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| From | Mr Flibble <flibble@reddwarf.jmc> |
|---|---|
| Newsgroups | comp.theory |
| Subject | Re: On recursion and infinite recursion (reprise #2) |
| Message-ID | <20220505005156.000010e1@reddwarf.jmc> (permalink) |
| References | <20220504174626.0000449b@reddwarf.jmc> <rbEcK.93$SOP1.79@fx46.iad> |
| Organization | Jupiter Mining Corp |
| Date | 2022-05-05 00:51 +0100 |
On Wed, 4 May 2022 19:42:19 -0400 Richard Damon <Richard@Damon-Family.org> wrote: > On 5/4/22 12:46 PM, Mr Flibble wrote: > > The halting problem theorem and proof thereof [Turing, 1937] (upon > > which other currently extant halting problem proofs are derived) is > > invalid due to an invalid "impossible program" [Strachey, 1965] that > > arises not from a function call-like infinite recursion but from a > > category error in the form of an invalid (erroneous) infinite > > recursion present in the proof [Wikipedia, 2022]. > > > > The categories involved in the category error are the decider and > > that which is being decided. Currently extant attempts to conflate > > the decider with that which is being decided are infinitely > > recursive and thus invalid. > > > > /Flibble > > > > And what is the error between the decider and the decided. > > The Decider is H. > > The thing to be decideer is H^ applied to <H^> > > Now, if you want to claim that H^ can't use H, then you are saying > either that Turing Macines aren't allowed to use other Turing > Machines, which is crasy, or that H just can't be asked about > machines which are based on it, at which point that is just admitting > that the Halting Problem is in fact impossible, as there exist some > VALID programs (which H^ is) that H just can't be asked to decide on. > > Note, H^ is NOT recursive in definition (unless H is). H^ is > basically jast a "call" to H with a little bit of simple logic around > it. > > The "recursion" (which isn't actually recursion) comes about because > we give H^ and input that just happens to be a representation of > itself, and H^ doesn't actually know that. > > If H actually meets the requirements of being a decider (and thus > also of being a Comptation), then we get no infinite "recursion", as > the H inside H^ will, by necessity, return an answer after finite > time, and H^ will either Halt or go into a simple infinite loop. > > H is thus just proved to give the wrong answer. > > If H refuses to give the wrong answer, then it turns out to not be a > decider and just loops forever with an ever growing tape as the level > of simulation just keeps increasing. > > Note, we NEVER get back to H^.q0 or any of the states of H^ up to > H^.qx, as the entire execution trace is within its copy of H doing > its simulation to try to decide. There is no actual Recursion. > > > Yes, in trying to decide how we might program H to try to get the > right answer, we can think about levels of recursion, but those are > not actually in the real trace of the execution of H^. Once we actual > make a decision on how we are going to attempt to make an H, and > establish a fixed algorithm to program into H, we find that we have > failed to make a correct decider, because, as the theorem says, it IS > impossible. This doesn't mean the problem is "invalid" just > impossible. > > Just like the problem of creating a program to always win at Tic Tac > Toe. The problem is well defined, just impossible due to the nature > of the game. Nope. The infinite recursion is a category error and therefore invalid: you and the rest of you shower appear to have a blindspot to this fact. /Flibble
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On recursion and infinite recursion (reprise #2) Mr Flibble <flibble@reddwarf.jmc> - 2022-05-04 17:46 +0100
Re: On recursion and infinite recursion (reprise #2) André G. Isaak <agisaak@gm.invalid> - 2022-05-04 10:53 -0600
Re: On recursion and infinite recursion (reprise #2) Mr Flibble <flibble@reddwarf.jmc> - 2022-05-04 17:56 +0100
Re: On recursion and infinite recursion (reprise #2) olcott <polcott2@gmail.com> - 2022-05-04 12:53 -0500
Re: On recursion and infinite recursion (reprise #2) Mr Flibble <flibble@reddwarf.jmc> - 2022-05-04 19:00 +0100
Re: On recursion and infinite recursion (reprise #2) olcott <polcott2@gmail.com> - 2022-05-04 12:52 -0500
Re: On recursion and infinite recursion (reprise #2) olcott <polcott2@gmail.com> - 2022-05-04 12:51 -0500
Re: On recursion and infinite recursion (reprise #2) Richard Damon <Richard@Damon-Family.org> - 2022-05-04 19:42 -0400
Re: On recursion and infinite recursion (reprise #2) Mr Flibble <flibble@reddwarf.jmc> - 2022-05-05 00:51 +0100
Re: On recursion and infinite recursion (reprise #2) Python <python@example.invalid> - 2022-05-05 01:58 +0200
Re: On recursion and infinite recursion (reprise #2) Richard Damon <Richard@Damon-Family.org> - 2022-05-04 20:02 -0400
Re: On recursion and infinite recursion (reprise #2) Mr Flibble <flibble@reddwarf.jmc> - 2022-05-05 01:05 +0100
Re: On recursion and infinite recursion (reprise #2) Richard Damon <Richard@Damon-Family.org> - 2022-05-04 20:21 -0400
Re: On recursion and infinite recursion (reprise #2) Mr Flibble <flibble@reddwarf.jmc> - 2022-05-05 01:24 +0100
Re: On recursion and infinite recursion (reprise #2) Richard Damon <Richard@Damon-Family.org> - 2022-05-04 20:41 -0400
Re: On recursion and infinite recursion (reprise #2) Mr Flibble <flibble@reddwarf.jmc> - 2022-05-05 17:47 +0100
Re: On recursion and infinite recursion (reprise #2) olcott <polcott2@gmail.com> - 2022-05-05 16:40 -0500
Re: On recursion and infinite recursion (reprise #2) Richard Damon <Richard@Damon-Family.org> - 2022-05-05 22:28 -0400
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