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Groups > sci.physics.relativity > #428654
| From | Thomas 'PointedEars' Lahn <PointedEars@web.de> |
|---|---|
| Newsgroups | sci.physics.relativity |
| Subject | Re: The overpass |
| Date | 2017-08-14 15:52 +0200 |
| Organization | PointedEars Software (PES) |
| Message-ID | <2572523.e9J7NaK4W3@PointedEars.de> (permalink) |
| References | <omp0d9$1gbi$1@gioia.aioe.org> <ws-dnVPmJb5vwQ3EnZ2dnUU7_8zNnZ2d@giganews.com> <4284818.GXAFRqVoOG@PointedEars.de> <L6CdnYB8RIyNvAzEnZ2dnUU7_8zNnZ2d@giganews.com> |
Tom Roberts wrote: > On 8/13/17 8/13/17 12:40 PM, Thomas 'PointedEars' Lahn wrote: >> Tom Roberts wrote: >>> On 8/13/17 8/13/17 2:51 AM, LuigiFortunati wrote: >>>> On the overpass C the head A of the train AB encounters the head N of >>>> the train MN traveling in the opposite direction: >>>> -------------M------->N------------------------ >>>> ----------------------C---------------------->x >>>> ----------------------A<-------B--------------- >>>> >>>> Since the two trains have the same length and speed, in the land >>>> reference also the tail B of the train AB encounters the queue M of the >>>> train MN on the same overpass C: >>>> ----------------------M------->N--------------- >>>> ----------------------C---------------------->x >>>> -------------A<-------B------------------------ >>>> >>>> At that point, from the tail of both trains a bomb destroys the flyover >>>> but the trains are now gone and so they are safe. >>> >>> OK. That describes the physical situation. ALL reference frames will >>> agree that A and N reach C simultaneously, and all frames agree that B >>> and N reach C simultaneously, and the overpass is destroyed after both >>> train are gone. >> >> How did you get that idea? Maybe they agree on the two events >> separately, but they cannot agree on both of them. > > You are confused, No, you are. The relativity of simultaneity applies to this situation. > and your discussion considers different events than the > relevant ones. There are just two relevant events (given in the original > description): > #1: N and A reach C simultaneously. > #2: M and B reach C simultaneously. No, the description implies that *an observer at rest in C* sees N and A *and* M and B reach C simultaneously, respectively. That other observers (not comoving with C) do _not_ observe *complete* simultaneity – which is correct – has been explicitly stated by the OP (but they did not consider all implications). > Since #1m,occurs at a SINGLE EVENT in spacetime, all frames will see it as > a single event, so all frames see N and A reach C simultaneously. They may, if that is being agreed on, but: > Ditto for #2. AISB, *all* observers can only agree on either #1 or #2, but _not_ on both. > (They all differ on the value of the time coordinate when each > happens, and on the elapsed time between #1 and #2; all see #1 happen > before #2 because they have timelike separation.) No. >> As I have shown in my picture, if the observers agree on the distance >> that the rear ends of the trains have from C, they must disagree on the >> distance that the front ends of the trains have from C, and so if both >> trains move at the same speed towards C, they must disagree about the >> simultaneity of the arrival of the front ends of the trains at C. > > You have intermixed frames. No. > The trains move at the same speed ONLY in the rest frame of C, Correct. > but you applied that in the frame of each train. No, I do not think so. Of course the speed of the train in its own frame is zero, but then the speed of C in that frame is not. >>> It is only for spacelike-separated events that their order is frame >>> dependent. There are no such events here. >> >> The moving ends of the trains are space-like separated events, > > Yes, BUT IRRELEVANT. No, very relevant. The relativity of simultaneity applies to those events. > Yes, an observer on train AB will measure train MN as shorter than her > own. Yes. > She will also measure it as moving at a slower speed relative to C > than her own train. This statement does not make sense. If we measure the speed of MN relative to C, then we are measuring it *in the frame of C*. If we measure AB’s speed relative to C, then we are measuring it *in the frame of C*, not of AB. > The result is she will see N reach C right as A reaches C, and she will > see M reach C just as B reaches C. Similarly for an observer on train MN. No, I do not think so. -- PointedEars Twitter: @PointedEars2 Please do not cc me. / Bitte keine Kopien per E-Mail.
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The overpass LuigiFortunati <fortunati.luigi@gmail.com> - 2017-08-13 09:51 +0200
Re: The overpass Thomas 'PointedEars' Lahn <PointedEars@web.de> - 2017-08-13 15:53 +0200
Re: The overpass Luigi Fortunati <fortunati.luigi@gmail.com> - 2017-08-13 19:13 +0200
Re: The overpass The Starmaker <starmaker@ix.netcom.com> - 2017-08-13 11:02 -0700
Re: The overpass Tom Roberts <tjroberts137@sbcglobal.net> - 2017-08-13 09:06 -0500
Re: The overpass Luigi Fortunati <fortunati.luigi@gmail.com> - 2017-08-13 19:07 +0200
Re: The overpass Thomas 'PointedEars' Lahn <PointedEars@web.de> - 2017-08-13 19:40 +0200
Re: The overpass Thomas 'PointedEars' Lahn <PointedEars@web.de> - 2017-08-13 21:32 +0200
Re: The overpass Thomas 'PointedEars' Lahn <PointedEars@web.de> - 2017-08-13 21:45 +0200
Re: The overpass Prudence Oppenheimer <phow@innfldo.sp> - 2017-08-13 21:32 +0000
Re: The overpass Thomas 'PointedEars' Lahn <PointedEars@web.de> - 2017-08-14 00:34 +0200
Re: The overpass Tom Roberts <tjroberts137@sbcglobal.net> - 2017-08-13 23:03 -0500
Re: The overpass Thomas 'PointedEars' Lahn <PointedEars@web.de> - 2017-08-14 15:52 +0200
Re: The overpass Tom Roberts <tjroberts137@sbcglobal.net> - 2017-08-14 15:21 -0500
Re: The overpass Tom Roberts <tjroberts137@sbcglobal.net> - 2017-08-14 16:43 -0500
Re: The overpass "Ross A. Finlayson" <ross.finlayson@gmail.com> - 2017-08-13 17:14 -0700
Re: The overpass Tom Roberts <tjroberts137@sbcglobal.net> - 2017-08-13 23:04 -0500
Re: The overpass "Ross A. Finlayson" <ross.finlayson@gmail.com> - 2017-08-14 19:55 -0700
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