Groups > sci.physics.relativity > #460857

Re: Why does gravity have to be transmitted through particles when gravity isn't a force in general relativity?

From	Odd Bodkin <bodkinodd@gmail.com>
Newsgroups	sci.physics.relativity
Subject	Re: Why does gravity have to be transmitted through particles when gravity isn't a force in general relativity?
Date	2018-06-10 21:19 +0000
Organization	Aioe.org NNTP Server
Message-ID	<pfk4lh$tpu$1@gioia.aioe.org> (permalink)
References	(15 earlier) <2c216db8-65f5-4fbf-ba45-19c05d189029@googlegroups.com> <pfja32$7nv$1@dont-email.me> <591909d1-aacc-4dc4-89f5-b90927079456@googlegroups.com> <pfjp6p$a1m$1@dont-email.me> <268120e4-aaa4-417d-8077-398393ff5d40@googlegroups.com>

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kenseto <setoken@att.net> wrote:
> On Sunday, June 10, 2018 at 2:04:11 PM UTC-4, Volney wrote:
>> On 6/10/2018 10:32 AM, kenseto wrote:
>>> On Sunday, June 10, 2018 at 9:46:12 AM UTC-4, Volney wrote:
>>>> On 6/10/2018 9:12 AM, kenseto wrote:
>>>>> On Saturday, June 9, 2018 at 12:39:58 PM UTC-4, Odd Bodkin wrote:
>>>>>> kenseto <setoken@att.net> wrote:
>>>>>>> On Saturday, June 9, 2018 at 9:48:01 AM UTC-4, Odd Bodkin wrote:
>>>>>>>> kenseto <setoken@att.net> wrote:
>>>>>>>>> On Friday, June 8, 2018 at 6:31:37 PM UTC-4, Odd Bodkin wrote:
>>>>>>>>>> There is a formula for the centripetal acceleration. What’s the formula for
>>>>>>>>>> the tangential acceleration? If If you were to calculate the tangential
>>>>>>>>>> acceleration of the moon, how would you do it?
>>>>>>>>> 
>>>>>>>>> 
>>>>>>>>> There is a formula for centrifugal acceleration and that is tangential
>>>>>>>>> acceleration.
>>>>>>>> 
>>>>>>>> Alright what is that formula, and what is the tangential acceleration of
>>>>>>>> the moon?
>>>>>>> 
>>>>>>> You look it up in the internet
>>>>>> 
>>>>>> So you made some claim about a formula for centrifugal and tangential
>>>>>> acceleration, and when anybody asks where you got that, you just dodge?
>>>>> 
>>>>> As you said nobody is here to educate you.....look it up.
>>>> 
>>>> I looked it up for you, Ken. The tangential acceleration for a circular
>>>> orbit is 0. What does that mean for your hypothesis?
>>> 
>>> Sigh....the satellite is constantly changing tangential direction,
>>> that’s tangential acceleration.
>> 
>> NO IT IS NOT!!
> 
> Yes it is.
> 
>> 
>> It looks like you don't even know the meaning of tangential 
>> position/velocity/acceleration.  It is all where you are in a rotating 
>> frame.
> 
> No sir, I am not in the rotating frame and I can see the rider is
> accelerating toward the wall and presses against the wall, not the wall
> presses against the rider toward the center as you claimed.
> 
>> 
>> position: where you are on the circle.
>> velocity: how fast the circle is rotating.
>> acceleration: how fast the rotation rate is changing.
> 
> These are wrong assertions.
>> 
>> For the moon in orbit, the rotation rate never changes (~1 month) so the 
>> tangential acceleration is 0.
> 
> The direction of tangential motion of the moon is continually changing
> with time and by definition that is tangential acceleration. Learn real
> physics so you won’t embarrass yourself again.
> 

Ken, what’s your motive here? Do you stay alive by being combative? 

Everyone — and I mean everyone — is letting you know that you are wrong.
What you say is counter to Newton, counter to freshman classical physics as
thoroughly explained in hundreds of physics books. Do you REALLY think you
are right and the rest of the world is wrong? 

You were asked to provide a formula for tangential acceleration and
calculate the tangential acceleration of the moon, and you dodged and
avoided answering. Do you REALLY think you’ve fooled anyone?

What are you getting out of this nonsense? What’s in it for you?

-- 
Odd Bodkin — Maker of fine toys, tools, tables

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