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Re: fs, net: deadlock between bind/splice on af_unix

Started byebiederm@xmission.com (Eric W. Biederman)
First post2017-01-17 09:20 +0100
Last post2017-01-17 09:20 +0100
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  Re: fs, net: deadlock between bind/splice on af_unix ebiederm@xmission.com (Eric W. Biederman) - 2017-01-17 09:20 +0100

#1560333 — Re: fs, net: deadlock between bind/splice on af_unix

Fromebiederm@xmission.com (Eric W. Biederman)
Date2017-01-17 09:20 +0100
SubjectRe: fs, net: deadlock between bind/splice on af_unix
Message-ID<t0x9M-4At-17@gated-at.bofh.it>
Al Viro <viro@ZenIV.linux.org.uk> writes:

> On Thu, Dec 08, 2016 at 10:32:00PM -0800, Cong Wang wrote:
>
>> > Why do we do autobind there, anyway, and why is it conditional on
>> > SOCK_PASSCRED?  Note that e.g. for SOCK_STREAM we can bloody well get
>> > to sending stuff without autobind ever done - just use socketpair()
>> > to create that sucker and we won't be going through the connect()
>> > at all.
>> 
>> In the case Dmitry reported, unix_dgram_sendmsg() calls unix_autobind(),
>> not SOCK_STREAM.
>
> Yes, I've noticed.  What I'm asking is what in there needs autobind triggered
> on sendmsg and why doesn't the same need affect the SOCK_STREAM case?

With respect to the conditionality on SOCK_PASSCRED those are the linux
semantics.  Semantically that is the way the code has behaved since
2.1.15 when support for passing credentials was added to the code.
So I presume someone thought it was a good idea to have a name for
a socket that is sending credentials to another socket.  It certainly
seems reasonable at first glance.

With socketpair the only path that doesn't enforce this with
SOCK_STREAM and SOCK_PASSCRED that is either an oversight or a don't
care because we already know who is at the other end.

I can imagine two possible fixes:
1) Declare that splice is non-sense in the presence of SOCK_PASSCRED.
2) Someone adds a preparation operation that can be called on
   af_unix sockets that will ensure the autobind happens before
   any problematic locks are taken.

Eric

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