Groups | Search | Server Info | Keyboard shortcuts | Login | Register [http] [https] [nntp] [nntps]
Groups > comp.lang.python > #80150
| Date | 2014-11-03 12:04 +0100 |
|---|---|
| From | Antoon Pardon <antoon.pardon@rece.vub.ac.be> |
| Subject | Dictionaries with variable default. |
| Newsgroups | comp.lang.python |
| Message-ID | <mailman.15424.1415012757.18130.python-list@python.org> (permalink) |
Is it possible to have a default dictionary where the default is dependant on the key? I was hoping something like this might work: >>> m = defaultdict(lambda key: key+1) But it obviously doesn't: >>> m[3] Traceback (most recent call last): File "<stdin>", line 1, in <module> TypeError: <lambda>() takes exactly 1 argument (0 given) -- Antoon Pardon
Back to comp.lang.python | Previous | Next | Find similar | Unroll thread
Dictionaries with variable default. Antoon Pardon <antoon.pardon@rece.vub.ac.be> - 2014-11-03 12:04 +0100
csiph-web