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Groups > comp.soft-sys.math.mathematica > #1790
| From | "Sjoerd C. de Vries" <sjoerd.c.devries@gmail.com> |
|---|---|
| Newsgroups | comp.soft-sys.math.mathematica |
| Subject | Re: solution |
| Date | 2011-04-20 08:27 +0000 |
| Organization | Steven M. Christensen and Associates, Inc and MathTensor, Inc. |
| Message-ID | <iom5e6$t81$1@smc.vnet.net> (permalink) |
| References | <iojpp7$i52$1@smc.vnet.net> |
Why don't you increase the number of starting values?
With 100 the number of unique solutions found by Mathematica is 42 (a
magic number in certain circles). If you take 260 instead you'll get
100 roots.
Cheers -- Sjoerd
Fast responses to Mathematica questions at StackOverflow
http://stackoverflow.com/questions/tagged/mathematica
On Apr 19, 12:56 pm, amelia Jackson <meli.jac...@gmail.com> wrote:
> Dear MathGroup,
>
> I have a problem. I want to find solution:
> r := Table[
> k /. FindRoot[BesselJ[0, k] + k BesselJ[1, k] == 0, {k, n}], {n, 1, 1=
00}]
>
> but I get about 30 roots. I need about 100 or more.
> I think that "step" "n" tend to Pi
>
> Please for help...
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solution amelia Jackson <meli.jacson@gmail.com> - 2011-04-19 10:56 +0000 Re: solution "Sjoerd C. de Vries" <sjoerd.c.devries@gmail.com> - 2011-04-20 08:27 +0000 Re: solution Gary Wardall <gwardall@gmail.com> - 2011-04-20 08:29 +0000 Re: solution Peter <petsie@dordos.net> - 2011-04-22 09:40 +0000
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