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Writing Java code while high and drunk

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  Writing Java code while high and drunk chad altenburg <cdalten@gmail.com> - 2020-02-17 06:57 -0800
    Re: Writing Java code while high and drunk Arne Vajhøj <arne@vajhoej.dk> - 2020-02-17 12:58 -0500
    Re: Writing Java code while high and drunk Joerg Meier <joergmmeier@arcor.de> - 2020-02-17 22:48 +0100

#39299 — Writing Java code while high and drunk

I *attempted* the following problem on codingbat.com while both high and drunk...

"
Given a string, return true if the number of appearances of "is" anywhere in the string is equal to the number of appearances of "not" anywhere in the string (case sensitive).

equalIsNot("This is not") → false
equalIsNot("This is notnot") → true
equalIsNot("noisxxnotyynotxisi") → true
"

Here is what I came up with...

public boolean equalIsNot(String str) {
  int numberIs = 0;
  int numberNot = 0;
  
  for (int i = 0 ; i <= str.length() - 2; i++) {
    if (str.substring(i, i+2).equals("is") ) {
      numberIs++;
    } 
  }
  

   for (int i = 0 ; i <= str.length() - 3; i++) {
    if (str.substring(i, i+3).equals("not") ) {
      numberNot++;
    }
   }
  
  if (numberIs == numberNot) return true;
  else return false;
}


And here is what I found via Google...

https://github.com/mirandaio/codingbat/blob/master/java/string-3/equalIsNot.java


I don't know which one is more correct. With that, I going to back to listening to my neighbor's having loud sex.

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#39300

On 2/17/2020 9:57 AM, chad altenburg wrote:
(ignoring various non-Java pieces of information)> "
> Given a string, return true if the number of appearances of "is" anywhere in the string is equal to the number of appearances of "not" anywhere in the string (case sensitive).
> 
> equalIsNot("This is not") → false
> equalIsNot("This is notnot") → true
> equalIsNot("noisxxnotyynotxisi") → true
> "
> 
> Here is what I came up with...
> 
> public boolean equalIsNot(String str) {
>    int numberIs = 0;
>    int numberNot = 0;
>    
>    for (int i = 0 ; i <= str.length() - 2; i++) {
>      if (str.substring(i, i+2).equals("is") ) {
>        numberIs++;
>      }
>    }
>    
> 
>     for (int i = 0 ; i <= str.length() - 3; i++) {
>      if (str.substring(i, i+3).equals("not") ) {
>        numberNot++;
>      }
>     }
>    
>    if (numberIs == numberNot) return true;
>    else return false;
> }
> 
> 
> And here is what I found via Google...
> 
> https://github.com/mirandaio/codingbat/blob/master/java/string-3/equalIsNot.java
> 
> I don't know which one is more correct.

They are pretty similar.

I believe there are at least 3 different approaches:
1) simple for loop and equals
2) a tricky loop and indexOf
3) regex

Arne

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#39301

On Mon, 17 Feb 2020 06:57:30 -0800 (PST), chad altenburg wrote:

> I *attempted* the following problem on codingbat.com while both high and drunk...

> "
> Given a string, return true if the number of appearances of "is" anywhere in the string is equal to the number of appearances of "not" anywhere in the string (case sensitive).

> equalIsNot("This is not") → false
> equalIsNot("This is notnot") → true
> equalIsNot("noisxxnotyynotxisi") → true
> "

> Here is what I came up with...
 
Is that missing instructions ? Because otherwise, you can just do:

Function<String, Boolean> equalIsNot = s -> s.split("is", -1).length ==
s.split("not", -1).length;
    

Runnable example:

<https://repl.it/repls/ActiveAlertFactorial>

Liebe Gruesse,
		Joerg

-- 
Ich lese meine Emails nicht, replies to Email bleiben also leider
ungelesen.

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