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Writing Java code while high and drunk

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I *attempted* the following problem on codingbat.com while both high and drunk...

"
Given a string, return true if the number of appearances of "is" anywhere in the string is equal to the number of appearances of "not" anywhere in the string (case sensitive).

equalIsNot("This is not") → false
equalIsNot("This is notnot") → true
equalIsNot("noisxxnotyynotxisi") → true
"

Here is what I came up with...

public boolean equalIsNot(String str) {
  int numberIs = 0;
  int numberNot = 0;
  
  for (int i = 0 ; i <= str.length() - 2; i++) {
    if (str.substring(i, i+2).equals("is") ) {
      numberIs++;
    } 
  }
  

   for (int i = 0 ; i <= str.length() - 3; i++) {
    if (str.substring(i, i+3).equals("not") ) {
      numberNot++;
    }
   }
  
  if (numberIs == numberNot) return true;
  else return false;
}


And here is what I found via Google...

https://github.com/mirandaio/codingbat/blob/master/java/string-3/equalIsNot.java


I don't know which one is more correct. With that, I going to back to listening to my neighbor's having loud sex.

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Writing Java code while high and drunk chad altenburg <cdalten@gmail.com> - 2020-02-17 06:57 -0800
  Re: Writing Java code while high and drunk Arne Vajhøj <arne@vajhoej.dk> - 2020-02-17 12:58 -0500
  Re: Writing Java code while high and drunk Joerg Meier <joergmmeier@arcor.de> - 2020-02-17 22:48 +0100

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