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Re: This moron thought a magnetic field is only a vector dependent on how it was derived Re: people that do not understand

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Archimedes Plutonium <plutonium.archimedes@gmail.com> writes:

>On Monday, September 19, 2016 at 5:27:16 PM UTC-5, Michael Moroney wrote:
>> Archimedes Plutonium <plutonium.archimedes@gmail.com> writes:
>> 
>(snip)
>> 
>> >The Magnetic Field is always a vector, regardless of any operation placed
>> >upon it. That is the meaning of dipole. Something like a parrot of
>> >understanding cannot grasp for themselves until told. Dipole means
>> >Magnetism requires a Field to mediate the two poles, and hence a vector
>> >is involved.
>> 
>> The magnetic field is a vector, yes, but not for the reasons you give.

>Oh, was it Serigo that whispered in your ear that you were dumb wrong 
>by thinking a magnetic field is a vector only on how it was derived.

Nope, I always knew that the magnetic field and the electric field were
vectors.  They have a magnitude and a direction, which is how vectors
appear to us in 3 dimensional space.

>Eh, what stupidity you have, and why you failed physics.

Nope, I have a degree in electrical engineering, which requires that I
pass physics (which I aced).  Not just the simple fact that you need to
pass certain mandatory physics courses in order to qualify for the degree,
you simply have to actually know the physics in order to have any chance
of passing all the electrical engineering courses you need for the degree.

Meanwhile, you have no degree, much less a physics degree, so if anyone
is a failure at physics, it is you, with all your pretending.

>> I suspect you really don't understand what a vector is, or what the dot
>> products and cross products of vectors are.

>So, when you are found stupid wrong, your comeback is to say "I think 
>you do not understand such and such." You are a stupid twisted fool, a 
>fool that failed physics, and no more belongs in sci.physics than do the 
>spammers.

Instead of addressing my comment, you launch into a personal attack.
That proves to me that you do not, in fact, know what a vector, a
dot product or a cross product are.

>Hope you are not a science teacher in school.

>What a fruitcake,,,,,,,,,,

Meanwhile, while you babble here about corrupting Maxwell's Equations,
scientists and engineers will continue to use the *real* Maxwell's
Equations and physics laws derived from the real Maxwell's Equations in
whole or part, to design and build all kinds of electromagnetic wizardry.
Just as they have been doing very successfully for some 150 years now.
Soon, you'll move on and start babbling about something else, and your
corrupted Maxwell's Equations babble will quickly be forgotten. Meanwhile,
the scientists and engineers, who have never heard of you, will continue
to use the actual Maxwell's Equations and their derivitives to develop
even more electromagnetic wizardry.  The actual Maxwell's Equations are
one of the most successful developments in physics ever.

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How to gather the missing terms in Faraday Law, and yes, Maxwell goofed here Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-18 15:07 -0700
  How to gather the missing terms in Faraday Law, and yes, Maxwell goofed here Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-18 17:25 -0700
  Re: How to gather the missing terms in Faraday Law, and yes, Maxwell goofed here Serigo <invalid@invalid.com> - 2016-09-18 20:32 -0500
    Magnetic Field in most-everything Re: How to gather the missing terms in Faraday Law, and yes, Maxwell goofed here Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-18 19:38 -0700
      Re: Magnetic Field in most-everything Re: How to gather the missing terms in Faraday Law, and yes, Maxwell goofed here moroney@world.std.spaamtrap.com (Michael Moroney) - 2016-09-19 15:51 +0000
        people that do not understand that if you have a Magnetic Field which is always a vector, that multiples thereof are also vectors Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-19 13:07 -0700
          Re: people that do not understand that if you have a Magnetic Field which is always a vector, that multiples thereof are also vectors Serigo <invalid@invalid.com> - 2016-09-19 16:15 -0500
            Re: people that do not understand that if you have a Magnetic Field which is always a vector, that multiples thereof are also vectors Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-19 14:29 -0700
              Re: people that do not understand that if you have a Magnetic Field which is always a vector, that multiples thereof are also vectors Serigo <invalid@invalid.com> - 2016-09-19 19:51 -0500
                Faraday law looks like (V*R^-1)' = A*R + B + constant; Ampere law looks like (A*R)' = B + V*A^-1 + constant Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-19 19:41 -0700
                Re: Faraday law looks like (V*R^-1)' = A*R + B + constant; Ampere law looks like (A*R)' = B + V*A^-1 + constant Serigo <invalid@invalid.com> - 2016-09-20 09:55 -0500
                Re: Faraday law looks like (V*R^-1)' = A*R + B + constant; Ampere law looks like (A*R)' = B + V*A^-1 + constant "hanson" <hanson@quick.net> - 2016-09-20 09:03 -0700
          Re: people that do not understand that if you have a Magnetic Field which is always a vector, that multiples thereof are also vectors moroney@world.std.spaamtrap.com (Michael Moroney) - 2016-09-19 22:26 +0000
            This moron thought a magnetic field is only a vector dependent on how it was derived Re: people that do not understand Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-19 19:23 -0700
              Re: This moron thought a magnetic field is only a vector dependent on how it was derived Re: people that do not understand Serigo <invalid@invalid.com> - 2016-09-19 21:41 -0500
                (A*R)' = A'*R  +  R'*A and derivative (V*R^-1)' = V'*R^-1  +  V*(R^-1)' Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-19 22:12 -0700
                derivative of magnetic field Re: (A*R)' = A'*R  +  R'*A and derivative (V*R^-1)' = V'*R^-1  +  V*(R^-1)' Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-19 23:45 -0700
                Re: (A*R)' = A'*R + R'*A and derivative (V*R^-1)' = V'*R^-1 + V*(R^-1)' Serigo <invalid@invalid.com> - 2016-09-20 10:09 -0500
              Re: This moron thought a magnetic field is only a vector dependent on how it was derived Re: people that do not understand moroney@world.std.spaamtrap.com (Michael Moroney) - 2016-09-20 04:08 +0000
                Re: This moron thought a magnetic field is only a vector dependent on how it was derived Re: people that do not understand Serigo <invalid@invalid.com> - 2016-09-20 10:28 -0500
                Re: This moron thought a magnetic field is only a vector dependent on how it was derived Re: people that do not understand moroney@world.std.spaamtrap.com (Michael Moroney) - 2016-09-20 16:40 +0000
    Someone in Old Physics trying to flesh out Faraday's law Re: How to gather the missing terms in Faraday Law, and yes, Maxwell goofed here Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-18 20:03 -0700
      Re: Someone in Old Physics trying to flesh out Faraday's law Re: How to gather the missing terms in Faraday Law, and yes, Maxwell goofed here Serigo <invalid@invalid.com> - 2016-09-18 22:31 -0500
        Old Physics Faraday law math does not match the experiment Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-18 20:51 -0700
          math that matches is the Product Rule in Differentiation that gives a Lenz law inside of Faraday law Re: Old Physics Faraday law math does not match the experiment Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-19 02:47 -0700
    trying to teach a brainwashed that velocity on Magnetic Field is just another Magnetic Field Re: How to gather the missing terms in Faraday Law, and yes, Maxwell goofed here Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-18 20:20 -0700

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