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Avogadro constant (1 atomic mass unit) / ((3.7037037e-28 kg) / ((5^0.5) / 10)) = 1.00253111

Started by"David (Kronos Prime) Fuller" <fuller.david@hotmail.com>
First post2017-07-07 22:07 -0700
Last post2017-07-08 00:05 -0700
Articles 3 — 2 participants

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  Avogadro constant  (1 atomic mass unit) / ((3.7037037e-28 kg) / ((5^0.5) / 10)) = 1.00253111 "David (Kronos Prime) Fuller" <fuller.david@hotmail.com> - 2017-07-07 22:07 -0700
    Re: Avogadro constant  (1 atomic mass unit) / ((3.7037037e-28 kg) / ((5^0.5) / 10)) = 1.00253111 "David (Kronos Prime) Fuller" <fuller.david@hotmail.com> - 2017-07-07 22:20 -0700
      Re: Avogadro constant  (1 atomic mass unit) / ((3.7037037e-28 kg) /  ((5^0.5) / 10)) = 1.00253111 The Starmaker <starmaker@ix.netcom.com> - 2017-07-08 00:05 -0700

#424231 — Avogadro constant (1 atomic mass unit) / ((3.7037037e-28 kg) / ((5^0.5) / 10)) = 1.00253111

From"David (Kronos Prime) Fuller" <fuller.david@hotmail.com>
Date2017-07-07 22:07 -0700
SubjectAvogadro constant (1 atomic mass unit) / ((3.7037037e-28 kg) / ((5^0.5) / 10)) = 1.00253111
Message-ID<c7e7d1f3-1941-4cd8-84a2-a24cb441431c@googlegroups.com>
Avogadro constant

(5^0.5) / 10 = 0.22360679775

((5^0.5) / 10) / 3.7037037e-28 = 6.0373835e+26


http://physics.nist.gov/cgi-bin/cuu/Value?na  = 6.022140857e+23

the number of atoms in one gram-molecule of atomic hydrogen, meaning one gram of hydrogen

(((5^0.5) / 10) / 3.7037037e-28) / 6.022140857e+26 = 1.0025311079


(1 atomic mass unit) / ((3.7037037e-28 kg) / ((5^0.5) / 10)) = 1.00253111


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#424234

From"David (Kronos Prime) Fuller" <fuller.david@hotmail.com>
Date2017-07-07 22:20 -0700
Message-ID<1791cd51-0795-48bc-8e40-4a96150de174@googlegroups.com>
In reply to#424231
On Saturday, July 8, 2017 at 12:07:33 AM UTC-5, David (Kronos Prime) Fuller wrote:
> Avogadro constant
> 
> (5^0.5) / 10 = 0.22360679775
> 
> ((5^0.5) / 10) / 3.7037037e-28 = 6.0373835e+26
> 
> 
> http://physics.nist.gov/cgi-bin/cuu/Value?na  = 6.022140857e+23
> 
> the number of atoms in one gram-molecule of atomic hydrogen, meaning one gram of hydrogen
> 
> (((5^0.5) / 10) / 3.7037037e-28) / 6.022140857e+26 = 1.0025311079
> 
> 
> (1 atomic mass unit) / ((3.7037037e-28 kg) / ((5^0.5) / 10)) = 1.00253111


The gas constant (also known as the molar, universal, or ideal gas constant, denoted by the symbol R ) 71.11111111111111^0.5 = 8.43274042712

http://physics.nist.gov/cgi-bin/cuu/Value?r

https://en.wikipedia.org/wiki/Gas_constant

((((5^0.5) / 10) / (3.7037037e-28 kg)) / 1000) * ((0.5 * 8.88888e-12 * (0.5^0.25))^2) = 8.43272357


(((((5^0.5) / 10) / (3.7037037037e-28 kg)) / 1000) * ((0.5 * 8.88888888888e-12 * (0.5^0.25))^2))^2 = 71.1111111 

(((((5^0.5) / 10) / (3.7037037037e-28 kg)) / 1000) * ((0.5 * 8.88888888888e-12 * (0.5^0.25))^2)) / 8.3144598 = 1.01422589

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#424245 — Re: Avogadro constant (1 atomic mass unit) / ((3.7037037e-28 kg) / ((5^0.5) / 10)) = 1.00253111

FromThe Starmaker <starmaker@ix.netcom.com>
Date2017-07-08 00:05 -0700
SubjectRe: Avogadro constant (1 atomic mass unit) / ((3.7037037e-28 kg) / ((5^0.5) / 10)) = 1.00253111
Message-ID<5960842A.35A3@ix.netcom.com>
In reply to#424234
David (Kronos Prime) Fuller wrote:
> 
> On Saturday, July 8, 2017 at 12:07:33 AM UTC-5, David (Kronos Prime) Fuller wrote:
> > Avogadro constant
> >
> > (5^0.5) / 10 = 0.22360679775
> >
> > ((5^0.5) / 10) / 3.7037037e-28 = 6.0373835e+26
> >
> >
> > http://physics.nist.gov/cgi-bin/cuu/Value?na  = 6.022140857e+23
> >
> > the number of atoms in one gram-molecule of atomic hydrogen, meaning one gram of hydrogen
> >
> > (((5^0.5) / 10) / 3.7037037e-28) / 6.022140857e+26 = 1.0025311079
> >
> >
> > (1 atomic mass unit) / ((3.7037037e-28 kg) / ((5^0.5) / 10)) = 1.00253111
> 
> The gas constant (also known as the molar, universal, or ideal gas constant, denoted by the symbol R ) 71.11111111111111^0.5 = 8.43274042712
> 
> http://physics.nist.gov/cgi-bin/cuu/Value?r
> 
> https://en.wikipedia.org/wiki/Gas_constant
> 
> ((((5^0.5) / 10) / (3.7037037e-28 kg)) / 1000) * ((0.5 * 8.88888e-12 * (0.5^0.25))^2) = 8.43272357
> 
> (((((5^0.5) / 10) / (3.7037037037e-28 kg)) / 1000) * ((0.5 * 8.88888888888e-12 * (0.5^0.25))^2))^2 = 71.1111111
> 
> (((((5^0.5) / 10) / (3.7037037037e-28 kg)) / 1000) * ((0.5 * 8.88888888888e-12 * (0.5^0.25))^2)) / 8.3144598 = 1.01422589



you speled Avacado wrong..

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