Groups | Search | Server Info | Keyboard shortcuts | Login | Register [http] [https] [nntp] [nntps]
Groups > sci.physics > #724428 > unrolled thread
| Started by | Jamie M <jmorken@shaw.ca> |
|---|---|
| First post | 2019-01-23 07:49 -0800 |
| Last post | 2019-01-23 11:43 -0800 |
| Articles | 3 — 3 participants |
Back to article view | Back to sci.physics
dark energy theory Jamie M <jmorken@shaw.ca> - 2019-01-23 07:49 -0800
Re: dark energy theory "Sir Gregory Hall, Esq." <greghall@yacht_maester.fake> - 2019-01-23 11:17 -0500
Re: dark energy theory mitchrae3323@gmail.com - 2019-01-23 11:43 -0800
| From | Jamie M <jmorken@shaw.ca> |
|---|---|
| Date | 2019-01-23 07:49 -0800 |
| Subject | dark energy theory |
| Message-ID | <q2a2ei$opf$1@gioia.aioe.org> |
Hi, Explaining dark energy as an emergent phenomenon of interaction between gravity and EM fields: things to consider: 1. the gravitational potential of the universe 2. the overall EM field of the universe (electrostatic/electromagnetic charge) 3. the interaction between 1 and 2. If EM waves are orthagonal to free space, and free space is curved due to gravity, then the EM waves are not orthagonal to each other over the curvature. If there is a net electrostatic or electromagnetic charge over that distance, there will be an attractive or repulsive force between the EM waves, which act on the free space itself. A way to test this, would be to take a very high powered coherent light source and aim it along the curvature of a gravitational body, and then when the laser is pulsed measure the gravitational force above the laser. Ie on earth, aim the laser from the atmosphere or space, towards the center of earth, and then on the same line at a higher altitude, measure the gravitational force of Earth. If the laser is powerful enough it should very slightly reduce the local curvature of the gravitational field, since the laser itself will curve to match the gravitational field, which will make the EM waves of the coherent light source non-orthogonal, resisting the curvature. I had previously tried to explain dark energy as solely an emergent property of gravity (ie a curvature will inherently try to expand to a flat surface) however that fell flat no pun intended. cheers, Jamie
[toc] | [next] | [standalone]
| From | "Sir Gregory Hall, Esq." <greghall@yacht_maester.fake> |
|---|---|
| Date | 2019-01-23 11:17 -0500 |
| Message-ID | <8m4h4e5ce790f4u2psrb72cadnhha8vfuh@4ax.com> |
| In reply to | #724428 |
On Wed, 23 Jan 2019 07:49:41 -0800, Jamie M <jmorken@shaw.ca> wrote: >Hi, > >Explaining dark energy as an emergent phenomenon of interaction between >gravity and EM fields: > >things to consider: > >1. the gravitational potential of the universe > >2. the overall EM field of the universe (electrostatic/electromagnetic >charge) > >3. the interaction between 1 and 2. > > >If EM waves are orthagonal to free space, and free space is curved due >to gravity, then the EM waves are not orthagonal to each other over >the curvature. If there is a net electrostatic or electromagnetic >charge over that distance, there will be an attractive or repulsive >force between the EM waves, which act on the free space itself. > >A way to test this, would be to take a very high powered coherent light >source and aim it along the curvature of a gravitational body, and then >when the laser is pulsed measure the gravitational force above the >laser. > >Ie on earth, aim the laser from the atmosphere or space, towards the >center of earth, and then on the same line at a higher altitude, measure >the gravitational force of Earth. > >If the laser is powerful enough it should very slightly reduce the local >curvature of the gravitational field, since the laser itself will curve >to match the gravitational field, which will make the EM waves of the >coherent light source non-orthogonal, resisting the curvature. > >I had previously tried to explain dark energy as solely an emergent >property of gravity (ie a curvature will inherently try to expand to a >flat surface) however that fell flat no pun intended. Not necessarily will a curvature inherently expand a flat surface. That thinking is myopic. Why? Because it assumes the flat surface is infinite. What if the flat surface is finite, that would mean boundaries or ends, edges. So such a flat surface, if then, curved could still have the same surface area by virtue of the ends, edges, boundaries withdrawing from their original positions. -- Everybody here likes Yours Truly, Gregøry Hall - Bombastic Loudmouth of the South
[toc] | [prev] | [next] | [standalone]
| From | mitchrae3323@gmail.com |
|---|---|
| Date | 2019-01-23 11:43 -0800 |
| Message-ID | <74d78ec7-c4e0-4422-ab44-abc985106fc6@googlegroups.com> |
| In reply to | #724428 |
On Wednesday, January 23, 2019 at 7:49:43 AM UTC-8, Jamie M wrote: > Hi, > > Explaining dark energy as an emergent phenomenon of interaction between > gravity and EM fields: > > things to consider: > > 1. the gravitational potential of the universe > > 2. the overall EM field of the universe (electrostatic/electromagnetic > charge) > > 3. the interaction between 1 and 2. > > > If EM waves are orthagonal to free space, and free space is curved due > to gravity, then the EM waves are not orthagonal to each other over > the curvature. If there is a net electrostatic or electromagnetic > charge over that distance, there will be an attractive or repulsive > force between the EM waves, which act on the free space itself. > > A way to test this, would be to take a very high powered coherent light > source and aim it along the curvature of a gravitational body, and then > when the laser is pulsed measure the gravitational force above the > laser. > > Ie on earth, aim the laser from the atmosphere or space, towards the > center of earth, and then on the same line at a higher altitude, measure > the gravitational force of Earth. > > If the laser is powerful enough it should very slightly reduce the local > curvature of the gravitational field, since the laser itself will curve > to match the gravitational field, which will make the EM waves of the > coherent light source non-orthogonal, resisting the curvature. > > I had previously tried to explain dark energy as solely an emergent > property of gravity (ie a curvature will inherently try to expand to a > flat surface) however that fell flat no pun intended. > > cheers, > Jamie What are the strengths of the magnetic and electric fields of force making up light? Do they have null strength? God creates gravitation. Eternally. Mitchell Raemsch
[toc] | [prev] | [standalone]
Back to top | Article view | sci.physics
csiph-web