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Groups > comp.soft-sys.math.mathematica > #2594

Re: Series[log[x], {x, 0, 3}]

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Hongyi Zhao <hszhao.cn@gmail.com> writes:

> Hi all,
>
> I do the following computation within Mathematica:
>
> Series[log[x], {x, 0, 3}]
>
> Then I get:
>
> log[0]+(log^\[Prime])[0] x+1/2 (log^\[Prime]\[Prime])[0] x^2+1/6 (log^(3))
> [0] x^3+O[x]^4

As you should.

>
> Any hints on this result?  The log[0] is illegal in my mind.

Why? Mathematica doesn't know what 'log' is, so it treats it (correctly)
as a general function.

If you want to calculate the series of the logarithm, use

Series[Log[x],{x,0.3}]

(Note: Log, not log)

-- 
Space - The final frontier

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Thread

Series[log[x], {x, 0, 3}] Hongyi Zhao <hszhao.cn@gmail.com> - 2011-05-21 10:44 +0000
  Re: Series[log[x], {x, 0, 3}] Erik Max Francis <max@alcyone.com> - 2011-05-22 10:56 +0000
  Re: Series[log[x], {x, 0, 3}] Oliver Jennrich <oliver.jennrich@gmx.net> - 2011-05-22 10:56 +0000
  Re: Series[log[x], {x, 0, 3}] Peter Pein <petsie@dordos.net> - 2011-05-22 10:58 +0000

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