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| From | Tim Prince <tprince@computer.org> |
|---|---|
| Newsgroups | comp.lang.c |
| Subject | Re: What is truncation for (singed) integer in C ? |
| Date | 2015-09-19 16:38 -0400 |
| Message-ID | <d65vdmFsqvaU1@mid.individual.net> (permalink) |
| References | <6f66f235-1b11-4b0c-b2d8-c49ac3eac78e@googlegroups.com> <87twqq9msk.fsf@bsb.me.uk> |
On 9/19/2015 4:28 PM, Ben Bacarisse wrote: > fl <rxjwg98@gmail.com> writes: > >> I see the following on wikipedia and doubt about negative integer when >> truncating. >> >> https://en.wikipedia.org/wiki/Type_conversion >> /////// >> Data can be lost when floating-point representations are converted to integer >> representations as the fractional components of the floating-point values >> will be truncated (rounded towards zero) >> ....... >> >> I agree for positive integer, truncation in C is towards 0. But for >> negative integer, it looks like away from '0'. For example, for a >> unsigned char 83H, > > Something is already wrong here. You say "but for negative integer" and > the then give an example of "unsigned char 83H". unsigned char 83H is > not negative -- it's unsigned. > >> one bit (LSB) truncation result will be 41H, whose non-truncation value >> (8-bit) is equal to 82H. The real value of 82H plus '1' is 83H. That is, >> 82H < 83H. For these negative numbers, it is not rounded towards zero. >> >> Is the above link not talking the same thing with my understanding? > > I think you are talking here about integer division by two. The article > you cite is about converting floating point values to integers so there > is no direct connection. The rules about integer division have changed > between old C (ANSI C or ISO C from 1990) and modern C (C99 and later) > but in modern C, the result is indeed truncated (rounded towards zero). > > To use your example, signed char c = -125; will give c the bit-pattern > 83 in hex. Note that I can't say c == 0x83 because that is not correct > in C -- do you know why? Now c/2 is -125/2 which, truncated towards > zero is -62. That will "look like" C2 in hex, but, again, c/2 == 0xC2 > is not correct in C. > My references imply that the definition with truncation towards 0 came in with C89. Before that, i/2 might be considered interchangeable with i>>1 regardless of whether 1's or 2's complement was in use, even though they give different results. I would assume that casting from a floating point type to unsigned char would involve an intermediate int representation, but OP seemed to lose track of what was the question.
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What is truncation for (singed) integer in C ? fl <rxjwg98@gmail.com> - 2015-09-19 12:25 -0700
Re: What is truncation for (singed) integer in C ? fir <profesor.fir@gmail.com> - 2015-09-19 12:55 -0700
Re: What is truncation for (singed) integer in C ? fir <profesor.fir@gmail.com> - 2015-09-19 13:20 -0700
Re: What is truncation for (singed) integer in C ? Geoff <geoff@invalid.invalid> - 2015-09-19 13:05 -0700
Re: What is truncation for (singed) integer in C ? Ben Bacarisse <ben.usenet@bsb.me.uk> - 2015-09-19 21:28 +0100
Re: What is truncation for (singed) integer in C ? Tim Prince <tprince@computer.org> - 2015-09-19 16:38 -0400
Re: What is truncation for (singed) integer in C ? James Kuyper <jameskuyper@verizon.net> - 2015-09-19 16:52 -0400
Re: What is truncation for (singed) integer in C ? Keith Thompson <kst-u@mib.org> - 2015-09-19 13:45 -0700
Re: What is truncation for (singed) integer in C ? James Kuyper <jameskuyper@verizon.net> - 2015-09-19 16:46 -0400
Re: What is truncation for (singed) integer in C ? Eric Sosman <esosman@comcast-dot-net.invalid> - 2015-09-19 16:47 -0400
Re: What is truncation for (singed) integer in C ? Joe Pfeiffer <pfeiffer@cs.nmsu.edu> - 2015-09-19 22:55 -0600
Re: What is truncation for (singed) integer in C ? James Kuyper <jameskuyper@verizon.net> - 2015-09-20 10:54 -0400
Re: What is truncation for (singed) integer in C ? Joe Pfeiffer <pfeiffer@cs.nmsu.edu> - 2015-09-20 10:11 -0600
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