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Re: Remove leading zeros from string

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>>> 
>>> ?Replace("32 01 22 88 03", "0", "")
>> 
>> Oops! That's going to replac *ALL* zeros; - the task is to replace *LEADING* 
>> ZEROS ONLY!!
>> 
>
> I devised the following solution. Maybe using regular expressions
> is overkill, but it worked.  Here it is:
>
> Public Sub MyReplace()
> ' Include"Microsoft VBScript Regular Expressions 5.5" in Tools->References
> Dim regEx As New VBScript_RegExp_55.RegExp
>
> Dim s1 As String
> Dim sFinal As String
> Dim sExample As String
>
> sExample = "01 07 08 22 88 06 04"
>
> ' Replace leading zeros (in middle of line)
> regEx.Pattern = " 0"
> regEx.Global = True
> regEx.IgnoreCase = False
> s1 = regEx.Replace(sExample, " ")
>
> ' Remove leading zeros (at beginning of line)
> regEx.Pattern = "^0"
> regEx.Global = True
> regEx.IgnoreCase = False
> sFinal = regEx.Replace(s1, "")
>
> MsgBox sFinal
>
> End Sub
>
>
> - Robert Crandall

Yep, too much typing for me! I already have functions for various filtering 
needs; here's one for removing leading zeros...


Function NoPad_Zeros$(sText$)
' Returns a string with no leading zeros
  Dim vTmp, n&
  Application.Volatile

  vTmp = Split(sText, " ")
  For n = LBound(vTmp) To UBound(vTmp)
    vTmp(n) = CLng(vTmp(n))
  Next 'n
  NoPad_Zeros = Join(vTmp, " ")
End Function

..that you can call from code OR use as a cell formula.

In the IW:
  ?nopad_zeros("01 07 08 22 88 06 04")
  Returns 1 7 8 22 88 6 4

In a cell:
  A1 contains 01 07 08 22 88 06 04
  B1 contains =nopad_zeros(A1)
     displays 1 7 8 22 88 6 4

-- 
Garry

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Remove leading zeros from string Tatsujin <tatsujin.3.r@gmail.com> - 2018-10-13 04:08 -0700
  Re: Remove leading zeros from string Claus Busch <claus_busch@t-online.de> - 2018-10-13 13:19 +0200
  Re: Remove leading zeros from string Ramon-México <cesaramon@gmail.com> - 2018-10-13 21:00 -0700
    Re: Remove leading zeros from string GS <gs@v.invalid> - 2018-10-14 01:55 -0400
      Re: Remove leading zeros from string Tatsujin <tatsujin.3.r@gmail.com> - 2018-10-14 02:33 -0700
        Re: Remove leading zeros from string GS <gs@v.invalid> - 2018-10-14 09:52 -0400
          Re: Remove leading zeros from string GS <gs@v.invalid> - 2018-10-14 10:09 -0400

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