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Re: templated lambda issue

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On 14 Jun 2021 13:10, Bonita Montero wrote:
> int main()
> {
>      auto f = []<typename T>() -> T
>      {
>          return 123;
>      };
>      f.operator ()<int>(); // only way ?
> }
> 
> Is the above code the only way to call the lambda ?

I've never used a templated lambda, but if I needed something like that 
I think I'd use a type-indicating argument, like (off the cuff)

    template< class T > struct Use_type_{ using Type = T; };

    auto main() -> int
    {
        const auto f = []( auto t )
        { return static_cast<decltype(t)::Type>( 123 ); };

        return f( Use_type_<int>() );
    }

- Alf

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templated lambda issue Bonita Montero <Bonita.Montero@gmail.com> - 2021-06-14 13:10 +0200
  Re: templated lambda issue David Brown <david.brown@hesbynett.no> - 2021-06-14 14:23 +0200
    Re: templated lambda issue Bonita Montero <Bonita.Montero@gmail.com> - 2021-06-14 14:58 +0200
  Re: templated lambda issue "Alf P. Steinbach" <alf.p.steinbach@gmail.com> - 2021-06-14 15:12 +0200
    Re: templated lambda issue MrSpook_5fdc40@qvqo7xsmj4s.co.uk - 2021-06-14 13:16 +0000

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