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Groups > comp.soft-sys.math.mathematica > #1539
| From | Bob Hanlon <hanlonr@cox.net> |
|---|---|
| Newsgroups | comp.soft-sys.math.mathematica |
| Subject | Re: Coefficents of terms in an expression containing the matching string |
| Date | 2011-04-08 08:15 +0000 |
| Organization | Steven M. Christensen and Associates, Inc and MathTensor, Inc. |
| Message-ID | <inmg65$q0c$1@smc.vnet.net> (permalink) |
Use proper Mathematica syntax when writing to the group.
y = 0.5*u*Exp[-2 I d1 - d2 - I d4 - phi] -
0.5*k2*k3*u*Exp[-I d2 - I d4 - phi] -
0.5*k2*k4*u*Exp[-I d2 - Id 3 - I phi];
List @@ y /. Exp[_] -> 1
{0.5 u, -0.5 k2 k3 u, -0.5 k2 k4 u}
If you really want to lose the signs then
List @@ y /. {Exp[_] -> 1, x_?Negative -> -x}
{0.5 u, 0.5 k2 k3 u, 0.5 k2 k4 u}
y = 0.5*u*Exp[-2 I d1 - d2 - I d4 - phi] -
0.5*k2^2*k3*u*Exp[-I d2 - I d4 - phi] -
0.5*k2*k4*u*Exp[-I d2 - Id 3 - I phi] -
0.5*k2^2*k5*v*Exp[-I d2 - Id 3 - I phi];
Select[y, ! FreeQ[#, k2^2] &]
-0.5*E^((-I)*d2 - I*d4 - phi)*k2^2*k3*u -
0.5*E^((-I)*d2 - 3*Id - I*phi)*k2^2*k5*v
Bob Hanlon
---- Chelly <chelly85086@gmail.com> wrote:
=============
I have two questions. The solutions may be very simple, but since I am a Mathematica novice, need some guidance.
1) I have an expression:
y = 0.5*u*exp(-2 I d1 - d2 - I d4 - phi) -
0.5*k2*k3*u*exp(-I d2 - I d4 - phi) -
0.5*k2*k4*u*exp(-I d2 - Id 3 - I phi) ;
What command should I use to get just the amplitude of each term, i.e excluding the exponential - exp(). In this case, the results needs to be
{0.5*u, 0.5*k2*k3*u, 0.5*k2*k4*u)
2) The second question is along similar lines. I have an expression and I need to find out the terms that have k2^2 in the amplitude
y = 0.5*u*exp(-2 I d1 - d2 - I d4 - phi) -
0.5*k2^2*k3*u*exp(-I d2 - I d4 - phi) -
0.5*k2*k4*u*exp(-I d2 - Id 3 - I phi) -
0.5*k2^2*k5*v*exp(-I d2 - Id 3 - I phi) ;
In this case, the answer is the second and last term:
0.5*k2^2*k3*u*exp(-I d2 - I d4 - phi) -
0.5*k2^2*k5*v*exp(-I d2 - Id 3 - I phi)
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Re: Coefficents of terms in an expression containing the matching string Bob Hanlon <hanlonr@cox.net> - 2011-04-08 08:15 +0000
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