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1 Second Defined in a Formula

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  1 Second Defined in a Formula omnilobe@gmail.com - 2016-04-11 20:54 -0700
    Re: 1 Second Defined in a Formula benj <none@gmail.com> - 2016-04-12 02:39 -0400
    Re: 1 Second Defined in a Formula Sylvia Else <sylvia@not.at.this.address> - 2016-04-12 16:56 +1000
      Re: 1 Second Defined in a Formula omnilobe@gmail.com - 2016-04-12 09:03 -0700
        Re: 1 Second Defined in a Formula noTthaTguY <abu.kuanysh05@gmail.com> - 2016-04-12 17:41 -0700
          Re: 1 Second Defined in a Formula omnilobe@gmail.com - 2016-04-12 19:50 -0700
            Re: 1 Second Defined in a Formula noTthaTguY <abu.kuanysh05@gmail.com> - 2016-04-13 13:26 -0700
        Re: 1 Second Defined in a Formula Sylvia Else <sylvia@not.at.this.address> - 2016-04-14 17:17 +1000
          Re: 1 Second Defined in a Formula omnilobe@gmail.com - 2016-04-14 10:11 -0700

#569860 — 1 Second Defined in a Formula

1 second =  4 pi V k m / (5.131534 x 10^-9 h G q)

where 

V is proton volume 3.591364 x 10^-45 meter^3

k is Coulombs constant

m is proton mass

h is Planck's Constant

G is Newton's Constant

q is proton charge

5.13 ns is the universal constant for the conservation of continuum

Conclusion

This formula is accurate to within 1%. It is based on gravity's momentum of free space being related to the Planck's Constant angular momentum (Joule second). The second is produced by protons when gravity grows time and drains space like a liquid. The formula for the second is about the source of time: protons. This formula is not a guess, it is intended to show a correct understanding of time and the magnitude of the second compared to the magnitude of the proton volume. 

5.131534 nanoseconds magnitude = 3.591364 x 10^-45 cubic meters

1 Second Defined in a Formula from Gravity Volume Theory

1 second =  4 pi V k m / (5.131534 x 10^-9 h G q)

Alan Folmsbee, April 11, 2016

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#569870

On 04/11/2016 11:54 PM, omnilobe@gmail.com wrote:
> 1 second =  4 pi V k m / (5.131534 x 10^-9 h G q)
>
> where

> 5.13 ns is the universal constant for the conservation of continuum

> Alan Folmsbee, April 11, 2016

Please explain what this "universal constant for conservation of 
continuum" might be. What is "conservation of continuum"?

Sam and HVAC feel free to enlighten me on this fine point.



-- 

       ___           ___           ___            ___
      /\  \         /\  \         /\__\          /\  \
     /::\  \       /::\  \       /::|  |         \:\  \
    /:/\:\  \     /:/\:\  \     /:|:|  |     ___ /::\__\
   /::\~\:\__\   /::\~\:\  \   /:/|:|  |__  /\  /:/\/__/
  /:/\:\ \:|__| /:/\:\ \:\__\ /:/ |:| /\__\ \:\/:/  /
  \:\~\:\/:/  / \:\~\:\ \/__/ \/__|:|/:/  /  \::/  /
   \:\ \::/  /   \:\ \:\__\       |:/:/  /    \/__/
    \:\/:/  /     \:\ \/__/       |::/  /
     \::/__/       \:\__\         /:/  /
      ~~            \/__/         \/__/

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#569871

On 12/04/2016 1:54 PM, omnilobe@gmail.com wrote:
> 1 second =  4 pi V k m / (5.131534 x 10^-9 h G q)
>
> where
>
> V is proton volume 3.591364 x 10^-45 meter^3
>
> k is Coulombs constant
>
> m is proton mass
>
> h is Planck's Constant
>
> G is Newton's Constant
>

Leaving aside the arbitrary constant you introduced, G is not known very 
accurately, so it's a very rough definition.

Sylvia.

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#569916

On Monday, April 11, 
Sylvia wrote:

"Leaving aside the arbitrary constant you introduced, G is not known very 
accurately, so it's a very rough definition."

See a correction at the end.

Yes. G is rough and V, the proton volume is widely based on a radius from 0.84fm to 1.25fm. But the 5.1ns non-arbitrary universal constant is adjusted to match the V so the Momentum of Free Space (p) matches experiments. 

p = V / 5ns

Conclusion for Sylvia : Yes it is rough, now. It is a theory to explain reality. It is not a guessing game where an arbitrary constant is used. The 5.1ns has been verified on six planets and two stars. Conservation of Continuum sets space equal to time magnitudes as gravity shrinks space and grows time from protons and neutrons.

$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$

Correction

Correction, include Bohr Radius:

1 Second Defined in a Formula

1 second =  4 pi a V k m / (5.131534 x 10^-9 h G q)

where 

a is Bohr radius, 0.53 x 10^-10 meters

V is proton volume 3.591364 x 10^-45 meter^3

k is Coulombs constant

m is proton mass

h is Planck's Constant

G is Newton's Constant

q is proton charge

5.13 ns is the universal constant for the conservation of continuum

The formula was constructed as follows: 

Gravity has a "momentum of free space: V / 5.1ns = p

Planck's Constant is an angular momentum h = pR which is a linear momentum times a length, R.

R is 947 meters.

Since R is so long, scale it down by multiplying R by a dimensionless fraction to get a, the Bohr radius, a. The Hydrogen atom has that radius.

The fraction tried was m/q, theproton mass over charge ratio. After that number was tried, the formula still needed 10^20 to be divided. And the 4 pi was included as in the Bohr Magneton.

10^20 = k/G

Putting it all together has scaled the 947 meters to .53 angstroms.

h = p a (k/G) (m/q) (4 pi) (V/5ns)

Solve for seconds from the ns on right:

5ns = p a (k/G) (m/q) (4 pi) (V/h)

divide both sides by 10^-9

5 seconds =  4 pi a V k m / (10^-9 h G q)

1 second =  4 pi a V k m / (5.131534 x 10^-9 h G q)

Yeah, it is corrected and accurate within 1%.

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#570048

what is the idea;
teh second is a fraction of rrthdiem

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#570072

On Tuesday, April 12, 2016 at 2:41:08 PM UTC-10, noTthaTguY wrote:
> what is the idea;
> teh second is a fraction of rrthdiem

Time grows in a way that makes it inevitable that states will change:

1 second = 2.4 x 10^9 kaVm/GhQ

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#570251

twenty-four hundred-million what

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#570361

On 13/04/2016 2:03 AM, omnilobe@gmail.com wrote:
> On Monday, April 11, Sylvia wrote:
>
> "Leaving aside the arbitrary constant you introduced, G is not known
> very accurately, so it's a very rough definition."
>
> See a correction at the end.
>
> Yes. G is rough and V, the proton volume is widely based on a radius
> from 0.84fm to 1.25fm. But the 5.1ns non-arbitrary universal constant
> is adjusted to match the V so the Momentum of Free Space (p) matches
> experiments.
>
> p = V / 5ns
>
> Conclusion for Sylvia : Yes it is rough, now. It is a theory to
> explain reality. It is not a guessing game where an arbitrary
> constant is used. The 5.1ns has been verified on six planets and two
> stars. Conservation of Continuum sets space equal to time magnitudes
> as gravity shrinks space and grows time from protons and neutrons.

What do you mean by "verified"?

At the moment, it looks as if you've taken 1 second, divided/multiplied 
it by the other constants, as appropriate, and the 5.131534 x 10^-9 is 
what's left. This makes it arbitrary. You could similarly define a 
second in terms of my daily alcohol intake and the average number of 
birds in my garden, if you include the necessary fudge factor. The 
result is physically meaningless.

Sylvia.

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#570452

S asked:
"What do you mean by verified? 

At the moment, it looks as if you've taken 1 second, divided/multiplied it by the other constants, as appropriate, and the 5.131534 x 10^-9 is what's left. This makes it arbitrary. You could similarly define a second in terms of my daily alcohol intake and the average number of birds in my garden, if you include the necessary fudge factor. The result is physically meaningless. "

Answer by Al:

The Universal Constant for the Conservation of 4D Continuum, 5ns,  was verified by calculating the gravity theory formula for stars, planets, and the asteroid Vesta before the other work was started to define the second.

Fudging a number would come after the work on defining a second was begun. The 5ns value was calculated as follows in December 2014. I have photos and several witnesses to the announcement in 2014, long before I applied the 5ns constant to evaluations of Planck's Constant and proton energy 938MeV.

Calculated 5ns for Earth

The Gravity Volume Theory





The Law is proposed:

"The volume of all baryons on Earth V2 equals the volume of a fallen shell, V1. " Alan Folmsbee

The Reasoning

Gravity makes an apple fall 4.9 meters in 1 second. That is a volume effect because potentially, trillions of apples can all be dropped 4.9 meters all over the Earth in a shell of height z.

V1 = zA

z = height fallen during experiment of duration t=1 second

z = (1/2) g t^2

g is the acceleration due to gravity, 9.8 meters/sec^2

A = 4 pi R^2 = Area of Earth for potential experiments

R = radius of Earth

V1 = a volume of space allowing free fall experiment

$$$$$$$$$$$$$$$$$$$$$$$

V2 = NV

N is number of protons and neutrons in Earth

V is proton volume , using proton radius 0.95 x 10^-15 meters

V = (4/3) pi R^3

N = M/m

M = mass of Earth

m = mass of proton or neutron average

N = 3.5692 x 10^51 baryons in Earth

V = 3.591364 x 10^-45 meters^3

V2 = 1.27391 x 10^7 cubic meters of baryon stuff in planet

V2 = V1

Find the time tau for the shell to fall z meters so V2=V1 theory is tried. (Here is The Momentum of Free Space formula).

V2/tau = V1/t

find tau, 

tau = (V2 * t) / V1

In the 1 second experiment t = 1 second

tau = (1.27391 x 10^7 meter^3)*second / ( 4.9 meters * A)





A = 4 pi R^2

R = 6.378000 x 10^6 meters

R^2 = 40.679 x 10^12 square meters

A = 5.111859 x 10^14 square meters for Sea and Land near test

V1 = zA

V1 = 2.504811 x 10^15 cubic meters

V2 = 1.27391 x 10^7 cubic meters 

tau = (V2 * t) / V1

tau = (1.27391 x 10^7  * seconds) / 2.504811 x 10^15 

tau = 5.08585 x 10^-9 seconds

tau = 5.1 nanoseconds

Conclusion

Fudging a constant comes AFTER the goal is ready for a fudge factor, not a year before setting the goal for Planck's Constant and The Second definition formula.

The 5.1ns constant came first for The Gravity Volume Theory. It was not fabricated to fit into a collection of many constants of standard physics to get 1.0 seconds. No. The opposite is true:

The Gravity Volume Theory has produced a new universal constant that Old Science was not aware of. Tau is the missing piece to the puzzle called a grand unified theory. Volume, not mass (area), causes gravity.

Newton's Big G

G = V / ((2 pi m 5.1ns)*second) 

Nova star density for relativistic fusion

rho = 3 m c * 5.1ns / VR

time unit = (kaVm / Geh)*5x10-9

5.131534 nanoseconds appears in several parts of physics, but Old Science ignores Volume Theory and dilutes its concepts with math and mass myths.

Verification website:

http://fcontinuumgravity.blogspot.com/p/research-planning.html

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