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Groups > sci.math > #424509 > unrolled thread
| Started by | 7777777 <jussir@yahoo.com> |
|---|---|
| First post | 2018-09-29 03:54 -0700 |
| Last post | 2018-10-08 01:17 -0700 |
| Articles | 10 on this page of 30 — 7 participants |
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what is x^dx equal to? 7777777 <jussir@yahoo.com> - 2018-09-29 03:54 -0700
Re: what is x^dx equal to? Roland Franzius <roland.franzius@uos.de> - 2018-09-29 13:43 +0200
Re: what is x^dx equal to? 7777777 <jussir@yahoo.com> - 2018-09-29 09:33 -0700
Re: what is x^dx equal to? Zelos Malum <zelos.malum@gmail.com> - 2018-09-30 22:55 -0700
Re: what is x^dx equal to? 7777777 <jussir@yahoo.com> - 2018-09-30 23:08 -0700
Re: what is x^dx equal to? Zelos Malum <zelos.malum@gmail.com> - 2018-09-30 23:23 -0700
Re: what is x^dx equal to? 7777777 <jussir@yahoo.com> - 2018-10-01 11:05 -0700
Re: what is x^dx equal to? Zelos Malum <zelos.malum@gmail.com> - 2018-10-01 22:34 -0700
Re: what is x^dx equal to? 7777777 <jussir@yahoo.com> - 2018-10-01 23:20 -0700
Re: what is x^dx equal to? Zelos Malum <zelos.malum@gmail.com> - 2018-10-02 00:36 -0700
Re: what is x^dx equal to? 7777777 <jussir@yahoo.com> - 2018-10-02 13:48 -0700
Re: what is x^dx equal to? Sergio <invalid@invalid.com> - 2018-10-02 19:34 -0500
Re: what is x^dx equal to? Zelos Malum <zelos.malum@gmail.com> - 2018-10-04 00:02 -0700
Re: what is x^dx equal to? 7777777 <jussir@yahoo.com> - 2018-10-04 11:03 -0700
Re: what is x^dx equal to? Sergio <invalid@invalid.com> - 2018-10-04 13:36 -0500
Re: what is x^dx equal to? 7777777 <jussir@yahoo.com> - 2018-10-04 11:52 -0700
Re: what is x^dx equal to? Sergio <invalid@invalid.com> - 2018-10-04 20:59 -0500
Re: what is x^dx equal to? Zelos Malum <zelos.malum@gmail.com> - 2018-10-04 22:26 -0700
Re: what is x^dx equal to? Zelos Malum <zelos.malum@gmail.com> - 2018-10-05 00:24 -0700
Re: what is x^dx equal to? Zelos Malum <zelos.malum@gmail.com> - 2018-10-05 00:24 -0700
Re: what is x^dx equal to? Zelos Malum <zelos.malum@gmail.com> - 2018-10-05 00:24 -0700
Re: what is x^dx equal to? Zelos Malum <zelos.malum@gmail.com> - 2018-10-05 00:24 -0700
Re: what is x^dx equal to? Zelos Malum <zelos.malum@gmail.com> - 2018-10-05 00:24 -0700
Re: what is x^dx equal to? Zelos Malum <zelos.malum@gmail.com> - 2018-10-05 00:25 -0700
Re: what is x^dx equal to? Python <python@python.invalid> - 2018-10-04 21:39 +0200
Re: what is x^dx equal to? Mathedman <Mathedman@hotmail.com> - 2018-10-02 09:10 -0500
Re: what is x^dx equal to? Jan <filmart@gmail.com> - 2018-10-02 09:25 -0700
Re: what is x^dx equal to? Sergio <invalid@invalid.com> - 2018-10-02 19:35 -0500
Re: what is x^dx equal to? Mathedman <Mathedman@hotmail.com> - 2018-10-07 08:47 -0500
Re: what is x^dx equal to? Zelos Malum <zelos.malum@gmail.com> - 2018-10-08 01:17 -0700
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| From | Zelos Malum <zelos.malum@gmail.com> |
|---|---|
| Date | 2018-10-05 00:24 -0700 |
| Message-ID | <9a0ece60-985c-4dd7-9f57-308929640ad1@googlegroups.com> |
| In reply to | #424978 |
Den måndag 1 oktober 2018 kl. 08:08:13 UTC+2 skrev 7777777: > maanantai 1. lokakuuta 2018 8.55.53 UTC+3 Zelos Malum kirjoitti: > > Den lördag 29 september 2018 kl. 12:55:02 UTC+2 skrev 7777777: > > > What is x^dx equal to ? > > > > define what you mean with dx here. > > > dx is the same as in f'(x) = dy/dx
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| From | Zelos Malum <zelos.malum@gmail.com> |
|---|---|
| Date | 2018-10-05 00:24 -0700 |
| Message-ID | <e414fed2-1c10-4111-89a7-3fd790182e80@googlegroups.com> |
| In reply to | #424978 |
Den måndag 1 oktober 2018 kl. 20:06:00 UTC+2 skrev 7777777: > maanantai 1. lokakuuta 2018 9.24.05 UTC+3 Zelos Malum kirjoitti: > > Den måndag 1 oktober 2018 kl. 08:08:13 UTC+2 skrev 7777777: > > > maanantai 1. lokakuuta 2018 8.55.53 UTC+3 Zelos Malum kirjoitti: > > > > Den lördag 29 september 2018 kl. 12:55:02 UTC+2 skrev 7777777: > > > > > What is x^dx equal to ? > > > > > > > > define what you mean with dx here. > > > > > > > > > dx is the same as in f'(x) = dy/dx > > > > considering that is just notational convinience there, it still needs a proper definition to what it is. > > > > neither dy nor dx in dy/dx refers to any number, x^dx is meaningless. > > no, it is not meaningless. > > The correct answer was already provided here: > https://groups.google.com/d/msg/sci.math/mEIGH8xomvc/yAmuBlz1AQAJ
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| From | Zelos Malum <zelos.malum@gmail.com> |
|---|---|
| Date | 2018-10-05 00:24 -0700 |
| Message-ID | <b66191b7-1615-498f-b26b-67a6f0955b64@googlegroups.com> |
| In reply to | #424978 |
Den tisdag 2 oktober 2018 kl. 08:20:42 UTC+2 skrev 7777777: > tiistai 2. lokakuuta 2018 8.34.41 UTC+3 Zelos Malum kirjoitti: > > >no, it is not meaningless. > > > > You can give it meanign but if you say it is from dy/dx=f'(x), then it is meaningless cause dy nor dx does not refer to a function, value or anything on their own, but together they do. > > > > He assumed you meant a value of some sort (at which it is correct) but you are not refering to a value with your previous statement. Therefore it is wrong. > > > > you can defien dx^2=0, we got nilpotent structures and such, but it is not like dy/dx=f'(x) then. > > It is not wrong. > > What function does dx refer in e^dx = 1 + dx ? > > It comes from x^dx = 1 + ln x dx when x = e
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| From | Zelos Malum <zelos.malum@gmail.com> |
|---|---|
| Date | 2018-10-05 00:25 -0700 |
| Message-ID | <cd6ad899-fe09-43d1-8361-9b59e40d01d3@googlegroups.com> |
| In reply to | #424978 |
Den tisdag 2 oktober 2018 kl. 22:48:16 UTC+2 skrev 7777777: > tiistai 2. lokakuuta 2018 10.36.47 UTC+3 Zelos Malum kirjoitti: > > Den tisdag 2 oktober 2018 kl. 08:20:42 UTC+2 skrev 7777777: > > > tiistai 2. lokakuuta 2018 8.34.41 UTC+3 Zelos Malum kirjoitti: > > > > >no, it is not meaningless. > > > > > > > > You can give it meanign but if you say it is from dy/dx=f'(x), then it is meaningless cause dy nor dx does not refer to a function, value or anything on their own, but together they do. > > > > > > > > He assumed you meant a value of some sort (at which it is correct) but you are not refering to a value with your previous statement. Therefore it is wrong. > > > > > > > > you can defien dx^2=0, we got nilpotent structures and such, but it is not like dy/dx=f'(x) then. > > > > > > It is not wrong. > > > > > > What function does dx refer in e^dx = 1 + dx ? > > > > > > It comes from x^dx = 1 + ln x dx when x = e > > > > The it is not the same as in dy/dx=f' > > > > it is somethign else that you haven't specified, some real number presumibly > > y = f(x) = e^x > > f'(x) = dy/dx = (f(x+dx) - f(x))/dx =( e^(x+dx) - e^x )/dx = > (e^x * e^dx - e^x)/dx = e^x(e^dx - 1)/dx = e^x((1+dx) - 1)/dx = e^x > > so e^dx = 1 + dx > and > dx is the same as in f'(x) = dy/dx
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| From | Python <python@python.invalid> |
|---|---|
| Date | 2018-10-04 21:39 +0200 |
| Message-ID | <5bb66c5a$0$3745$426a74cc@news.free.fr> |
| In reply to | #424933 |
Finished Finish 7777777 wrote: > torstai 4. lokakuuta 2018 10.03.05 UTC+3 Zelos Malum kirjoitti: >>>> f'(x) = dy/dx = (f(x+dx) - f(x))/dx >> >> FALSE! >> >> It is >> >> f'(x) = dy/dx = lim(h->0) (f(x+h) - f(x))/h >> >> The limit must be there >> >> and as others now have pointed out, your string of symbosl are meaningless cause you've not defined it properly and don't know basic calculus. > > you stupid jerk there is no limit in f'(x) = dy/dx You are a idiot, an ignorant and a jerk Herr Seven Seven.
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| From | Mathedman <Mathedman@hotmail.com> |
|---|---|
| Date | 2018-10-02 09:10 -0500 |
| Message-ID | <7834b80f-c8b7-e44e-f71a-87c6f6a1b8e2@hotmail.com> |
| In reply to | #424509 |
On 9/29/2018 5:54 AM, 7777777 wrote: > What is x^dx equal to ? > absolutely nothing - it's a senseless grouping of 3 letters and one computer math symbol.
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| From | Jan <filmart@gmail.com> |
|---|---|
| Date | 2018-10-02 09:25 -0700 |
| Message-ID | <de0336b0-b967-42b0-9183-1e15c3a7d273@googlegroups.com> |
| In reply to | #424509 |
On Saturday, September 29, 2018 at 3:55:02 AM UTC-7, 7777777 wrote: > What is x^dx equal to ? Undefined. "dx" is (by definition) an element of a covector basis, and in a vector space by definition vectors can be only added and multiplied by a scalar. You are free to define symbols like "x^dx" but they should be consistent with the already established usage to avoid confusion. OTOH if you intend this to be an entirely different thing, use a different notation. Either way, you have to provide a definition as currently this symbol is meaningless. -- Jan
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| From | Sergio <invalid@invalid.com> |
|---|---|
| Date | 2018-10-02 19:35 -0500 |
| Message-ID | <pp12sm$mtg$2@gioia.aioe.org> |
| In reply to | #424509 |
On 9/29/2018 5:54 AM, 7777777 wrote: > What is x^dx equal to ? > x^dx = (x^d)*x that is all.
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| From | Mathedman <Mathedman@hotmail.com> |
|---|---|
| Date | 2018-10-07 08:47 -0500 |
| Message-ID | <d4d61f5d-b453-c19e-795e-2b64a761ec2d@hotmail.com> |
| In reply to | #424509 |
On 9/29/2018 5:54 AM, 7777777 wrote:
> What is x^dx equal to ?
>
4 typographical symbols !
Mathematically, it is nonsense.
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| From | Zelos Malum <zelos.malum@gmail.com> |
|---|---|
| Date | 2018-10-08 01:17 -0700 |
| Message-ID | <87116296-4a5d-4f88-83e3-8b376196ca42@googlegroups.com> |
| In reply to | #425112 |
Den söndag 7 oktober 2018 kl. 15:47:30 UTC+2 skrev Mathedman: > On 9/29/2018 5:54 AM, 7777777 wrote: > > What is x^dx equal to ? > > > 4 typographical symbols ! > > Mathematically, it is nonsense. It is, I told him but he is mathematically illiterate.
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