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Groups > sci.physics.relativity > #388224
| From | Thomas 'PointedEars' Lahn <PointedEars@web.de> |
|---|---|
| Newsgroups | sci.physics.relativity |
| Subject | Re: Gravity and light question |
| Date | 2016-07-23 15:38 +0200 |
| Organization | PointedEars Software (PES) |
| Message-ID | <4194432.GXAFRqVoOG@PointedEars.de> (permalink) |
| References | (9 earlier) <nmif5n$1711$2@gioia.aioe.org> <2358326.mvXUDI8C0e@PointedEars.de> <nmjh16$11f7$1@gioia.aioe.org> <4231954.31r3eYUQgx@PointedEars.de> <XeednXdReMoB2g_KnZ2dnUU7_8zNnZ2d@giganews.com> |
Tom Roberts wrote: > On 7/18/16 7/18/16 - 11:31 PM, Thomas 'PointedEars' Lahn wrote: >> The Einstein field equations are: >> R_µν − 1∕2 R g_µν + Λ g_µν = 8 π G∕c⁴ T_µν >> The shape of spacetime on the left-hand side is determined by the stress– >> energy tensor T_µν on the right-hand side *and vice-versa* (its >> componenent T₀₀ is the energy density which by the mass–energy >> equivalence is equivalent >> to the mass density in the trivial case). [This is succintly summarized >> in John Archibald Wheeler’s “Spacetime tells matter how to move; matter >> tells >> spacetime how to curve.” So there *is* a difference between light and >> massive objects: light, being massless, does _not_ affect spacetime >> considerably.] > > Your last claim is wrong. Just LOOK at the equation you wrote above -- the > curvature (LHS) is related to the energy-momentum tensor T. Light clearly > has nonzero T, and thus affects the curvature. Straw man. I said “does _not_ affect spacetime *considerably*” (i.e., compared to massive objects). I did not say “does _not_ affect spacetime *at all*”. > Beware of sound bites -- they invariably omit some details. I beg your pardon? > It's just that in practice it's very difficult to have a large amount of > energy-momentum in light; it's much easier for massive objects, as mass > has an enormous amount of energy and dmomentum (compared to other types). AISB. >> The curvature of spacetime, then, is found in R_µν, the Ricci curvature >> tensor, and R, the scalar curvature. Obviously, R_µν − 1∕2 R g_µν ≠ G ∕ >> c². > > Hmmm. It is quite common to define the Einstein curvature tensor G with > components: > > G_µν = R_µν − 1∕2 R g_µν I know. Irrelevant. Had I meant the Einstein tensor, I would have written indices (to indicate covariance and/or contravariance). > (There's no 1/c².) Of course not. That the curvature of spacetime were defined by “G / c^2” was “Odd Bodkin”’s claim, which was thus disproved. I value your professional insight, but you should read postings more carefully, so as not to leave the impression that you are posting follow-ups only for the sake of posting. -- PointedEars Twitter: @PointedEars2 Please do not cc me. / Bitte keine Kopien per E-Mail.
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Re: Gravity and light question Odd Bodkin <bodkinodd@gmail.com> - 2016-07-18 16:17 -0500
Re: Gravity and light question Thomas 'PointedEars' Lahn <PointedEars@web.de> - 2016-07-19 06:31 +0200
Re: Gravity and light question Odd Bodkin <bodkinodd@gmail.com> - 2016-07-22 07:13 -0500
Re: Gravity and light question Thomas 'PointedEars' Lahn <PointedEars@web.de> - 2016-07-23 15:52 +0200
Re: Gravity and light question Tom Roberts <tjroberts137@sbcglobal.net> - 2016-07-22 11:19 -0500
Re: Gravity and light question Ben Wagner <benwa@ubuntusite.org> - 2016-07-22 18:40 +0000
Re: Gravity and light question Tom Roberts <tjroberts137@sbcglobal.net> - 2016-07-22 22:43 -0500
Re: Gravity and light question Poutnik <poutnik4nntp@gmail.com> - 2016-07-23 07:23 +0200
Re: Gravity and light question Poutnik <poutnik4nntp@gmail.com> - 2016-07-23 08:15 +0200
Re: Gravity and light question Thomas 'PointedEars' Lahn <PointedEars@web.de> - 2016-07-23 15:38 +0200
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