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Mahipal <mahipal7638@gmail.com> writes: >On Thursday, October 6, 2016 at 10:37:39 PM UTC-4, Archimedes Plutonium wrote: >> So that in Maxwell's original 8 differential equations of EM theory >> one of them is the Lorentz force which embodies the Faraday law and >> instead of being just one term on the rightside of equation it >> involves three terms: >> F = qE + qv + qB >There's a typo in your Lorentz force equation. Are you baiting, AP? >F = qE + q(v X B) is the right vector representation for the Lorentz force. No, Archie seriously believe he can hack willy-nilly at Maxwell's Equations and other electromagnetism equations, and his "new" ones are correct. Because he said so. And despite the fact the old ones worked just fine for well over a century. A Feynman quote Archie needs to understand: "It doesn't matter how beautiful your theory is, it doesn't matter how smart you are. If it doesn't agree with experiment, it's wrong." Richard P. Feynman
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derivative of B as B1^2 - B2^2; Faraday Law = A*B + V*B1^2 - V*B2^2; Ampere Law = A*R + A*B1^2 - A*B2^2 Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-20 09:56 -0700
derivative of B as B1^2 - B2^2; Faraday Law = A*B + V*B1^2 - V*B2^2; Ampere Law = A*R + A*B1^2 - A*B2^2 Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-20 13:56 -0700
Maxwell history Re: derivative of B as B1^2 - B2^2; Faraday Law = A*B + V*B1^2 - V*B2^2; Ampere Law = A*R + A*B1^2 - A*B2^2 Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-20 21:18 -0700
Maxwell history Re: derivative of B as B1^2 - B2^2; Faraday Law = A*B + V*B1^2 - V*B2^2; Ampere Law = A*R + A*B1^2 - A*B2^2 Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-21 01:35 -0700
Maxwell history Re: derivative of B as B1^2 - B2^2; Faraday Law = A*B + V*B1^2 - V*B2^2; Ampere Law = A*R + A*B1^2 - A*B2^2 Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-21 02:03 -0700
measuring the spin term Re: derivative of B as B1^2 - B2^2; Faraday Law = A*B + V*B1^2 - V*B2^2; Ampere Law = A*R + A*B1^2 - A*B2^2 Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-21 13:56 -0700
spin term in EM laws Re: derivative of B as B1^2 - B2^2; Faraday Law = A*B + V*B1^2 - V*B2^2; Ampere Law = A*R + A*B1^2 - A*B2^2 Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-21 19:02 -0700
spin term experiments Re: spin term in EM laws Re: derivative of B as B1^2 - B2^2; Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-21 23:44 -0700
Revision-Page17, 3-2, EM theory becomes the axioms over all of physics/ Atom-Totality-Universe / textbook 7th ed Re: derivative of B as B1^2 - B2^2; Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-28 21:37 -0700
review and inspection of my new equations Re: derivative of B as B1^2 - B2^2; Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-10-03 17:13 -0700
A*R is displacement voltage not as Maxwell thought-- displacement current Re: review and inspection of my new equations Re: derivative of B as B1^2 - B2^2; Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-10-04 09:06 -0700
A*R is displacement voltage not as Maxwell thought-- displacement current Re: review and inspection of my new equations Re: derivative of B as B1^2 - B2^2; Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-10-04 13:11 -0700
Faraday and Ampere laws need the same number of terms on rightside of equation Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-10-04 21:03 -0700
straightening out the terms Re: Faraday and Ampere laws need the same number of terms on rightside of equation Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-10-05 11:54 -0700
Re: straightening out the terms Re: Faraday and Ampere laws need the same number of terms on rightside of equation Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-10-05 14:13 -0700
Re: straightening out the terms Re: Faraday and Ampere laws need the same number of terms on rightside of equation Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-10-05 16:24 -0700
Re: straightening out the terms Re: Faraday and Ampere laws need the same number of terms on rightside of equation Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-10-05 22:25 -0700
Maxwell had a better grip on EM with his 8 equations, not the present day 4 Re: Faraday and Ampere laws need the same number of terms on rightside of equation Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-10-06 12:37 -0700
Maxwell had a better grip on EM with his 8 equations, not the present day 4 Re: Faraday and Ampere laws need the same number of terms on rightside of equation Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-10-06 14:38 -0700
Maxwell's original 8 equations is better than its Heaviside makeover Re: Faraday and Ampere laws need the same number of terms on rightside of equation Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-10-06 19:37 -0700
Re: Maxwell's original 8 equations is better than its Heaviside makeover Re: Faraday and Ampere laws need the same number of terms on rightside of equation Mahipal <mahipal7638@gmail.com> - 2016-10-06 20:00 -0700
F = u(vxH) - dA/dt - electric potential Re: Faraday and Ampere laws need the same number of terms on rightside of equation Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-10-06 21:54 -0700
Re: F = u(vxH) - dA/dt - electric potential Re: Faraday and Ampere laws need the same number of terms on rightside of equation Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-10-07 10:26 -0700
Re: F = u(vxH) - dA/dt - electric potential Re: Faraday and Ampere laws need the same number of terms on rightside of equation "Efftard K. Donglemeier" <moderator@gmail.com> - 2016-10-07 12:09 -0700
F = u(vxH) - dA/dt - electric potential Re: Faraday and Ampere laws need the same number of terms on rightside of equation Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-10-07 12:17 -0700
Re: F = u(vxH) - dA/dt - electric potential Re: Faraday and Ampere laws need the same number of terms on rightside of equation Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-10-07 13:19 -0700
Re: Maxwell's original 8 equations is better than its Heaviside makeover Re: Faraday and Ampere laws need the same number of terms on rightside of equation moroney@world.std.spaamtrap.com (Michael Moroney) - 2016-10-07 13:40 +0000
Re: Maxwell's original 8 equations is better than its Heaviside makeover Re: Faraday and Ampere laws need the same number of terms on rightside of equation Mahipal <mahipal7638@gmail.com> - 2016-10-07 07:52 -0700
Re: Maxwell's original 8 equations is better than its Heaviside makeover Re: Faraday and Ampere laws need the same number of terms on rightside of equation Odd Bodkin <bodkinodd@gmail.com> - 2016-10-07 07:27 -0500
Maxwell history Re: derivative of B as B1^2 - B2^2; Faraday Law = A*B + V*B1^2 - V*B2^2; Ampere Law = A*R + A*B1^2 - A*B2^2 Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2016-09-21 02:16 -0700
Re: derivative of B as B1^2 - B2^2; Faraday Law = A*B + V*B1^2 - V*B2^2; Ampere Law = A*R + A*B1^2 - A*B2^2 Odd Bodkin <bodkinodd@gmail.com> - 2016-09-22 09:29 -0500
Re: derivative of B as B1^2 - B2^2; Faraday Law = A*B + V*B1^2 - V*B2^2; Ampere Law = A*R + A*B1^2 - A*B2^2 rbrteline@gmail.com - 2016-10-03 13:25 -0700
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