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Groups > comp.soft-sys.math.mathematica > #1791
| From | "Sjoerd C. de Vries" <sjoerd.c.devries@gmail.com> |
|---|---|
| Newsgroups | comp.soft-sys.math.mathematica |
| Subject | Re: Simplify results |
| Date | 2011-04-20 08:28 +0000 |
| Organization | Steven M. Christensen and Associates, Inc and MathTensor, Inc. |
| Message-ID | <iom5eg$t89$1@smc.vnet.net> (permalink) |
| References | <iojpot$i4q$1@smc.vnet.net> |
They are the same. Both the nominator and denominator are sign- reversed. Cheers -- Sjoerd More Mathematica questions answered at StackOverflow http://stackoverflow.com/questions/tagged/mathematica On Apr 19, 12:56 pm, "Berthold Hamburger" <b-hambur...@artinso.com> wrote: > Hi, > > This might be a silly question, so please bear with me, but I have been > scratching my head about it for some time now. > > Is there a particular reason why Mathematica (8.01) simplifies the following > fraction reversing the signs in the result: > > IN: > > Simplify[(8a^2b^3(c^2+1)^4-6a^3b^2(c^2+1)^3+14a^4b > (c^2+1)^2)/(4a^3b^2(c^2+1)^2-10a^4b^3(c^2+1)^3)] > > OUT: > > (-7 a^2+3 a b (1+c^2)-4 b^2 (1+c^2)^2)/(a b (-2+5 a b (1+c^2))) > > Reducing the fraction by hand gives me: > > (7 a^2-3 a b (1+c^2)+4 b^2 (1+c^2)^2)/(a b (2-5 a b (1+c^2))) > > Thanks > > Berthold > > -- > > Berthold Hamburger - Cellist/Spain > > Email: beha...@artinso.com > > http://www.artinso.com > > http://www.astronomy.artinso.com
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Simplify results "Berthold Hamburger" <b-hamburger@artinso.com> - 2011-04-19 10:56 +0000 Re: Simplify results "Sjoerd C. de Vries" <sjoerd.c.devries@gmail.com> - 2011-04-20 08:28 +0000 Re: Simplify results Gary Wardall <gwardall@gmail.com> - 2011-04-20 08:29 +0000
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