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use unintialized_copy where is initialized

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`the difference between *uninitialized_copy* function and *copy* is that the 
*uninitialized_copy* function could copy the object at the location where 
is uninitialized. For example:

    int ia[5] = {1, 2, 3, 4, 5};
    int n = sizeof ia / sizeof *ia;
    int *ib = (int *)malloc(n * sizeof *ia);
    uninitialized_copy(ia, ia + n, ib);

My question is, what if I copy the initialized memory by calling the 
uninitialized_copy function. Instead of allocatiing the memory by calling 
malloc, I use new.
    int *ib = new int[n];
    uninitialized_copy(ia, ia + n, ib);

I works too. But am i correct? If so, what's the difference between copy 
and uninitialized_copy? 

Thanks.

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use unintialized_copy where is initialized Stanley Rice <heconghui@gmail.com> - 2012-02-17 19:03 -0800
  Re: use unintialized_copy where is initialized Paavo Helde <myfirstname@osa.pri.ee> - 2012-02-18 03:05 -0600

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