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Re: Writing Java code while high and drunk

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On 2/17/2020 9:57 AM, chad altenburg wrote:
(ignoring various non-Java pieces of information)> "
> Given a string, return true if the number of appearances of "is" anywhere in the string is equal to the number of appearances of "not" anywhere in the string (case sensitive).
> 
> equalIsNot("This is not") → false
> equalIsNot("This is notnot") → true
> equalIsNot("noisxxnotyynotxisi") → true
> "
> 
> Here is what I came up with...
> 
> public boolean equalIsNot(String str) {
>    int numberIs = 0;
>    int numberNot = 0;
>    
>    for (int i = 0 ; i <= str.length() - 2; i++) {
>      if (str.substring(i, i+2).equals("is") ) {
>        numberIs++;
>      }
>    }
>    
> 
>     for (int i = 0 ; i <= str.length() - 3; i++) {
>      if (str.substring(i, i+3).equals("not") ) {
>        numberNot++;
>      }
>     }
>    
>    if (numberIs == numberNot) return true;
>    else return false;
> }
> 
> 
> And here is what I found via Google...
> 
> https://github.com/mirandaio/codingbat/blob/master/java/string-3/equalIsNot.java
> 
> I don't know which one is more correct.

They are pretty similar.

I believe there are at least 3 different approaches:
1) simple for loop and equals
2) a tricky loop and indexOf
3) regex

Arne

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Writing Java code while high and drunk chad altenburg <cdalten@gmail.com> - 2020-02-17 06:57 -0800
  Re: Writing Java code while high and drunk Arne Vajhøj <arne@vajhoej.dk> - 2020-02-17 12:58 -0500
  Re: Writing Java code while high and drunk Joerg Meier <joergmmeier@arcor.de> - 2020-02-17 22:48 +0100

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