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Re: Evaluation Order in Function Declaration

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Hello,

Am 02/28/2012 06:22 AM, schrieb Shao Miller:
> Is the evaluation order guaranteed to be left-to-right for the
> declaration of 'baz' in the following code?  Or are the array size
> expressions unsequenced relative to one another, as in 'a + b'?  Or
> something else?
> 
>   #include <stdio.h>
> 
>   int foo(void) { puts("foo"); return 1; }
>   int bar(void) { puts("bar"); return 1; }
> 
>   int baz(int (* x)[foo()], int (* y)[bar()]) { return 0; }
> 
>   int main(void) { return baz(0, 0); }

Yes, not only that it is left to right, you are even allowed to use each
of the preceding identifiers in the expressions. Otherwise things like

double sum(size_t n, size_t m, double A[n][m]) { ... }

could never work reliably.

Jens

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Evaluation Order in Function Declaration Shao Miller <sha0.miller@gmail.com> - 2012-02-28 00:22 -0500
  Re: Evaluation Order in Function Declaration Jens Gustedt <jens.gustedt@loria.fr> - 2012-02-28 10:14 +0100
    Re: Evaluation Order in Function Declaration Kaz Kylheku <kaz@kylheku.com> - 2012-02-28 09:31 +0000
      Re: Evaluation Order in Function Declaration Jens Gustedt <jens.gustedt@loria.fr> - 2012-02-28 13:09 +0100
  Re: Evaluation Order in Function Declaration pete <pfiland@mindspring.com> - 2012-03-08 08:49 -0500

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