Groups | Search | Server Info | Keyboard shortcuts | Login | Register [http] [https] [nntp] [nntps]
Groups > comp.soft-sys.math.mathematica > #2588
| From | DrMajorBob <btreat1@austin.rr.com> |
|---|---|
| Newsgroups | comp.soft-sys.math.mathematica |
| Subject | Re: Series[log[x], {x, 0, 3}] |
| Date | 2011-05-22 10:53 +0000 |
| Organization | Steven M. Christensen and Associates, Inc and MathTensor, Inc. |
| Message-ID | <iraq06$llg$1@smc.vnet.net> (permalink) |
The function is called Log. (ALL Mathematica built-ins start with capital
letters.)
Log has a singularity at 0, so you'd have to expand around some other
point, such as 1:
Series[Log@x, {x, 1, 3}]
(x-1)-1/2 (x-1)^2+1/3 (x-1)^3+O[x-1]^4
Bobby
On Sat, 21 May 2011 05:44:59 -0500, Hongyi Zhao <hszhao.cn@gmail.com>
wrote:
> Hi all,
>
> I do the following computation within Mathematica:
>
> Series[log[x], {x, 0, 3}]
>
> Then I get:
>
> log[0]+(log^\[Prime])[0] x+1/2 (log^\[Prime]\[Prime])[0] x^2+1/6
> (log^(3))
> [0] x^3+O[x]^4
>
> Any hints on this result? The log[0] is illegal in my mind.
>
> Regards.
> --
> .: Hongyi Zhao [ hongyi.zhao AT gmail.com ] Free as in Freedom :.
>
--
DrMajorBob@yahoo.com
Back to comp.soft-sys.math.mathematica | Previous | Next | Find similar | Unroll thread
Re: Series[log[x], {x, 0, 3}] DrMajorBob <btreat1@austin.rr.com> - 2011-05-22 10:53 +0000
csiph-web