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| From | moroney@world.std.spaamtrap.com (Michael Moroney) |
|---|---|
| Newsgroups | sci.physics, sci.math |
| Subject | Re: Solved Circumference of Oval and Ellipse, both simultaneously |
| Date | 2018-01-16 05:29 +0000 |
| Organization | The World : www.TheWorld.com : Since 1989 |
| Message-ID | <p3k2jk$u92$4@pcls7.std.com> (permalink) |
| References | <247e56f0-64ff-4987-93f0-6d768977b49d@googlegroups.com> <8ecf773c-14f7-456c-ae31-22f18633c60b@googlegroups.com> |
Cross-posted to 2 groups.
Archimedes Plutonium <plutonium.archimedes@gmail.com> writes:
>Solved the problem of Circumference for Ellipse, Oval. See no 2.71...
>involved, but see an easy trig function solution
Solved, the problem of whether the ellipse is a conic section.
Some preliminaries:
Top view of the conic section and depiction of the coordinate system used
in the proof:
^ x
|
-+- <= x=h
.' | `.
. | .
| | |
' | '
`. | .'
y <----------+ <= x=0
Cone (side view):
.
/|\
/ | \
/b | \
/---+---' <= x = h
/ |' \
/ ' | \
/ ' | \
x = 0 => '-------+-------\
/ a | \
Proof:
r(x) = a - ((a-b)/h)x and d(x) = a - ((a+b)/h)x, hence
y(x)^2 = r(x)^2 - d(x)^2 = ab - ab(2x/h - 1)^2 = ab(1 - 4(x - h/2)^2/h^2.
Hence (1/ab)y(x)^2 + (4/h^2)(x - h/2)^2 = 1 ...equation of an ellipse
qed
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Solved Circumference of Oval and Ellipse, both simultaneously Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2018-01-15 12:05 -0800
Re: Solved Circumference of Oval and Ellipse, both simultaneously moroney@world.std.spaamtrap.com (Michael Moroney) - 2018-01-16 05:29 +0000
Re: Solved Circumference of Oval and Ellipse, both simultaneously Serg io <invalid@invalid.com> - 2018-01-22 19:38 -0600
Re: Solved Circumference of Oval and Ellipse, both simultaneously benj <benj@nobody.net> - 2018-01-23 12:56 -0500
Re: Solved Circumference of Oval and Ellipse, both simultaneously Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2018-01-23 11:30 -0800
Solved Circumference of Oval and Ellipse, both simultaneously Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2018-01-16 07:26 -0800
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