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Re: Drs.Rafe Mazzeo, James R. Milgram of Stanford, are you as dumb as Jan Bielawski, never seeing that a Conic section is a OVAL, never an ellipse?? Proofs contained

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  Re: Drs.Rafe Mazzeo, James R. Milgram of Stanford, are you as dumb as Jan Bielawski, never seeing that a Conic section is a OVAL, never an ellipse?? Proofs contained Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2019-03-02 13:04 -0800
    Re: Archimedes "just not bolted down too tight in the first place" Plutonium flunked the physics lifetime-generation test moroney@world.std.spaamtrap.com (Michael Moroney) - 2019-03-02 22:18 +0000

#729975 — Re: Drs.Rafe Mazzeo, James R. Milgram of Stanford, are you as dumb as Jan Bielawski, never seeing that a Conic section is a OVAL, never an ellipse?? Proofs contained

Moroney wrote:
Feb 14
>Math Failure 

AP writes: 26 years of stalking by shitheads Moroney, kibo, shein, std. No wonder Stanford still teaches ellipse is a conic with their heads up their arse like kibo.

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#729984 — Re: Archimedes "just not bolted down too tight in the first place" Plutonium flunked the physics lifetime-generation test

AlzheimerPlutonium <plutonium.archimedes@gmail.com> fails at math and science:

>Subject: Re: Drs.Rafe Mazzeo, James R. Milgram of Stanford, are you as dumb as
> Jan Bielawski, never seeing that a Conic section is a OVAL, never an
> ellipse?? Proofs contained

Oh you want to see the ellipse proof again? Here you go!


Below you will find a simple *proof* that shows that certain conic 
sections are ellipses.

Some preliminaries:

Top view of the conic section and depiction of the coordinate system used 
in the proof:

              ^ x
              |
             -+- <= x=h
         .'   |   `.
        .     |     .
        |     |     |
        '     |     '      
         `.   |   .'
 y <----------+ <= x=0
             
Cone (side view):
                 .
                /|\
               / | \
              /b |  \
             /---+---' <= x = h
            /    |'   \
           /   ' |     \
          / '    |      \
x = 0 => '-------+-------\
        /    a   |        \

Proof:

r(x) = a - ((a-b)/h)x  and  d(x) = a - ((a+b)/h)x,  hence

y(x)^2 = r(x)^2 - d(x)^2 = ab - ab(2x/h - 1)^2 = ab(1 - 4(x - h/2)^2/h^2.

Hence (1/ab)y(x)^2 + (4/h^2)(x - h/2)^2 = 1  ...equation of an ellipse

qed




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