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Re: Thomas Hales flunked the Math Test of a lifetime-generation test

Started byArchimedes Plutonium <plutonium.archimedes@gmail.com>
First post2018-08-26 14:34 -0700
Last post2018-08-26 21:44 +0000
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  Re: Thomas Hales flunked the Math Test of a lifetime-generation test Archimedes Plutonium <plutonium.archimedes@gmail.com> - 2018-08-26 14:34 -0700
    Re: Archimedes "Total Failure" Plutonium flunked the Math Test of a lifetime-generation test moroney@world.std.spaamtrap.com (Michael Moroney) - 2018-08-26 21:44 +0000

#422223 — Re: Thomas Hales flunked the Math Test of a lifetime-generation test

FromArchimedes Plutonium <plutonium.archimedes@gmail.com>
Date2018-08-26 14:34 -0700
SubjectRe: Thomas Hales flunked the Math Test of a lifetime-generation test
Message-ID<28b9d73f-7fbc-455a-9489-47b85df937e4@googlegroups.com>
On Sunday, August 26
Dan Christensen 	wrote:
3:42 PM (46 minutes ago)

>WARNING TO STUDENTS: 

AP writes:: yes, Dan, Thomas Hales cannot tell the difference between a ellipse and a oval, but can he tell the difference between a rhombus and a dodecahedron?

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#422226 — Re: Archimedes "Total Failure" Plutonium flunked the Math Test of a lifetime-generation test

Frommoroney@world.std.spaamtrap.com (Michael Moroney)
Date2018-08-26 21:44 +0000
SubjectRe: Archimedes "Total Failure" Plutonium flunked the Math Test of a lifetime-generation test
Message-ID<plv6vs$mnn$3@pcls7.std.com>
In reply to#422223
Math Failure Archimedes Plutonium <plutonium.archimedes@gmail.com> fails:

Still struggling with the ellipse proof?

Here you go!

Below you will find a simple *proof* that shows that certain conic 
sections are ellipses.

Some preliminaries:

Top view of the conic section and depiction of the coordinate system used 
in the proof:

              ^ x
              |
             -+- <= x=h
         .'   |   `.
        .     |     .
        |     |     |
        '     |     '      
         `.   |   .'
 y <----------+ <= x=0
             
Cone (side view):
                 .
                /|\
               / | \
              /b |  \
             /---+---' <= x = h
            /    |'   \
           /   ' |     \
          / '    |      \
x = 0 => '-------+-------\
        /    a   |        \

Proof:

r(x) = a - ((a-b)/h)x  and  d(x) = a - ((a+b)/h)x,  hence

y(x)^2 = r(x)^2 - d(x)^2 = ab - ab(2x/h - 1)^2 = ab(1 - 4(x - h/2)^2/h^2.

Hence (1/ab)y(x)^2 + (4/h^2)(x - h/2)^2 = 1  ...equation of an ellipse

qed

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