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Groups > comp.lang.php > #8680
| From | bill <william@TechServSys.com> |
|---|---|
| Newsgroups | comp.lang.php |
| Subject | Re: change of color on a field value basis in a table... |
| Date | 2013-03-16 10:34 -0400 |
| Organization | Aioe.org NNTP Server |
| Message-ID | <ki1vu1$a1g$3@speranza.aioe.org> (permalink) |
| References | <6dc42f7d-353e-4ac8-8821-b342bd74e3e1@googlegroups.com> |
On 3/16/2013 9:16 AM, nag wrote:
> Hi,
> I am a newbie to php. Here I am trying to print the table
rows with different colors based on a value of a field.
But it is displaying the very first record in different
color and next is the other color until the date field changes.
>
> suppose:
>
> id dt
> xyz 05 (this is in #a99999 color)
> abc 05 (this is in #ffffff color)
> 123 05 (this is in #ffffff color)
> 324 06 (this is in #a99999 color)
> ccc 06 (this is in #ffffff color)
>
>
> but i need first three (with 05 date) in same color and next
records in other color alternatively.
>
> the following is my code:
>
>
> if($tmp!=$dt){$color="#a99999"; $tmp=$dt;}else{$color="#ffffff";}
>
> while($row = mysql_fetch_array( $result )) {
> $id=$row[1];
>
> $dt=substr($row[5],5,2);
>
> // Print out the contents of each row into a table
>
> $slno++;
> $tmp=$dt;
>
> if($tmp!=$dt){$color="#a99999"; $tmp=$dt;}else{$color="#ffffff";}
>
> echo "<tr bgcolor='$color'><td align='right'>";
> echo $slno;
> echo "</td><td><b>";
> echo $row[0];
> echo "</td><td align='center'>";
> ?>
> <a href="profile.php?id=<?php echo $idnum; ?>"><?php echo $idnum;?>
> </a>
> <?PHP
> echo "</td><td>";
> echo sprintf("%07d",$row[2]);
> echo "</td><td align='center'>";
> echo $row[3];
> echo "</td><td align='center'><b>";
> echo $row[4];
> echo "</td><td align='center'>";
> echo $row[5];
> echo "</td><tr>";
> }
> echo "</table>";
>
> thank you.
>
modestly confused: if I read what you wrote it seems you want
the 05 records to be #a99999 and
all other records to alternate between #fff and some other (as
yet unspecified) color ?
however:
$dt=substr($row[5],5,2);
// Print out the contents of each row into a table
$slno++;
$tmp=$dt; <<< this insures that $tmp will always = $dt
if($tmp!=$dt) { <<< so this will never be true
$color="#a99999";
$tmp=$dt;
}
else { <<< BTW, the brackets are not needed if it is a
single statement, but they are not wrong either
$color="#ffffff";
}
--
bill
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change of color on a field value basis in a table... nag <visitnag@gmail.com> - 2013-03-16 06:16 -0700
Re: change of color on a field value basis in a table... bill <william@TechServSys.com> - 2013-03-16 10:34 -0400
Re: change of color on a field value basis in a table... Arno Welzel <usenet@arnowelzel.de> - 2013-03-16 15:40 +0100
Re: change of color on a field value basis in a table... nag <visitnag@gmail.com> - 2013-03-16 09:17 -0700
Re: change of color on a field value basis in a table... bill <william@TechServSys.com> - 2013-03-17 06:31 -0400
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