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Groups > sci.physics.relativity > #386542 > unrolled thread
| Started by | "David (Time Lord) Fuller" <fuller.david@hotmail.com> |
|---|---|
| First post | 2016-06-22 20:05 -0700 |
| Last post | 2016-06-24 20:42 -0700 |
| Articles | 4 — 2 participants |
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((5^0.5-1)/2)*((1837.420365 * ((3*10^8 - 299792458) / c))^2) = 1 "David (Time Lord) Fuller" <fuller.david@hotmail.com> - 2016-06-22 20:05 -0700
Re: ((5^0.5-1)/2)*((1837.420365 * ((3*10^8 - 299792458) / c))^2) = 1 The Starmaker <starmaker@ix.netcom.com> - 2016-06-23 00:06 -0700
Re: ((5^0.5-1)/2)*((1837.420365 * ((3*10^8 - 299792458) / c))^2) = 1 "David (Time Lord) Fuller" <fuller.david@hotmail.com> - 2016-06-23 06:21 -0700
Re: ((5^0.5-1)/2)*((1837.420365 * ((3*10^8 - 299792458) / c))^2) = 1 "David (Time Lord) Fuller" <fuller.david@hotmail.com> - 2016-06-24 20:42 -0700
| From | "David (Time Lord) Fuller" <fuller.david@hotmail.com> |
|---|---|
| Date | 2016-06-22 20:05 -0700 |
| Subject | ((5^0.5-1)/2)*((1837.420365 * ((3*10^8 - 299792458) / c))^2) = 1 |
| Message-ID | <01f15a5d-fee1-4084-9228-10b3389c6208@googlegroups.com> |
((5^0.5-1)/2)*((1837.420365 * ((3*10^8 - 299792458) / c))^2) = 1 1836.15267389 / 1837.420365 = 0.99931007017 3 * (1836.15267389 / 1837.420365) = 2.99793021053 c / ((3 * (10^8)) * (1 836.15267389 / 1 837.420365)) = 0.999998122
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| From | The Starmaker <starmaker@ix.netcom.com> |
|---|---|
| Date | 2016-06-23 00:06 -0700 |
| Message-ID | <576B8A72.2C3D@ix.netcom.com> |
| In reply to | #386542 |
David (Time Lord) Fuller wrote: > > ((5^0.5-1)/2)*((1837.420365 * ((3*10^8 - 299792458) / c))^2) = 1 wrong answer: https://www.google.com/#q=((5%5E0.5-1)%2F2)*((1837.420365+*+((3*10%5E8+-+299792458)+%2F+c))%5E2)+%3D = 1 s2 / m2 you need new batteries for your calculator.
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| From | "David (Time Lord) Fuller" <fuller.david@hotmail.com> |
|---|---|
| Date | 2016-06-23 06:21 -0700 |
| Message-ID | <34090262-6055-4915-852d-d0b807db20bc@googlegroups.com> |
| In reply to | #386554 |
(c / 300000000) / (1836.15267389 / 1837.420365) = 0.999998122 m / s (1837.420365 * (((3 * (10^8)) - 299792458) / c))^2 = 1.61803399 No, it looks right.
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| From | "David (Time Lord) Fuller" <fuller.david@hotmail.com> |
|---|---|
| Date | 2016-06-24 20:42 -0700 |
| Message-ID | <f586ab42-3259-4946-bf04-b266150adbbd@googlegroups.com> |
| In reply to | #386563 |
(1 / (((68 665.5865 (meters per second)) / (1 Mpc)) * (c^2))) / 5 = 1 If an expanding earth is factual at all, it is tied to the Hubble expansion (1 / (((68 665.5865 (meters per second)) / (1 Mpc)) * (c^2))) / 5 = 1 (pi / 4) / ((((5^0.5) - 1) / 2) * (1835.65992 * (((3 * (10^8)) - 299792458) / c))) = 1 m / s (pi / 4) / ((((5^0.5) - 1) / 2) * ((1836.15267389 - 0.5) * (((3 * (10^8)) - 299792458) / c))) = 1.00000395 m / s (c / 300000000) / (1836.15267389 / 1837.420365) = 0.999998122 m / s (1837.420365 * (((3 * (10^8)) - 299792458) / c))^2 = 1.61803399 ((5^0.5-1)/2)*((1837.420365 * ((3*10^8 - 299792458) / c))^2) = 1 1836.15267389 / 1837.420365 = 0.99931007017 3 * (1836.15267389 / 1837.420365) = 2.99793021053 c / ((3 * (10^8)) * (1836.15267389 / 1837.420365)) = 0.999998122 ((3 * (10^8)) / c) * (1 - (1 / ((1836.15267389 / 4) * pi))) = 0.999998378 s / m (1836.15267389 / 4) * pi = 1442.11093779 1 / (1 - (299792458 / 300000000)) = 1445.4905513
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