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Re: Maxwell's original 8 equations is better than its Heaviside makeover Re: Faraday and Ampere laws need the same number of terms on rightside of equation

From Odd Bodkin <bodkinodd@gmail.com>
Newsgroups sci.physics
Subject Re: Maxwell's original 8 equations is better than its Heaviside makeover Re: Faraday and Ampere laws need the same number of terms on rightside of equation
Date 2016-10-07 07:27 -0500
Organization Aioe.org NNTP Server
Message-ID <nt84c2$1p2l$5@gioia.aioe.org> (permalink)
References (12 earlier) <11886d93-c5f2-426e-9c33-89648087143c@googlegroups.com> <ae0795ba-c96c-4c82-95e6-fd00231d7dc0@googlegroups.com> <49726365-b440-4e38-8614-4ce460e7f943@googlegroups.com> <ed11b6c4-1fec-4751-8717-6b9847851f2a@googlegroups.com> <53120909-06ef-4ddd-b785-6a7f01ec3a32@googlegroups.com>

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On 10/6/2016 9:37 PM, Archimedes Plutonium wrote:
> So that in Maxwell's original 8 differential equations of EM theory one of
> them is the Lorentz force which embodies the Faraday law and instead of being
> just one term on the rightside of equation it involves three terms:
>
> F = qE + qv + qB
>
> AP

That's not the Lorentz force law.
You're in a steep decline.


-- 
Odd Bodkin --- maker of fine toys, tools, tables

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derivative of B as B1^2 - B2^2; Faraday Law = A*B  + V*B1^2 - V*B2^2; Ampere Law = A*R  + A*B1^2 - A*B2^2 Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-20 09:56 -0700
  derivative of B as B1^2 - B2^2; Faraday Law = A*B  + V*B1^2 - V*B2^2; Ampere Law = A*R  + A*B1^2 - A*B2^2 Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-20 13:56 -0700
    Maxwell history Re: derivative of B as B1^2 - B2^2; Faraday Law = A*B  + V*B1^2 - V*B2^2; Ampere Law = A*R  + A*B1^2 - A*B2^2 Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-20 21:18 -0700
      Maxwell history Re: derivative of B as B1^2 - B2^2; Faraday Law = A*B  + V*B1^2 - V*B2^2; Ampere Law = A*R  + A*B1^2 - A*B2^2 Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-21 01:35 -0700
        Maxwell history Re: derivative of B as B1^2 - B2^2; Faraday Law = A*B  + V*B1^2 - V*B2^2; Ampere Law = A*R  + A*B1^2 - A*B2^2 Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-21 02:03 -0700
          measuring the spin term Re: derivative of B as B1^2 - B2^2; Faraday Law = A*B  + V*B1^2 - V*B2^2; Ampere Law = A*R  + A*B1^2 - A*B2^2 Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-21 13:56 -0700
            spin term in EM laws Re: derivative of B as B1^2 - B2^2; Faraday Law = A*B  + V*B1^2 - V*B2^2; Ampere Law = A*R  + A*B1^2 - A*B2^2 Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-21 19:02 -0700
              spin term experiments Re: spin term in EM laws Re: derivative of B as B1^2 - B2^2; Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-21 23:44 -0700
                Revision-Page17, 3-2, EM theory becomes the axioms over all of physics/ Atom-Totality-Universe / textbook 7th ed Re: derivative of B as B1^2 - B2^2; Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-28 21:37 -0700
                review and inspection of my new equations Re: derivative of B as B1^2 - B2^2; Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-10-03 17:13 -0700
                A*R is displacement voltage not as Maxwell thought-- displacement current Re: review and inspection of my new equations Re: derivative of B as B1^2 - B2^2; Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-10-04 09:06 -0700
                A*R is displacement voltage not as Maxwell thought-- displacement current Re: review and inspection of my new equations Re: derivative of B as B1^2 - B2^2; Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-10-04 13:11 -0700
                Faraday and Ampere laws need the same number of terms on rightside of equation Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-10-04 21:03 -0700
                straightening out the terms Re: Faraday and Ampere laws need the same number of terms on rightside of equation Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-10-05 11:54 -0700
                Re: straightening out the terms Re: Faraday and Ampere laws need the same number of terms on rightside of equation Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-10-05 14:13 -0700
                Re: straightening out the terms Re: Faraday and Ampere laws need the same number of terms on rightside of equation Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-10-05 16:24 -0700
                Re: straightening out the terms Re: Faraday and Ampere laws need the same number of terms on rightside of equation Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-10-05 22:25 -0700
                Maxwell had a better grip on EM with his 8 equations, not the present day 4 Re: Faraday and Ampere laws need the same number of terms on rightside of equation Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-10-06 12:37 -0700
                Maxwell had a better grip on EM with his 8 equations, not the present day 4 Re: Faraday and Ampere laws need the same number of terms on rightside of equation Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-10-06 14:38 -0700
                Maxwell's original 8 equations is better than its Heaviside makeover Re: Faraday and Ampere laws need the same number of terms on rightside of equation Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-10-06 19:37 -0700
                Re: Maxwell's original 8 equations is better than its Heaviside makeover Re: Faraday and Ampere laws need the same number of terms on rightside of equation Mahipal <mahipal7638@gmail.com> - 2016-10-06 20:00 -0700
                F = u(vxH) - dA/dt - electric potential Re: Faraday and Ampere laws need the same number of terms on rightside of equation Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-10-06 21:54 -0700
                Re: F = u(vxH) - dA/dt - electric potential Re: Faraday and Ampere laws need the same number of terms on rightside of equation Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-10-07 10:26 -0700
                Re: F = u(vxH) - dA/dt - electric potential Re: Faraday and Ampere laws need the same number of terms on rightside of equation "Efftard K. Donglemeier" <moderator@gmail.com> - 2016-10-07 12:09 -0700
                F = u(vxH) - dA/dt - electric potential Re: Faraday and Ampere laws need the same number of terms on rightside of equation Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-10-07 12:17 -0700
                Re: F = u(vxH) - dA/dt - electric potential Re: Faraday and Ampere laws need the same number of terms on rightside of equation Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-10-07 13:19 -0700
                Re: Maxwell's original 8 equations is better than its Heaviside makeover Re: Faraday and Ampere laws need the same number of terms on rightside of equation moroney@world.std.spaamtrap.com (Michael Moroney) - 2016-10-07 13:40 +0000
                Re: Maxwell's original 8 equations is better than its Heaviside makeover Re: Faraday and Ampere laws need the same number of terms on rightside of equation Mahipal <mahipal7638@gmail.com> - 2016-10-07 07:52 -0700
                Re: Maxwell's original 8 equations is better than its Heaviside makeover Re: Faraday and Ampere laws need the same number of terms on rightside of equation Odd Bodkin <bodkinodd@gmail.com> - 2016-10-07 07:27 -0500
        Maxwell history Re: derivative of B as B1^2 - B2^2; Faraday Law = A*B  + V*B1^2 - V*B2^2; Ampere Law = A*R  + A*B1^2 - A*B2^2 Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-21 02:16 -0700
    Re: derivative of B as B1^2 - B2^2; Faraday Law = A*B + V*B1^2 - V*B2^2; Ampere Law = A*R + A*B1^2 - A*B2^2 Odd Bodkin <bodkinodd@gmail.com> - 2016-09-22 09:29 -0500
      Re: derivative of B as B1^2 - B2^2; Faraday Law = A*B + V*B1^2 - V*B2^2; Ampere Law = A*R + A*B1^2 - A*B2^2 rbrteline@gmail.com - 2016-10-03 13:25 -0700

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