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Groups > comp.lang.c++ > #13605
| From | Ian Collins <ian-news@hotmail.com> |
|---|---|
| Newsgroups | comp.lang.c++ |
| Subject | Re: Help with reading formatted input from an istream |
| Date | 2012-01-27 20:21 +1300 |
| Message-ID | <9of1isF8j0U2@mid.individual.net> (permalink) |
| References | <48680e14-e47a-4778-931e-bc6ec6a40d87@t7g2000vbg.googlegroups.com> |
On 01/27/12 03:12 PM, Ttodir wrote:
> Consider the following program:
>
> #include<iostream>
> #include<iterator>
> #include<string>
> #include<set>
> #include<algorithm>
>
> using namespace std;
>
> typedef string T; // to simplify, always consider T as string
>
> template<typename input_iterator>
> void do_something(const input_iterator& first, const input_iterator&
> last) {
> const ostream_iterator<T> os(cout, "\n");
> const set<T> words(first, last);
> copy(words.begin(), words.end(), os);
> }
>
> int main(int argc, char** argv) {
> const istream_iterator<T> is(cin), eof;
> do_something(is, eof);
> return 0;
> }
>
> The program extracts all the words from an istream (cin) and does
> something with them. Each word is seperated by a white space by
> default. The logic behind the formatted extraction is inside the
> istream_iterator.
>
> What I need to do now is to pass to do_something() two iterators so
> that the extracted words will be separated by a punctuation character
> instead of a white space (white spaces will be considered as "normal"
> characters). How would you do that in a "clean C++ way" (that is, with
> the minimum effort)?
Derive your own input iterator class from std::input_iterator.
--
Ian Collins
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Help with reading formatted input from an istream Ttodir <sanmrtn96@gmail.com> - 2012-01-26 18:12 -0800
Re: Help with reading formatted input from an istream Ian Collins <ian-news@hotmail.com> - 2012-01-27 20:21 +1300
Re: Help with reading formatted input from an istream Leigh Johnston <leigh@i42.co.uk> - 2012-01-27 12:47 +0000
Re: Help with reading formatted input from an istream Ttodir <sanmrtn96@gmail.com> - 2012-01-28 11:02 -0800
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