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Re: "usual arithmetic conversions": please explain something...

From BartC <bc@freeuk.com>
Newsgroups comp.lang.c
Subject Re: "usual arithmetic conversions": please explain something...
Date 2017-03-01 12:04 +0000
Organization A noiseless patient Spider
Message-ID <o96d9b$p64$1@dont-email.me> (permalink)
References <448topoppn.fsf@be-well.ilk.org> <o951vq$ch6$2@dont-email.me> <ln1suhersb.fsf@kst-u.example.com>

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On 01/03/2017 00:59, Keith Thompson wrote:
> BartC <bc@freeuk.com> writes:
>> On 28/02/2017 23:33, Lowell Gilbert wrote:
>>> Given the following program:
>>>
>>>     #include <stdio.h>
>>>
>>>     int main (void)
>>>     {
>>>             unsigned long a = 4000;
>>>             signed long b = -10;
>>>             int c;
>>>
>>>             c = a * b;
>>>             printf("%d\n", c);
>>>
>>>             return 0;
>>>     }
>>>
>>> I am surprised that I get a negative answer. From reading the standard,
>>> my expectation was that the multiplication would convert the signed
>>> operand to unsigned, based on this bit of the standard:
>>>
>>>     Otherwise, if the operand that has unsigned integer type has rank
>>>     greater or equal to the rank of the type of the other operand,
>>>     then the operand with signed integer type is converted to the
>>>     type of the operand with unsigned integer type.
>>>
>>> They've got the same rank, right?
>>>
>>> What am I missing? [It must be something, because I don't even get
>>> warnings on any of several compilers, with messages cranked up high.]
>>
>> Try:
>>
>>               printf("%u\n", c);
>
> No, c is an int.
>
> But do try:
>
>     printf("%llu\n", a * b);


It doesn't make much difference. Trying this (on a machine where long is 
32 bits):

             unsigned long a = 4000;
             signed long b = -10;
             int c;

             c = a * b;
             printf("%d\n", c);
             printf("%u\n", c);
             printf("%X\n", c);

             printf("%d\n", a*b);
             printf("%u\n", a*b);
             printf("%X\n", a*b);

             printf("%ld\n", a*b);
             printf("%lu\n", a*b);
             printf("%lX\n", a*b);

the output is:

-40000
4294927296
FFFF63C0
-40000
4294927296
FFFF63C0
-40000
4294927296
FFFF63C0

That suggests that it's the same pattern which is the expected -40000 
when interpreted as a signed int, and the large positive value otherwise.

Changing a,b between both signed, both unsigned, unsigned/signed and 
signed/unsigned, all produce the same results.

The cases where signed and/or unsigned make a difference to the actual 
arithmetic performed can be tricky to find! I would experiment with 
operations such as ">>" and ">".

Or using 'double c' (or a cast to double) instead of int c. That might 
give more enlightening results, as then you are not imposing your own 
signedness on the answer using an implicit conversion with c=a*b, or an 
explicit one with "%lu":

   double c = a*b;
   printf("%f\n", c);

-- 
bartc

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Thread

"usual arithmetic conversions": please explain something... Lowell Gilbert <lgusenet@be-well.ilk.org> - 2017-02-28 18:33 -0500
  Re: "usual arithmetic conversions": please explain something... BartC <bc@freeuk.com> - 2017-02-28 23:45 +0000
    Re: "usual arithmetic conversions": please explain something... Keith Thompson <kst-u@mib.org> - 2017-02-28 16:59 -0800
      Re: "usual arithmetic conversions": please explain something... Ben Bacarisse <ben.usenet@bsb.me.uk> - 2017-03-01 02:20 +0000
        Re: "usual arithmetic conversions": please explain something... Keith Thompson <kst-u@mib.org> - 2017-02-28 18:51 -0800
      Re: "usual arithmetic conversions": please explain something... BartC <bc@freeuk.com> - 2017-03-01 12:04 +0000
        Re: "usual arithmetic conversions": please explain something... Keith Thompson <kst-u@mib.org> - 2017-03-01 08:25 -0800
          Re: "usual arithmetic conversions": please explain something... BartC <bc@freeuk.com> - 2017-03-01 16:47 +0000
            Re: "usual arithmetic conversions": please explain something... Keith Thompson <kst-u@mib.org> - 2017-03-01 09:43 -0800
              Re: "usual arithmetic conversions": please explain something... BartC <bc@freeuk.com> - 2017-03-01 18:00 +0000
                Re: "usual arithmetic conversions": please explain something... Keith Thompson <kst-u@mib.org> - 2017-03-01 10:15 -0800
                Re: "usual arithmetic conversions": please explain something... Ben Bacarisse <ben.usenet@bsb.me.uk> - 2017-03-01 19:08 +0000
          Re: "usual arithmetic conversions": please explain something... supercat@casperkitty.com - 2017-03-01 09:01 -0800
  Re: "usual arithmetic conversions": please explain something... jameskuyper@verizon.net - 2017-02-28 15:49 -0800
  Re: "usual arithmetic conversions": please explain something... Keith Thompson <kst-u@mib.org> - 2017-02-28 16:03 -0800
    Re: "usual arithmetic conversions": please explain something... Nick Bowler <nbowler@draconx.ca> - 2017-03-01 21:53 +0000
      Re: "usual arithmetic conversions": please explain something... Keith Thompson <kst-u@mib.org> - 2017-03-01 14:18 -0800
  Re: "usual arithmetic conversions": please explain something... Lowell Gilbert <lgusenet@be-well.ilk.org> - 2017-03-01 08:29 -0500
    Re: "usual arithmetic conversions": please explain something... Lowell Gilbert <lgusenet@be-well.ilk.org> - 2017-03-01 09:11 -0500
    Re: "usual arithmetic conversions": please explain something... Keith Thompson <kst-u@mib.org> - 2017-03-01 08:59 -0800
  Re: "usual arithmetic conversions": please explain something... scott@slp53.sl.home (Scott Lurndal) - 2017-03-01 14:00 +0000
    Re: "usual arithmetic conversions": please explain something... "James R. Kuyper" <jameskuyper@verizon.net> - 2017-03-01 10:58 -0500

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