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Re: Segment fault ../sysdeps/i386/i686/multiarch/strcpy-sse2.S

From Lev Lazinskiy <lev@levlaz.org>
Newsgroups linux.debian.user
Subject Re: Segment fault ../sysdeps/i386/i686/multiarch/strcpy-sse2.S
Date 2015-08-29 09:20 +0200
Message-ID <q2IAG-3ek-1@gated-at.bofh.it> (permalink)
References <q2IAG-3ek-3@gated-at.bofh.it> <q2Ihj-2Cx-1@gated-at.bofh.it>
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On Sat, 2015-08-29 at 08:54 +0200, Dan Richard wrote:
> My Debian is with kernel 4.0.0-2-rt-686-pae, and gcc (Debian 4.9.2
> -10) 4.9.2. 
>  
> I have a program where it uses strcpy, but when executing 
> (compilation successfully), it throws segment fault. Debugging with 
> gdb, it shows that it goes worng in strcpy function. 
>  
> _strcpy_sse2 () at ../sysdeps/i386/i686/multiarch/strcpy-sse2.S:2099
> 2099    ../sysdeps/i386/i686/multiarch/strcpy-sse2.S: No such file or 
> directory.
>  
> I wrote a simple program, it also throws segment fault. 
>  
> #include <string.h>
> #include <stdio.h>
> int main(int argc, char **argv)
> {
>   char *str;
>   strcpy(str, "hello");
>   printf("say %s\n", str);
>   return 0;
> }
>  
> How can I fix this problem?
>  
> Thanks
>  

Hi, 

You are failing to allocate memory. This sample program should look
something like this: 

#include <string.h>
#include <stdio.h>
#include <malloc.h>

int main(int argc, char **argv)
{
  char *str;
  str = malloc (5);
  strcpy(str, "hello");
  printf("say %s\n", str);
  free(str);
  return 0;
}

Best, 
Lev

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Re: Segment fault ../sysdeps/i386/i686/multiarch/strcpy-sse2.S Lev Lazinskiy <lev@levlaz.org> - 2015-08-29 09:20 +0200
  Re: Segment fault ../sysdeps/i386/i686/multiarch/strcpy-sse2.S "Thomas Schmitt" <scdbackup@gmx.net> - 2015-08-29 10:30 +0200

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