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Re: on gdb's sizeof versus gcc's sizeof

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Louis Valence <lvalence@example.com> writes:
>Can you explain this?  I don't get it.
>
>%cat sizeof-long.c
>#include <stdio.h>
>
>int main() {
>  printf("sizeof unsigned long: %ld\n", sizeof (unsigned long));
>  printf("sizeof long: %ld\n", sizeof (long));
>}
>
>%./sizeof-long
>sizeof unsigned long: 8
>sizeof long: 8
>
>%gdb
>GNU gdb (Ubuntu 8.0.1-0ubuntu1) 8.0.1
>
>[...]
>
>(gdb) p sizeof (unsigned long)
>$1 = 4

You may want to use a 64-bit build of GDB instead of the 32-bit:

(gdb) print sizeof(unsigned long)
$1 = 0x8
(gdb) quit

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on gdb's sizeof versus gcc's sizeof Louis Valence <lvalence@example.com> - 2019-09-25 22:03 -0300
  Re: on gdb's sizeof versus gcc's sizeof Keith Thompson <kst-u@mib.org> - 2019-09-25 19:22 -0700
  Re: on gdb's sizeof versus gcc's sizeof scott@slp53.sl.home (Scott Lurndal) - 2019-09-26 13:26 +0000
    Re: on gdb's sizeof versus gcc's sizeof Keith Thompson <kst-u@mib.org> - 2019-09-26 13:08 -0700
      Re: on gdb's sizeof versus gcc's sizeof Louis Valence <lvalence@example.com> - 2019-09-28 16:57 -0300

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