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Groups > linux.kernel > #1540292 > unrolled thread

Re: Perf hotplug lockup in v4.9-rc8

Started byWill Deacon <will.deacon@arm.com>
First post2016-12-12 12:50 +0100
Last post2016-12-22 17:40 +0100
Articles 5 — 3 participants

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Contents

  Re: Perf hotplug lockup in v4.9-rc8 Will Deacon <will.deacon@arm.com> - 2016-12-12 12:50 +0100
    Re: Perf hotplug lockup in v4.9-rc8 Peter Zijlstra <peterz@infradead.org> - 2016-12-12 13:50 +0100
      Re: Perf hotplug lockup in v4.9-rc8 Peter Zijlstra <peterz@infradead.org> - 2016-12-22 09:50 +0100
        Re: Perf hotplug lockup in v4.9-rc8 Peter Zijlstra <peterz@infradead.org> - 2016-12-22 15:10 +0100
          Re: Perf hotplug lockup in v4.9-rc8 "Paul E. McKenney" <paulmck@linux.vnet.ibm.com> - 2016-12-22 17:40 +0100

#1540292 — Re: Perf hotplug lockup in v4.9-rc8

FromWill Deacon <will.deacon@arm.com>
Date2016-12-12 12:50 +0100
SubjectRe: Perf hotplug lockup in v4.9-rc8
Message-ID<sNxhg-3NJ-5@gated-at.bofh.it>
On Fri, Dec 09, 2016 at 02:59:00PM +0100, Peter Zijlstra wrote:
> On Wed, Dec 07, 2016 at 07:34:55PM +0100, Peter Zijlstra wrote:
> 
> > @@ -2352,6 +2357,28 @@ perf_install_in_context(struct perf_event_context *ctx,
> >  		return;
> >  	}
> >  	raw_spin_unlock_irq(&ctx->lock);
> > +
> > +	raw_spin_lock_irq(&task->pi_lock);
> > +	if (!(task->state == TASK_RUNNING || task->state == TASK_WAKING)) {
> > +		/*
> > +		 * XXX horrific hack...
> > +		 */
> > +		raw_spin_lock(&ctx->lock);
> > +		if (task != ctx->task) {
> > +			raw_spin_unlock(&ctx->lock);
> > +			raw_spin_unlock_irq(&task->pi_lock);
> > +			goto again;
> > +		}
> > +
> > +		add_event_to_ctx(event, ctx);
> > +		raw_spin_unlock(&ctx->lock);
> > +		raw_spin_unlock_irq(&task->pi_lock);
> > +		return;
> > +	}
> > +	raw_spin_unlock_irq(&task->pi_lock);
> > +
> > +	cond_resched();
> > +
> >  	/*
> >  	 * Since !ctx->is_active doesn't mean anything, we must IPI
> >  	 * unconditionally.
> 
> So while I went back and forth trying to make that less ugly, I figured
> there was another problem.
> 
> Imagine the cpu_function_call() hitting the 'right' cpu, but not finding
> the task current. It will then continue to install the event in the
> context. However, that doesn't stop another CPU from pulling the task in
> question from our rq and scheduling it elsewhere.
> 
> This all lead me to the below patch.. Now it has a rather large comment,
> and while it represents my current thinking on the matter, I'm not at
> all sure its entirely correct. I got my brain in a fair twist while
> writing it.
> 
> Please as to carefully think about it.
> 
> ---
>  kernel/events/core.c | 70 +++++++++++++++++++++++++++++++++++-----------------
>  1 file changed, 48 insertions(+), 22 deletions(-)
> 
> diff --git a/kernel/events/core.c b/kernel/events/core.c
> index 6ee1febdf6ff..7d9ae461c535 100644
> --- a/kernel/events/core.c
> +++ b/kernel/events/core.c
> @@ -2252,7 +2252,7 @@ static int  __perf_install_in_context(void *info)
>  	struct perf_event_context *ctx = event->ctx;
>  	struct perf_cpu_context *cpuctx = __get_cpu_context(ctx);
>  	struct perf_event_context *task_ctx = cpuctx->task_ctx;
> -	bool activate = true;
> +	bool reprogram = true;
>  	int ret = 0;
>  
>  	raw_spin_lock(&cpuctx->ctx.lock);
> @@ -2260,27 +2260,26 @@ static int  __perf_install_in_context(void *info)
>  		raw_spin_lock(&ctx->lock);
>  		task_ctx = ctx;
>  
> -		/* If we're on the wrong CPU, try again */
> -		if (task_cpu(ctx->task) != smp_processor_id()) {
> -			ret = -ESRCH;
> -			goto unlock;
> -		}
> +		reprogram = (ctx->task == current);
>  
>  		/*
> -		 * If we're on the right CPU, see if the task we target is
> -		 * current, if not we don't have to activate the ctx, a future
> -		 * context switch will do that for us.
> +		 * If the task is running, it must be running on this CPU,
> +		 * otherwise we cannot reprogram things.
> +		 *
> +		 * If its not running, we don't care, ctx->lock will
> +		 * serialize against it becoming runnable.
>  		 */
> -		if (ctx->task != current)
> -			activate = false;
> -		else
> -			WARN_ON_ONCE(cpuctx->task_ctx && cpuctx->task_ctx != ctx);
> +		if (task_curr(ctx->task) && !reprogram) {
> +			ret = -ESRCH;
> +			goto unlock;
> +		}
>  
> +		WARN_ON_ONCE(reprogram && cpuctx->task_ctx && cpuctx->task_ctx != ctx);
>  	} else if (task_ctx) {
>  		raw_spin_lock(&task_ctx->lock);
>  	}
>  
> -	if (activate) {
> +	if (reprogram) {
>  		ctx_sched_out(ctx, cpuctx, EVENT_TIME);
>  		add_event_to_ctx(event, ctx);
>  		ctx_resched(cpuctx, task_ctx);
> @@ -2331,13 +2330,36 @@ perf_install_in_context(struct perf_event_context *ctx,
>  	/*
>  	 * Installing events is tricky because we cannot rely on ctx->is_active
>  	 * to be set in case this is the nr_events 0 -> 1 transition.
> +	 *
> +	 * Instead we use task_curr(), which tells us if the task is running.
> +	 * However, since we use task_curr() outside of rq::lock, we can race
> +	 * against the actual state. This means the result can be wrong.
> +	 *
> +	 * If we get a false positive, we retry, this is harmless.
> +	 *
> +	 * If we get a false negative, things are complicated. If we are after
> +	 * perf_event_context_sched_in() ctx::lock will serialize us, and the
> +	 * value must be correct. If we're before, it doesn't matter since
> +	 * perf_event_context_sched_in() will program the counter.
> +	 *
> +	 * However, this hinges on the remote context switch having observed
> +	 * our task->perf_event_ctxp[] store, such that it will in fact take
> +	 * ctx::lock in perf_event_context_sched_in().
> +	 *
> +	 * We do this by task_function_call(), if the IPI fails to hit the task
> +	 * we know any future context switch of task must see the
> +	 * perf_event_ctpx[] store.
>  	 */
> -again:
> +
>  	/*
> -	 * Cannot use task_function_call() because we need to run on the task's
> -	 * CPU regardless of whether its current or not.
> +	 * This smp_mb() orders the task->perf_event_ctxp[] store with the
> +	 * task_cpu() load, such that if the IPI then does not find the task
> +	 * running, a future context switch of that task must observe the
> +	 * store.
>  	 */
> -	if (!cpu_function_call(task_cpu(task), __perf_install_in_context, event))
> +	smp_mb();
> +again:
> +	if (!task_function_call(task, __perf_install_in_context, event))
>  		return;

I'm trying to figure out whether or not the barriers implied by the IPI
are sufficient here, or whether we really need the explicit smp_mb().
Certainly, arch_send_call_function_single_ipi has to order the publishing
of the remote work before the signalling of the interrupt, but the comment
above refers to "the task_cpu() load" and I can't see that after your
diff.

What are you trying to order here?

Will

>  
>  	raw_spin_lock_irq(&ctx->lock);
> @@ -2351,12 +2373,16 @@ perf_install_in_context(struct perf_event_context *ctx,
>  		raw_spin_unlock_irq(&ctx->lock);
>  		return;
>  	}
> -	raw_spin_unlock_irq(&ctx->lock);
>  	/*
> -	 * Since !ctx->is_active doesn't mean anything, we must IPI
> -	 * unconditionally.
> +	 * If the task is not running, ctx->lock will avoid it becoming so,
> +	 * thus we can safely install the event.
>  	 */
> -	goto again;
> +	if (task_curr(task)) {
> +		raw_spin_unlock_irq(&ctx->lock);
> +		goto again;
> +	}
> +	add_event_to_ctx(event, ctx);
> +	raw_spin_unlock_irq(&ctx->lock);
>  }
>  
>  /*

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#1540309

FromPeter Zijlstra <peterz@infradead.org>
Date2016-12-12 13:50 +0100
Message-ID<sNydk-4lY-9@gated-at.bofh.it>
In reply to#1540292
On Mon, Dec 12, 2016 at 11:46:40AM +0000, Will Deacon wrote:
> > @@ -2331,13 +2330,36 @@ perf_install_in_context(struct perf_event_context *ctx,
> >  	/*
> >  	 * Installing events is tricky because we cannot rely on ctx->is_active
> >  	 * to be set in case this is the nr_events 0 -> 1 transition.
> > +	 *
> > +	 * Instead we use task_curr(), which tells us if the task is running.
> > +	 * However, since we use task_curr() outside of rq::lock, we can race
> > +	 * against the actual state. This means the result can be wrong.
> > +	 *
> > +	 * If we get a false positive, we retry, this is harmless.
> > +	 *
> > +	 * If we get a false negative, things are complicated. If we are after
> > +	 * perf_event_context_sched_in() ctx::lock will serialize us, and the
> > +	 * value must be correct. If we're before, it doesn't matter since
> > +	 * perf_event_context_sched_in() will program the counter.
> > +	 *
> > +	 * However, this hinges on the remote context switch having observed
> > +	 * our task->perf_event_ctxp[] store, such that it will in fact take
> > +	 * ctx::lock in perf_event_context_sched_in().
> > +	 *
> > +	 * We do this by task_function_call(), if the IPI fails to hit the task
> > +	 * we know any future context switch of task must see the
> > +	 * perf_event_ctpx[] store.
> >  	 */
> > +
> >  	/*
> > +	 * This smp_mb() orders the task->perf_event_ctxp[] store with the
> > +	 * task_cpu() load, such that if the IPI then does not find the task
> > +	 * running, a future context switch of that task must observe the
> > +	 * store.
> >  	 */
> > +	smp_mb();
> > +again:
> > +	if (!task_function_call(task, __perf_install_in_context, event))
> >  		return;
> 
> I'm trying to figure out whether or not the barriers implied by the IPI
> are sufficient here, or whether we really need the explicit smp_mb().
> Certainly, arch_send_call_function_single_ipi has to order the publishing
> of the remote work before the signalling of the interrupt, but the comment
> above refers to "the task_cpu() load" and I can't see that after your
> diff.
> 
> What are you trying to order here?

I suppose something like this:


CPU0		CPU1		CPU2

		(current == t)

t->perf_event_ctxp[] = ctx;
smp_mb();
cpu = task_cpu(t);

		switch(t, n);
				migrate(t, 2);
				switch(p, t);

				ctx = t->perf_event_ctxp[]; // must not be NULL

smp_function_call(cpu, ..);

		generic_exec_single()
		  func();
		    spin_lock(ctx->lock);
		    if (task_curr(t)) // false

		    add_event_to_ctx();
		    spin_unlock(ctx->lock);

				perf_event_context_sched_in();
				  spin_lock(ctx->lock);
				  // sees event


Where between setting the perf_event_ctxp[] and sending the IPI the task
moves away and the IPI misses, and while the new CPU is in the middle of
scheduling in t, it hasn't yet passed through perf_event_sched_in(), but
when it does, it _must_ observe the ctx value we stored.

My thinking was that the IPI itself is not sufficient since when it
misses the task, nothing then guarantees we see the store. However, if
we order the store and the task_cpu() load, then any context
switching/migrating involved with changing that value, should ensure we
see our prior store.

Of course, even now writing this, I'm still confused.

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#1546222

FromPeter Zijlstra <peterz@infradead.org>
Date2016-12-22 09:50 +0100
Message-ID<sR7ex-72i-7@gated-at.bofh.it>
In reply to#1540309
On Mon, Dec 12, 2016 at 01:42:28PM +0100, Peter Zijlstra wrote:
> On Mon, Dec 12, 2016 at 11:46:40AM +0000, Will Deacon wrote:
> > > @@ -2331,13 +2330,36 @@ perf_install_in_context(struct perf_event_context *ctx,
> > >  	/*
> > >  	 * Installing events is tricky because we cannot rely on ctx->is_active
> > >  	 * to be set in case this is the nr_events 0 -> 1 transition.
> > > +	 *
> > > +	 * Instead we use task_curr(), which tells us if the task is running.
> > > +	 * However, since we use task_curr() outside of rq::lock, we can race
> > > +	 * against the actual state. This means the result can be wrong.
> > > +	 *
> > > +	 * If we get a false positive, we retry, this is harmless.
> > > +	 *
> > > +	 * If we get a false negative, things are complicated. If we are after
> > > +	 * perf_event_context_sched_in() ctx::lock will serialize us, and the
> > > +	 * value must be correct. If we're before, it doesn't matter since
> > > +	 * perf_event_context_sched_in() will program the counter.
> > > +	 *
> > > +	 * However, this hinges on the remote context switch having observed
> > > +	 * our task->perf_event_ctxp[] store, such that it will in fact take
> > > +	 * ctx::lock in perf_event_context_sched_in().
> > > +	 *
> > > +	 * We do this by task_function_call(), if the IPI fails to hit the task
> > > +	 * we know any future context switch of task must see the
> > > +	 * perf_event_ctpx[] store.
> > >  	 */
> > > +
> > >  	/*
> > > +	 * This smp_mb() orders the task->perf_event_ctxp[] store with the
> > > +	 * task_cpu() load, such that if the IPI then does not find the task
> > > +	 * running, a future context switch of that task must observe the
> > > +	 * store.
> > >  	 */
> > > +	smp_mb();
> > > +again:
> > > +	if (!task_function_call(task, __perf_install_in_context, event))
> > >  		return;
> > 
> > I'm trying to figure out whether or not the barriers implied by the IPI
> > are sufficient here, or whether we really need the explicit smp_mb().
> > Certainly, arch_send_call_function_single_ipi has to order the publishing
> > of the remote work before the signalling of the interrupt, but the comment
> > above refers to "the task_cpu() load" and I can't see that after your
> > diff.
> > 
> > What are you trying to order here?
> 
> I suppose something like this:
> 
> 
> CPU0		CPU1		CPU2
> 
> 		(current == t)
> 
> t->perf_event_ctxp[] = ctx;
> smp_mb();
> cpu = task_cpu(t);
> 
> 		switch(t, n);
> 				migrate(t, 2);
> 				switch(p, t);
> 
> 				ctx = t->perf_event_ctxp[]; // must not be NULL
> 

So I think I can cast the above into a test like:

  W[x] = 1                W[y] = 1                R[z] = 1
  mb                      mb                      mb
  R[y] = 0                W[z] = 1                R[x] = 0

Where x is the perf_event_ctxp[], y is our task's cpu and z is our task
being placed on the rq of cpu2.

See also commit: 8643cda549ca ("sched/core, locking: Document
Program-Order guarantees"), Independent of which cpu initiates the
migration between CPU1 and CPU2 there is ordering between the CPUs.

This would then translate into something like:

  C C-peterz

  {
  }

  P0(int *x, int *y)
  {
	  int r1;

	  WRITE_ONCE(*x, 1);
	  smp_mb();
	  r1 = READ_ONCE(*y);
  }

  P1(int *y, int *z)
  {
	  WRITE_ONCE(*y, 1);
	  smp_mb();
	  WRITE_ONCE(*z, 1);
  }

  P2(int *x, int *z)
  {
	  int r1;
	  int r2;

	  r1 = READ_ONCE(*z);
	  smp_mb();
	  r2 = READ_ONCE(*x);
  }

  exists
  (0:r1=0 /\ 2:r1=1 /\ 2:r2=0)

Which evaluates into:

  Test C-peterz Allowed
  States 7
  0:r1=0; 2:r1=0; 2:r2=0;
  0:r1=0; 2:r1=0; 2:r2=1;
  0:r1=0; 2:r1=1; 2:r2=1;
  0:r1=1; 2:r1=0; 2:r2=0;
  0:r1=1; 2:r1=0; 2:r2=1;
  0:r1=1; 2:r1=1; 2:r2=0;
  0:r1=1; 2:r1=1; 2:r2=1;
  No
  Witnesses
  Positive: 0 Negative: 7
  Condition exists (0:r1=0 /\ 2:r1=1 /\ 2:r2=0)
  Observation C-peterz Never 0 7
  Hash=661589febb9e41b222d8acae1fd64e25

And the strong and weak model agree.


> smp_function_call(cpu, ..);
> 
> 		generic_exec_single()
> 		  func();
> 		    spin_lock(ctx->lock);
> 		    if (task_curr(t)) // false
> 
> 		    add_event_to_ctx();
> 		    spin_unlock(ctx->lock);
> 
> 				perf_event_context_sched_in();
> 				  spin_lock(ctx->lock);
> 				  // sees event
> 
> 
> Where between setting the perf_event_ctxp[] and sending the IPI the task
> moves away and the IPI misses, and while the new CPU is in the middle of
> scheduling in t, it hasn't yet passed through perf_event_sched_in(), but
> when it does, it _must_ observe the ctx value we stored.
> 
> My thinking was that the IPI itself is not sufficient since when it
> misses the task, nothing then guarantees we see the store. However, if
> we order the store and the task_cpu() load, then any context
> switching/migrating involved with changing that value, should ensure we
> see our prior store.
> 
> Of course, even now writing this, I'm still confused.

On IRC you said:

: I think it's similar to the "ISA2" litmus test, only the first reads-from edge is an IPI and the second is an Unlock->Lock

In case the IPI misses, we cannot use the IPI itself for anything I'm
afraid, also per the above we don't need to.

: the case I'm more confused by is if CPU2 takes the ctx->lock before CPU1
: I'm guessing that's prevented by the way migration works?

So same scenario but CPU2 takes the ctx->lock first. In that case it
will not observe our event and do nothing. CPU1 will then acquire
ctx->lock, this then implies ordering against CPU2, which means it
_must_ observe task_curr() && task != current and it too will not do
anything but we'll loop and try the whole thing again.

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#1546389

FromPeter Zijlstra <peterz@infradead.org>
Date2016-12-22 15:10 +0100
Message-ID<sRcee-22K-15@gated-at.bofh.it>
In reply to#1546222
On Thu, Dec 22, 2016 at 09:45:09AM +0100, Peter Zijlstra wrote:
> On Mon, Dec 12, 2016 at 01:42:28PM +0100, Peter Zijlstra wrote:

> > > What are you trying to order here?
> > 
> > I suppose something like this:
> > 
> > 
> > CPU0		CPU1		CPU2
> > 
> > 		(current == t)
> > 
> > t->perf_event_ctxp[] = ctx;
> > smp_mb();
> > cpu = task_cpu(t);
> > 
> > 		switch(t, n);
> > 				migrate(t, 2);
> > 				switch(p, t);
> > 
> > 				ctx = t->perf_event_ctxp[]; // must not be NULL
> > 
> 
> So I think I can cast the above into a test like:
> 
>   W[x] = 1                W[y] = 1                R[z] = 1
>   mb                      mb                      mb
>   R[y] = 0                W[z] = 1                R[x] = 0
> 
> Where x is the perf_event_ctxp[], y is our task's cpu and z is our task
> being placed on the rq of cpu2.
> 
> See also commit: 8643cda549ca ("sched/core, locking: Document
> Program-Order guarantees"), Independent of which cpu initiates the
> migration between CPU1 and CPU2 there is ordering between the CPUs.

I think that when we assume RCpc locks, the above CPU1 mb ends up being
something like an smp_wmb() (ie. non transitive). CPU2 needs to do a
context switch between observing the task on its runqueue and getting to
switching in perf-events for the task, which keeps that a full mb.

Now, if only this model would have locks in ;-)

> This would then translate into something like:
> 
>   C C-peterz
> 
>   {
>   }
> 
>   P0(int *x, int *y)
>   {
> 	  int r1;
> 
> 	  WRITE_ONCE(*x, 1);
> 	  smp_mb();
> 	  r1 = READ_ONCE(*y);
>   }
> 
>   P1(int *y, int *z)
>   {
> 	  WRITE_ONCE(*y, 1);
> 	  smp_mb();

And this modified to: smp_wmb()

> 	  WRITE_ONCE(*z, 1);
>   }
> 
>   P2(int *x, int *z)
>   {
> 	  int r1;
> 	  int r2;
> 
> 	  r1 = READ_ONCE(*z);
> 	  smp_mb();
> 	  r2 = READ_ONCE(*x);
>   }
> 
>   exists
>   (0:r1=0 /\ 2:r1=1 /\ 2:r2=0)

Still results in the same outcome.

If however we change P2's barrier into a smp_rmb() it does become
possible, but as said above, there's a context switch in between which
implies a full barrier so no worries.

Similar if I replace everything z with smp_store_release() and
smp_load_acquire().


Of course, its entirely possible the litmus test doesn't reflect
reality, I still find it somewhat hard to write these things.

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#1546476

From"Paul E. McKenney" <paulmck@linux.vnet.ibm.com>
Date2016-12-22 17:40 +0100
Message-ID<sRezo-3nZ-25@gated-at.bofh.it>
In reply to#1546389
On Thu, Dec 22, 2016 at 03:00:10PM +0100, Peter Zijlstra wrote:
> On Thu, Dec 22, 2016 at 09:45:09AM +0100, Peter Zijlstra wrote:
> > On Mon, Dec 12, 2016 at 01:42:28PM +0100, Peter Zijlstra wrote:
> 
> > > > What are you trying to order here?
> > > 
> > > I suppose something like this:
> > > 
> > > 
> > > CPU0		CPU1		CPU2
> > > 
> > > 		(current == t)
> > > 
> > > t->perf_event_ctxp[] = ctx;
> > > smp_mb();
> > > cpu = task_cpu(t);
> > > 
> > > 		switch(t, n);
> > > 				migrate(t, 2);
> > > 				switch(p, t);
> > > 
> > > 				ctx = t->perf_event_ctxp[]; // must not be NULL
> > > 
> > 
> > So I think I can cast the above into a test like:
> > 
> >   W[x] = 1                W[y] = 1                R[z] = 1
> >   mb                      mb                      mb
> >   R[y] = 0                W[z] = 1                R[x] = 0
> > 
> > Where x is the perf_event_ctxp[], y is our task's cpu and z is our task
> > being placed on the rq of cpu2.
> > 
> > See also commit: 8643cda549ca ("sched/core, locking: Document
> > Program-Order guarantees"), Independent of which cpu initiates the
> > migration between CPU1 and CPU2 there is ordering between the CPUs.
> 
> I think that when we assume RCpc locks, the above CPU1 mb ends up being
> something like an smp_wmb() (ie. non transitive). CPU2 needs to do a
> context switch between observing the task on its runqueue and getting to
> switching in perf-events for the task, which keeps that a full mb.
> 
> Now, if only this model would have locks in ;-)

Yeah, we are slow.  ;-)

But you should be able to emulate them with xchg_acquire() and
smp_store_release().

							Thanx, Paul

> > This would then translate into something like:
> > 
> >   C C-peterz
> > 
> >   {
> >   }
> > 
> >   P0(int *x, int *y)
> >   {
> > 	  int r1;
> > 
> > 	  WRITE_ONCE(*x, 1);
> > 	  smp_mb();
> > 	  r1 = READ_ONCE(*y);
> >   }
> > 
> >   P1(int *y, int *z)
> >   {
> > 	  WRITE_ONCE(*y, 1);
> > 	  smp_mb();
> 
> And this modified to: smp_wmb()
> 
> > 	  WRITE_ONCE(*z, 1);
> >   }
> > 
> >   P2(int *x, int *z)
> >   {
> > 	  int r1;
> > 	  int r2;
> > 
> > 	  r1 = READ_ONCE(*z);
> > 	  smp_mb();
> > 	  r2 = READ_ONCE(*x);
> >   }
> > 
> >   exists
> >   (0:r1=0 /\ 2:r1=1 /\ 2:r2=0)
> 
> Still results in the same outcome.
> 
> If however we change P2's barrier into a smp_rmb() it does become
> possible, but as said above, there's a context switch in between which
> implies a full barrier so no worries.
> 
> Similar if I replace everything z with smp_store_release() and
> smp_load_acquire().
> 
> 
> Of course, its entirely possible the litmus test doesn't reflect
> reality, I still find it somewhat hard to write these things.
> 

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