 07:21 +0200
    Re: Built-in open() with buffering > 1 Ramchandra Apte <maniandram01@gmail.com> - 2012-08-24 07:32 -0700
  Re: Built-in open() with buffering > 1 Hans Mulder <hansmu@xs4all.nl> - 2012-08-26 10:25 +0200
    Re: Built-in open() with buffering > 1 Marco <marco_u@nsgmail.com> - 2012-08-30 17:39 +0200

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