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Groups > comp.lang.php > #9213
| From | Scott Johnson <noonehome@chalupasworld.com> |
|---|---|
| Newsgroups | comp.lang.php |
| Subject | determine a mysqli_result object |
| Date | 2013-04-27 16:11 -0700 |
| Organization | A noiseless patient Spider |
| Message-ID | <klhlph$vgi$1@dont-email.me> (permalink) |
I have a class that I am converting from mysql to mysqli in PHP 5.2.x
The problem I ran into is this.
Previously I could check the mysql_query if it return a resource by using:
is_resource($resource)
and could parse the resource using mysql_fetch_assoc or similar
and if it was an insert, update, etc.. it would not return a resource
and I would just return a true and carry on.
Now with mysqli it return a mysql_result object.
How do I check for this so I know whether to parse or return
Thanks
Here is a nutshell of what was using for mysql
// Already connected to mysqli
public function query($query){
$resource = $this->connection->query($query);
if($resource) {
if(is_resource($resource)) { // parse
$data = array();
$idx = 0;
while($result = $this->connection->fetch_assoc()) {
$data[$idx] = $result;
// Object assembly
}
} else { // return
// update, insert, etc..
return true;
}
} else {
// error
}
}
Scotty
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determine a mysqli_result object Scott Johnson <noonehome@chalupasworld.com> - 2013-04-27 16:11 -0700 Re: determine a mysqli_result object Scott Johnson <noonehome@chalupasworld.com> - 2013-04-27 16:18 -0700
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