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Groups > linux.kernel > #1330763 > unrolled thread
| Started by | "Luck, Tony" <tony.luck@intel.com> |
|---|---|
| First post | 2016-02-10 00:20 +0100 |
| Last post | 2016-02-10 22:00 +0100 |
| Articles | 4 — 2 participants |
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Re: [PATCH v10 3/4] x86, mce: Add __mcsafe_copy() "Luck, Tony" <tony.luck@intel.com> - 2016-02-10 00:20 +0100
Re: [PATCH v10 3/4] x86, mce: Add __mcsafe_copy() Borislav Petkov <bp@alien8.de> - 2016-02-10 12:00 +0100
Re: [PATCH v10 3/4] x86, mce: Add __mcsafe_copy() "Luck, Tony" <tony.luck@intel.com> - 2016-02-10 20:40 +0100
Re: [PATCH v10 3/4] x86, mce: Add __mcsafe_copy() Borislav Petkov <bp@alien8.de> - 2016-02-10 22:00 +0100
| From | "Luck, Tony" <tony.luck@intel.com> |
|---|---|
| Date | 2016-02-10 00:20 +0100 |
| Subject | Re: [PATCH v10 3/4] x86, mce: Add __mcsafe_copy() |
| Message-ID | <r0pJD-2qT-7@gated-at.bofh.it> |
> You can save yourself this MOV here in what is, I'm assuming, the > general likely case where @src is aligned and do: > > /* check for bad alignment of source */ > testl $7, %esi > /* already aligned? */ > jz 102f > > movl %esi,%ecx > subl $8,%ecx > negl %ecx > subl %ecx,%edx > 0: movb (%rsi),%al > movb %al,(%rdi) > incq %rsi > incq %rdi > decl %ecx > jnz 0b The "testl $7, %esi" just checks the low three bits ... it doesn't change %esi. But the code from the "subl $8" on down assumes that %ecx is a number in [1..7] as the count of bytes to copy until we achieve alignment. So your "movl %esi,%ecx" needs to be somthing that just copies the low three bits and zeroes the high part of %ecx. Is there a cute way to do that in x86 assembler? > Why aren't we pushing %r12-%r15 on the stack after the "jz 17f" above > and using them too and thus copying a whole cacheline in one go? > > We would need to restore them when we're done with the cacheline-wise > shuffle, of course. I copied that loop from arch/x86/lib/copy_user_64.S:__copy_user_nocache() I guess the answer depends on whether you generally copy enough cache lines to save enough time to cover the cost of saving and restoring those registers. -Tony
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| From | Borislav Petkov <bp@alien8.de> |
|---|---|
| Date | 2016-02-10 12:00 +0100 |
| Message-ID | <r0AF4-15k-7@gated-at.bofh.it> |
| In reply to | #1330763 |
On Tue, Feb 09, 2016 at 03:15:57PM -0800, Luck, Tony wrote:
> > You can save yourself this MOV here in what is, I'm assuming, the
> > general likely case where @src is aligned and do:
> >
> > /* check for bad alignment of source */
> > testl $7, %esi
> > /* already aligned? */
> > jz 102f
> >
> > movl %esi,%ecx
> > subl $8,%ecx
> > negl %ecx
> > subl %ecx,%edx
> > 0: movb (%rsi),%al
> > movb %al,(%rdi)
> > incq %rsi
> > incq %rdi
> > decl %ecx
> > jnz 0b
>
> The "testl $7, %esi" just checks the low three bits ... it doesn't
> change %esi. But the code from the "subl $8" on down assumes that
> %ecx is a number in [1..7] as the count of bytes to copy until we
> achieve alignment.
Grr, sorry about that, I actually missed to copy-paste the AND:
/* check for bad alignment of source */
testl $7, %esi
jz 102f /* already aligned */
movl %esi,%ecx
andl $7,%ecx
subl $8,%ecx
negl %ecx
subl %ecx,%edx
0: movb (%rsi),%al
movb %al,(%rdi)
incq %rsi
incq %rdi
decl %ecx
jnz 0b
I basically am proposing to move the unlikely case out of line and
optimize the likely one.
> So your "movl %esi,%ecx" needs to be somthing that just copies the
> low three bits and zeroes the high part of %ecx. Is there a cute
> way to do that in x86 assembler?
We could do some funky games with byte-sized moves but those are
generally slower anyway so doing the default operand size thing should
be ok.
> I copied that loop from arch/x86/lib/copy_user_64.S:__copy_user_nocache()
> I guess the answer depends on whether you generally copy enough
> cache lines to save enough time to cover the cost of saving and
> restoring those registers.
Well, that function will run on modern hw with a stack engine so I'd
assume those 4 pushes and pops would be paid for by the increased
registers count for the data shuffling.
But one could take out that function do some microbenchmarking with
different sizes and once with the current version and once with the
pushes and pops of r1[2-5] to see where the breakeven is.
--
Regards/Gruss,
Boris.
ECO tip #101: Trim your mails when you reply.
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| From | "Luck, Tony" <tony.luck@intel.com> |
|---|---|
| Date | 2016-02-10 20:40 +0100 |
| Message-ID | <r0IMi-6Am-5@gated-at.bofh.it> |
| In reply to | #1331065 |
On Wed, Feb 10, 2016 at 11:58:43AM +0100, Borislav Petkov wrote: > But one could take out that function do some microbenchmarking with > different sizes and once with the current version and once with the > pushes and pops of r1[2-5] to see where the breakeven is. On a 4K page copy from a source address that isn't in the cache I see all sorts of answers. On my desktop (i7-3960X) it is ~50 cycles slower to push and pop the four registers. On my latest Xeon - I can't post benchmarks ... but also a bit slower. On an older Xeon it is a few cycles faster (but even though I'm looking at the median of 10,000 runs I see more run-to-run variation that I see difference between register choices. Here's what I tested: push %r12 push %r13 push %r14 push %r15 /* Loop copying whole cache lines */ 1: movq (%rsi),%r8 2: movq 1*8(%rsi),%r9 3: movq 2*8(%rsi),%r10 4: movq 3*8(%rsi),%r11 9: movq 4*8(%rsi),%r12 10: movq 5*8(%rsi),%r13 11: movq 6*8(%rsi),%r14 12: movq 7*8(%rsi),%r15 movq %r8,(%rdi) movq %r9,1*8(%rdi) movq %r10,2*8(%rdi) movq %r11,3*8(%rdi) movq %r12,4*8(%rdi) movq %r13,5*8(%rdi) movq %r14,6*8(%rdi) movq %r15,7*8(%rdi) leaq 64(%rsi),%rsi leaq 64(%rdi),%rdi decl %ecx jnz 1b pop %r15 pop %r14 pop %r13 pop %r12 -Tony
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| From | Borislav Petkov <bp@alien8.de> |
|---|---|
| Date | 2016-02-10 22:00 +0100 |
| Message-ID | <r0K1H-7gs-1@gated-at.bofh.it> |
| In reply to | #1331452 |
On Wed, Feb 10, 2016 at 11:39:05AM -0800, Luck, Tony wrote:
> On Wed, Feb 10, 2016 at 11:58:43AM +0100, Borislav Petkov wrote:
> > But one could take out that function do some microbenchmarking with
> > different sizes and once with the current version and once with the
> > pushes and pops of r1[2-5] to see where the breakeven is.
>
> On a 4K page copy from a source address that isn't in the
> cache I see all sorts of answers.
>
> On my desktop (i7-3960X) it is ~50 cycles slower to push and pop the four
> registers.
>
> On my latest Xeon - I can't post benchmarks ... but also a bit slower.
>
> On an older Xeon it is a few cycles faster (but even though I'm
> looking at the median of 10,000 runs I see more run-to-run variation
> that I see difference between register choices.
Hmm, strange. Can you check whether perf doesn't show any significant
differences too. Something like:
perf stat --repeat 100 --sync --pre 'echo 3 > /proc/sys/vm/drop_caches' -- ./mcsafe_copy_1
and then
perf stat --repeat 100 --sync --pre 'echo 3 > /proc/sys/vm/drop_caches' -- ./mcsafe_copy_2
That'll be interesting...
Thanks.
--
Regards/Gruss,
Boris.
ECO tip #101: Trim your mails when you reply.
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