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Groups > sci.physics.relativity > #408239
| From | "Paul B. Andersen" <relativity@paulba.no> |
|---|---|
| Newsgroups | sci.physics.relativity |
| Subject | Re: twin paradox with distant mirror |
| Date | 2017-02-07 16:29 +0100 |
| Organization | albasani.net |
| Message-ID | <o7cp43$q53$1@news.albasani.net> (permalink) |
| References | <ccf40e18-7e01-40eb-bd3b-71c39c983684@googlegroups.com> <9d8acc2e-72b5-4425-81de-936dc9c692da@googlegroups.com> <96b90219-14e6-4c45-a111-4a94063764a4@googlegroups.com> |
On 07.02.2017 08:44, gertjacobusse@gmail.com wrote: > > This is what still puzzles me and why I introduced the mirror. > We know the acceleration: the speed change of B is instant, > like a flash of light that hits a mirror. > And in my opinion I defined how much space B did cover: > two light years in the reference frame of A. https://paulba.no/pdf/TwinsByMetric.pdf See 2.2. v = 0.99c and distance 2 light year [ly], TA = 2/0.99 year ~= 2.02 year > So, if much less than 2 yrs passed for B, TB = T sqrt(1-v^2/c^2) = 2.02 * 0.141 year = 0.285 year (Same as Dono's equation) > then B actuallytraveled much faster than the speed of light... Quite. v' = 2 ly/0.285y ~= 7.02c! Note also that v' = v/sqrt(1-v^2/c^2) = 0.99c/0.141 = 7.02c See below. > or is the amount of space different for B (length contraction?) When B is at the mirror when her clock shows (T/2)sqrt(1-v^2/c^2), then A has moved away with the speed v, and will be at a distance v (T/2)sqrt(1-v^2/c^2) as measured in B's rest frame. The speed of A is obviously v in the B's rest frame. And even more obvious, the speed of B in B's rest frame is zero. So what is moving with the speed 7.02c? It is dx/dt', that is the distance measured in A's rest frame divided by B's proper time. There is no upper limit to this speed. I have a book where this speed is called 'proper speed'. However, this book is from 1965 and I think this name may be obsolete. If we look at the four velocity, we have the components: u = [c dt/dt',dx/dt', dy/dt',dz/dt'] In our case: u = [c/sqrt(1-v^2/c^2),v/sqrt(1-v^2/c^2),0,0] So v/sqrt(1-v^2/c^2) ~= 7c is the spatial component of the four-velocity. Note also |u| = sqrt(-(c/sqrt(1-v^2/c^2)^2+(v/sqrt(1-v^2/c^2)^2) = -c -- Paul https://paulba.no/
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twin paradox with distant mirror gertjacobusse@gmail.com - 2017-02-06 11:55 -0800
Re: twin paradox with distant mirror Ned Latham <nedlatham@woden.valhalla.oz> - 2017-02-06 22:33 +0000
Re: twin paradox with distant mirror "Dono," <sa_ge@comcast.net> - 2017-02-06 15:11 -0800
Re: twin paradox with distant mirror gertjacobusse@gmail.com - 2017-02-06 23:44 -0800
Re: twin paradox with distant mirror gertjacobusse@gmail.com - 2017-02-07 02:46 -0800
Re: twin paradox with distant mirror "Paul B. Andersen" <relativity@paulba.no> - 2017-02-07 16:29 +0100
Re: twin paradox with distant mirror rotchm <rotchm@gmail.com> - 2017-02-06 21:40 -0800
Re: twin paradox with distant mirror "Dono," <sa_ge@comcast.net> - 2017-02-06 22:27 -0800
Re: twin paradox with distant mirror "Paul B. Andersen" <relativity@paulba.no> - 2017-02-07 12:55 +0100
Re: twin paradox with distant mirror gertjacobusse@gmail.com - 2017-02-07 04:51 -0800
Re: twin paradox with distant mirror gertjacobusse@gmail.com - 2017-02-07 05:33 -0800
Re: twin paradox with distant mirror "Dono," <sa_ge@comcast.net> - 2017-02-07 05:45 -0800
Re: twin paradox with distant mirror gertjacobusse@gmail.com - 2017-02-07 06:00 -0800
Re: twin paradox with distant mirror "Dono," <sa_ge@comcast.net> - 2017-02-07 06:17 -0800
Re: twin paradox with distant mirror Odd Bodkin <bodkinodd@gmail.com> - 2017-02-07 08:21 -0600
Re: twin paradox with distant mirror gertjacobusse@gmail.com - 2017-02-07 06:51 -0800
Re: twin paradox with distant mirror "Dono," <sa_ge@comcast.net> - 2017-02-07 07:09 -0800
Re: twin paradox with distant mirror gertjacobusse@gmail.com - 2017-02-08 06:23 -0800
Re: twin paradox with distant mirror mlwozniak@wp.pl - 2017-02-08 06:51 -0800
Re: twin paradox with distant mirror gertjacobusse@gmail.com - 2017-02-08 13:30 -0800
Re: twin paradox with distant mirror mlwozniak@wp.pl - 2017-02-08 22:49 -0800
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