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Re: Calculate/Interpolate size of y in x^y = z when you do know "number of digits z" and base x?

From Ben Bacarisse <ben.usenet@bsb.me.uk>
Newsgroups comp.lang.javascript
Subject Re: Calculate/Interpolate size of y in x^y = z when you do know "number of digits z" and base x?
Date 2015-05-11 13:56 +0100
Organization A noiseless patient Spider
Message-ID <87oalr8e8a.fsf@bsb.me.uk> (permalink)
References <a82630ee-3383-4c55-8da3-4cb092bcc1ae@googlegroups.com> <f7e8df7f-843c-43e8-8c00-66a30ac810dc@googlegroups.com> <dd8b527d-a2f8-428d-9419-2b5d2017baab@googlegroups.com>

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jonas.thornvall@gmail.com writes:

> Den måndag 11 maj 2015 kl. 13:28:06 UTC+2 skrev jonas.t...@gmail.com:
>> Den måndag 11 maj 2015 kl. 13:22:30 UTC+2 skrev jonas.t...@gmail.com:
>> > If i have a very bignumber z in decimal, i know the number of
>> > digits let us say 100 digits and base is x=64.
>> > 
>> > How can i interpolate, find a closeby y (where base is x). 
>> > I do understand that i can add 1 to y until i reach the neighbourhood.
>> > 
>> > But is there any general rule to use to close in faster when you
>> > do know x and the number of digits in z?
>> 
>> Sorry i was not clear i look for the closest integer of y bigger or smaller.
>
> But maybe assuming y is large like 1000 doing a search closing in by
> setting min and max is faster, than doing the calculation using
> logaritms?

It depends on how y is represented.  You say it is "in decimal".  If
that means it's a string then you just find the . and remove any
trailing digits.  This is so obvious that it can't be whay you mean.
How is z stored in the program?

-- 
Ben.

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Thread

Calculate/Interpolate size of y in  x^y = z  when you do know "number of  digits z" and  base  x? jonas.thornvall@gmail.com - 2015-05-11 04:22 -0700
  Re: Calculate/Interpolate size of y in  x^y = z  when you do know "number of  digits z" and  base  x? jonas.thornvall@gmail.com - 2015-05-11 04:28 -0700
    Re: Calculate/Interpolate size of y in  x^y = z  when you do know "number of  digits z" and  base  x? jonas.thornvall@gmail.com - 2015-05-11 05:47 -0700
      Re: Calculate/Interpolate size of y in  x^y = z  when you do know "number of  digits z" and  base  x? Ben Bacarisse <ben.usenet@bsb.me.uk> - 2015-05-11 13:56 +0100
        Re: Calculate/Interpolate size of y in  x^y = z  when you do know "number of  digits z" and  base  x? jonas.thornvall@gmail.com - 2015-05-11 06:12 -0700
          Re: Calculate/Interpolate size of y in  x^y = z  when you do know "number of  digits z" and  base  x? jonas.thornvall@gmail.com - 2015-05-11 06:19 -0700
          Re: Calculate/Interpolate size of y in  x^y = z  when you do know "number of  digits z" and  base  x? Ben Bacarisse <ben.usenet@bsb.me.uk> - 2015-05-11 21:49 +0100
  Re: Calculate/Interpolate size of y in  x^y = z  when you do know "number of  digits z" and  base  x? "Evertjan." <exxjxw.hannivoort@inter.nl.net> - 2015-05-11 15:19 +0200
    Re: Calculate/Interpolate size of y in  x^y = z  when you do know "number of  digits z" and  base  x? jonas.thornvall@gmail.com - 2015-05-11 06:25 -0700
    Re: Calculate/Interpolate size of y in  x^y = z  when you do know "number of  digits z" and  base  x? jonas.thornvall@gmail.com - 2015-05-11 06:30 -0700
      Re: Calculate/Interpolate size of y in  x^y = z  when you do know "number of  digits z" and  base  x? "Evertjan." <exxjxw.hannivoort@inter.nl.net> - 2015-05-11 18:18 +0200
        Re: Calculate/Interpolate size of y in  x^y = z  when you do know "number of  digits z" and  base  x? jonas.thornvall@gmail.com - 2015-05-11 09:32 -0700
          Re: Calculate/Interpolate size of y in  x^y = z  when you do know "number of  digits z" and  base  x? "Evertjan." <exxjxw.hannivoort@inter.nl.net> - 2015-05-11 19:45 +0200
            Re: Calculate/Interpolate size of y in  x^y = z  when you do know "number of  digits z" and  base  x? "Christoph M. Becker" <cmbecker69@arcor.de> - 2015-05-11 22:58 +0200
              Re: Calculate/Interpolate size of y in  x^y = z  when you do know "number of  digits z" and  base  x? "Evertjan." <exxjxw.hannivoort@inter.nl.net> - 2015-05-11 23:13 +0200

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