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Groups > comp.theory > #36666 > unrolled thread
| Started by | Mr Flibble <flibble@reddwarf.jmc> |
|---|---|
| First post | 2021-07-19 21:46 +0100 |
| Last post | 2021-07-20 14:17 -0700 |
| Articles | 20 on this page of 525 — 16 participants |
Back to article view | Back to comp.theory
Black box halt decider is NOT a partial decider Mr Flibble <flibble@reddwarf.jmc> - 2021-07-19 21:46 +0100
Re: Black box halt decider is NOT a partial decider "Chris M. Thomasson" <chris.m.thomasson.1@gmail.com> - 2021-07-19 14:03 -0700
Re: Black box halt decider is NOT a partial decider David Brown <david.brown@hesbynett.no> - 2021-07-20 21:06 +0200
Re: Black box halt decider is NOT a partial decider "Chris M. Thomasson" <chris.m.thomasson.1@gmail.com> - 2021-07-20 13:43 -0700
Re: Black box halt decider is NOT a partial decider Richard Damon <Richard@Damon-Family.org> - 2021-07-20 13:56 -0700
Re: Black box halt decider is NOT a partial decider "Chris M. Thomasson" <chris.m.thomasson.1@gmail.com> - 2021-07-20 14:16 -0700
Re: Black box halt decider is NOT a partial decider Richard Damon <Richard@Damon-Family.org> - 2021-07-20 14:50 -0700
Re: Black box halt decider is NOT a partial decider "Chris M. Thomasson" <chris.m.thomasson.1@gmail.com> - 2021-07-20 22:33 -0700
Re: Black box halt decider is NOT a partial decider Richard Damon <Richard@Damon-Family.org> - 2021-07-20 23:30 -0700
Re: Black box halt decider is NOT a partial decider Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-07-21 13:17 +0100
Re: Black box halt decider is NOT a partial decider "Chris M. Thomasson" <chris.m.thomasson.1@gmail.com> - 2021-07-22 13:35 -0700
Re: Black box halt decider is NOT a partial decider Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-07-22 22:10 +0100
Re: Black box halt decider is NOT a partial decider "Chris M. Thomasson" <chris.m.thomasson.1@gmail.com> - 2021-07-23 14:22 -0700
Re: Black box halt decider is NOT a partial decider Richard Damon <Richard@Damon-Family.org> - 2021-07-23 14:30 -0700
Re: Black box halt decider is NOT a partial decider Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-07-23 23:15 +0100
Re: Black box halt decider is NOT a partial decider "Chris M. Thomasson" <chris.m.thomasson.1@gmail.com> - 2021-07-23 15:28 -0700
Re: Black box halt decider is NOT a partial decider André G. Isaak <agisaak@gm.invalid> - 2021-07-23 16:49 -0600
Re: Black box halt decider is NOT a partial decider "Chris M. Thomasson" <chris.m.thomasson.1@gmail.com> - 2021-07-23 16:09 -0700
Re: Black box halt decider is NOT a partial decider Mike Terry <news.dead.person.stones@darjeeling.plus.com> - 2021-07-24 02:34 +0100
Re: Black box halt decider is NOT a partial decider "Chris M. Thomasson" <chris.m.thomasson.1@gmail.com> - 2021-08-04 21:53 -0700
Re: Black box halt decider is NOT a partial decider "Chris M. Thomasson" <chris.m.thomasson.1@gmail.com> - 2021-08-04 21:54 -0700
Re: Black box halt decider is NOT a partial decider Mike Terry <news.dead.person.stones@darjeeling.plus.com> - 2021-08-05 15:37 +0100
Re: Black box halt decider is NOT a partial decider Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-05 17:08 +0100
Re: Black box halt decider is NOT a partial decider Jeff Barnett <jbb@notatt.com> - 2021-08-05 11:41 -0600
Re: Black box halt decider is NOT a partial decider Jeff Barnett <jbb@notatt.com> - 2021-08-05 11:48 -0600
Re: Black box halt decider is NOT a partial decider Mike Terry <news.dead.person.stones@darjeeling.plus.com> - 2021-08-05 20:30 +0100
Re: Black box halt decider is NOT a partial decider "Chris M. Thomasson" <chris.m.thomasson.1@gmail.com> - 2021-08-05 13:55 -0700
Re: Black box halt decider is NOT a partial decider Jeff Barnett <jbb@notatt.com> - 2021-08-05 15:51 -0600
Re: Black box halt decider is NOT a partial decider Mike Terry <news.dead.person.stones@darjeeling.plus.com> - 2021-08-05 23:20 +0100
Re: Black box halt decider is NOT a partial decider "Chris M. Thomasson" <chris.m.thomasson.1@gmail.com> - 2021-08-05 13:53 -0700
Re: Black box halt decider is NOT a partial decider Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-05 22:21 +0100
Re: Black box halt decider is NOT a partial decider "Chris M. Thomasson" <chris.m.thomasson.1@gmail.com> - 2021-08-05 15:42 -0700
Re: Black box halt decider is NOT a partial decider "Chris M. Thomasson" <chris.m.thomasson.1@gmail.com> - 2021-08-05 15:48 -0700
Re: Black box halt decider is NOT a partial decider "Chris M. Thomasson" <chris.m.thomasson.1@gmail.com> - 2021-08-05 15:49 -0700
Re: Black box halt decider is NOT a partial decider "Chris M. Thomasson" <chris.m.thomasson.1@gmail.com> - 2021-08-05 15:52 -0700
Re: Black box halt decider is NOT a partial decider wij <wyniijj@gmail.com> - 2021-08-05 21:58 -0700
Re: Black box halt decider is NOT a partial decider Richard Damon <Richard@Damon-Family.org> - 2021-07-23 16:10 -0700
Re: Black box halt decider is NOT a partial decider "Chris M. Thomasson" <chris.m.thomasson.1@gmail.com> - 2021-07-23 16:14 -0700
Re: Black box halt decider is NOT a partial decider Richard Damon <Richard@Damon-Family.org> - 2021-07-23 16:40 -0700
Re: Black box halt decider is NOT a partial decider "Chris M. Thomasson" <chris.m.thomasson.1@gmail.com> - 2021-07-24 12:50 -0700
Re: Black box halt decider is NOT a partial decider Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-07-24 00:54 +0100
Re: Black box halt decider is NOT a partial decider "Chris M. Thomasson" <chris.m.thomasson.1@gmail.com> - 2021-07-23 16:59 -0700
Re: Black box halt decider is NOT a partial decider Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-07-25 00:42 +0100
Re: Black box halt decider is NOT a partial decider "Chris M. Thomasson" <chris.m.thomasson.1@gmail.com> - 2021-07-25 12:55 -0700
Re: Black box halt decider is NOT a partial decider Richard Damon <Richard@Damon-Family.org> - 2021-07-25 13:13 -0700
Re: Black box halt decider is NOT a partial decider "Chris M. Thomasson" <chris.m.thomasson.1@gmail.com> - 2021-07-25 14:08 -0700
Re: Black box halt decider is NOT a partial decider André G. Isaak <agisaak@gm.invalid> - 2021-07-24 18:07 -0600
Re: Black box halt decider is NOT a partial decider Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-07-25 01:50 +0100
Re: Black box halt decider is NOT a partial decider André G. Isaak <agisaak@gm.invalid> - 2021-07-24 20:58 -0600
Re: Black box halt decider is NOT a partial decider Mike Terry <news.dead.person.stones@darjeeling.plus.com> - 2021-07-25 04:03 +0100
Re: Black box halt decider is NOT a partial decider Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-07-25 04:22 +0100
Re: Black box halt decider is NOT a partial decider Andy Walker <anw@cuboid.co.uk> - 2021-07-25 13:34 +0100
Re: Black box halt decider is NOT a partial decider Mike Terry <news.dead.person.stones@darjeeling.plus.com> - 2021-07-25 17:14 +0100
Re: Black box halt decider is NOT a partial decider Malcolm McLean <malcolm.arthur.mclean@gmail.com> - 2021-07-25 10:40 -0700
Re: Black box halt decider is NOT a partial decider [ H(P,P)==0 is always correct ] olcott <NoOne@NoWhere.com> - 2021-07-25 13:10 -0500
Re: Black box halt decider is NOT a partial decider [ H(P,P)==0 is always correct ] Richard Damon <Richard@Damon-Family.org> - 2021-07-25 11:31 -0700
Re: Black box halt decider is NOT a partial decider [ H(P,P)==0 is always correct ] olcott <NoOne@NoWhere.com> - 2021-07-25 13:22 -0500
Re: Black box halt decider is NOT a partial decider [ H(P,P)==0 is always correct ] André G. Isaak <agisaak@gm.invalid> - 2021-07-25 12:43 -0600
Re: Black box halt decider is NOT a partial decider [ H(P,P)==0 is always correct ] Richard Damon <Richard@Damon-Family.org> - 2021-07-25 12:25 -0700
Re: Black box halt decider is NOT a partial decider [ H(P,P)==0 is always correct ] Malcolm McLean <malcolm.arthur.mclean@gmail.com> - 2021-07-25 12:46 -0700
Re: Black box halt decider is NOT a partial decider [ H(P,P)==0 is always correct ] Richard Damon <Richard@Damon-Family.org> - 2021-07-25 13:04 -0700
Re: Black box halt decider is NOT a partial decider [ H(P,P)==0 is always correct ] Jeff Barnett <jbb@notatt.com> - 2021-07-25 16:58 -0600
Re: Black box halt decider is NOT a partial decider [ H(P,P)==0 is always correct ] Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-07-25 20:38 +0100
Re: Black box halt decider is NOT a partial decider Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-07-25 20:52 +0100
Re: Black box halt decider is NOT a partial decider Malcolm McLean <malcolm.arthur.mclean@gmail.com> - 2021-07-25 13:54 -0700
Re: Black box halt decider is NOT a partial decider [ paradox rather than contradiction ] olcott <NoOne@NoWhere.com> - 2021-07-25 22:53 -0500
Re: Black box halt decider is NOT a partial decider [ paradox rather than contradiction ] Richard Damon <Richard@Damon-Family.org> - 2021-07-25 21:40 -0700
Re: Black box halt decider is NOT a partial decider [ paradox rather than contradiction ] André G. Isaak <agisaak@gm.invalid> - 2021-07-25 23:09 -0600
Re: Black box halt decider is NOT a partial decider [ H refutes Rice's Theorem ] olcott <NoOne@NoWhere.com> - 2021-07-26 09:20 -0500
Re: Black box halt decider is NOT a partial decider [ H refutes Rice's Theorem ] Richard Damon <Richard@Damon-Family.org> - 2021-07-26 07:40 -0700
Re: Black box halt decider is NOT a partial decider [ H refutes Rice's Theorem ] André G. Isaak <agisaak@gm.invalid> - 2021-07-26 10:09 -0600
Re: Black box halt decider is NOT a partial decider [ H refutes Rice's Theorem ] olcott <NoOne@NoWhere.com> - 2021-07-26 11:41 -0500
Re: Black box halt decider is NOT a partial decider [ H refutes Rice's Theorem ] André G. Isaak <agisaak@gm.invalid> - 2021-07-26 11:00 -0600
Re: Black box halt decider is NOT a partial decider [ H refutes Rice's Theorem ] olcott <NoOne@NoWhere.com> - 2021-07-26 14:40 -0500
Re: Black box halt decider is NOT a partial decider [ H refutes Rice's Theorem ] Richard Damon <Richard@Damon-Family.org> - 2021-07-26 15:29 -0700
Re: Black box halt decider is NOT a partial decider [ H refutes Rice's Theorem ] Jeff Barnett <jbb@notatt.com> - 2021-07-26 11:16 -0600
Re: Black box halt decider is NOT a partial decider [ H refutes Rice's Theorem ] olcott <NoOne@NoWhere.com> - 2021-07-26 13:57 -0500
Re: Black box halt decider is NOT a partial decider [ H refutes Rice's Theorem ] André G. Isaak <agisaak@gm.invalid> - 2021-07-26 13:55 -0600
Re: Black box halt decider is NOT a partial decider [ H refutes Rice's Theorem ] olcott <NoOne@NoWhere.com> - 2021-07-26 15:34 -0500
Re: Black box halt decider is NOT a partial decider [ H refutes Rice's Theorem ] André G. Isaak <agisaak@gm.invalid> - 2021-07-26 14:53 -0600
Re: Black box halt decider is NOT a partial decider [ H refutes Rice's Theorem ] Richard Damon <Richard@Damon-Family.org> - 2021-07-26 16:01 -0700
Re: Black box halt decider is NOT a partial decider [ H refutes Rice's Theorem ] olcott <NoOne@NoWhere.com> - 2021-07-26 19:14 -0500
Re: Black box halt decider is NOT a partial decider [ H refutes Rice's Theorem ] André G. Isaak <agisaak@gm.invalid> - 2021-07-26 18:21 -0600
Re: Black box halt decider is NOT a partial decider [ H refutes Rice's Theorem ] olcott <NoOne@NoWhere.com> - 2021-07-26 20:03 -0500
Re: Black box halt decider is NOT a partial decider [ H refutes Rice's Theorem ] André G. Isaak <agisaak@gm.invalid> - 2021-07-26 19:24 -0600
Re: Black box halt decider is NOT a partial decider [ H refutes Rice's Theorem ] olcott <NoOne@NoWhere.com> - 2021-07-26 20:30 -0500
Re: Black box halt decider is NOT a partial decider [ H refutes Rice's Theorem ] André G. Isaak <agisaak@gm.invalid> - 2021-07-26 20:34 -0600
Re: Black box halt decider is NOT a partial decider [ André doesn't know Rice's Theorem ] olcott <NoOne@NoWhere.com> - 2021-07-26 22:18 -0500
Re: Black box halt decider is NOT a partial decider [ André doesn't know Rice's Theorem ] André G. Isaak <agisaak@gm.invalid> - 2021-07-26 21:24 -0600
Re: Black box halt decider is NOT a partial decider [ André doesn't know Rice's Theorem ] olcott <NoOne@NoWhere.com> - 2021-07-26 22:31 -0500
Re: Black box halt decider is NOT a partial decider [ André doesn't know Rice's Theorem ] André G. Isaak <agisaak@gm.invalid> - 2021-07-26 21:55 -0600
Re: Black box halt decider is NOT a partial decider [ André doesn't know Rice's Theorem ] olcott <NoOne@NoWhere.com> - 2021-07-26 23:39 -0500
Re: Black box halt decider is NOT a partial decider [ André doesn't know Rice's Theorem ] André G. Isaak <agisaak@gm.invalid> - 2021-07-26 22:59 -0600
Re: Black box halt decider is NOT a partial decider [ André doesn't know Rice's Theorem ] olcott <NoOne@NoWhere.com> - 2021-07-27 10:27 -0500
Re: Black box halt decider is NOT a partial decider [ André doesn't know Rice's Theorem ] Richard Damon <Richard@Damon-Family.org> - 2021-07-26 22:22 -0700
Re: Black box halt decider is NOT a partial decider [ André doesn't know Rice's Theorem ] Malcolm McLean <malcolm.arthur.mclean@gmail.com> - 2021-07-27 02:42 -0700
Re: André doesn't know Rice's Theorem [ Malcolm ] olcott <NoOne@NoWhere.com> - 2021-07-27 10:24 -0500
Re: André doesn't know Rice's Theorem [ Malcolm ] Richard Damon <Richard@Damon-Family.org> - 2021-07-27 08:54 -0700
Re: André doesn't know Rice's Theorem [ Malcolm ]( finally quit lying ) olcott <NoOne@NoWhere.com> - 2021-07-27 11:05 -0500
Re: André doesn't know Rice's Theorem [ Malcolm ]( finally quit lying ) Richard Damon <Richard@Damon-Family.org> - 2021-07-27 09:29 -0700
Re: André doesn't know Rice's Theorem [ Malcolm ]( attention deficit disorder ) olcott <NoOne@NoWhere.com> - 2021-07-27 12:07 -0500
Re: André doesn't know Rice's Theorem [ Malcolm ]( attention deficit disorder ) Richard Damon <Richard@Damon-Family.org> - 2021-07-27 11:17 -0700
Re: André doesn't know Rice's Theorem [ Malcolm ]( attention deficit disorder ) olcott <NoOne@NoWhere.com> - 2021-07-27 13:29 -0500
Re: André doesn't know Rice's Theorem [ Malcolm ]( attention deficit disorder ) Richard Damon <Richard@Damon-Family.org> - 2021-07-27 11:47 -0700
Re: André doesn't know Rice's Theorem [ Malcolm ]( attention deficit disorder ) olcott <NoOne@NoWhere.com> - 2021-07-27 14:10 -0500
Re: André doesn't know Rice's Theorem [ Malcolm ]( attention deficit disorder ) Richard Damon <news.x.richarddamon@xoxy.net> - 2021-07-27 12:58 -0700
Re: André doesn't know Rice's Theorem [ Malcolm ]( attention deficit disorder ) Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-07-28 16:23 +0100
Re: André doesn't know Rice's Theorem [ Malcolm ]( attention deficit disorder ) olcott <NoOne@NoWhere.com> - 2021-07-28 11:01 -0500
Re: André doesn't know Rice's Theorem [ Malcolm ]( attention deficit disorder ) Richard Damon <news.x.richarddamon@xoxy.net> - 2021-07-28 09:25 -0700
Re: André doesn't know Rice's Theorem [ Malcolm ]( attention deficit disorder ) Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-07-28 21:38 +0100
Re: André doesn't know Rice's Theorem [ Malcolm ]( attention deficit disorder ) olcott <NoOne@NoWhere.com> - 2021-07-28 16:14 -0500
Re: André doesn't know Rice's Theorem [ Malcolm ]( attention deficit disorder ) olcott <NoOne@NoWhere.com> - 2021-07-28 16:20 -0500
Re: André doesn't know Rice's Theorem [ Malcolm ]( attention deficit disorder ) Richard Damon <news.x.richarddamon@xoxy.net> - 2021-07-28 15:04 -0700
Re: André doesn't know Rice's Theorem [ Malcolm ]( attention deficit disorder ) Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-07-29 00:33 +0100
Re: André doesn't know Rice's Theorem [ Malcolm ] André G. Isaak <agisaak@gm.invalid> - 2021-07-27 11:16 -0600
Re: André doesn't know Rice's Theorem [ Malcolm ] olcott <NoOne@NoWhere.com> - 2021-07-27 12:31 -0500
Re: André doesn't know Rice's Theorem [ Malcolm ] André G. Isaak <agisaak@gm.invalid> - 2021-07-27 13:42 -0600
Re: André doesn't know Rice's Theorem [ Malcolm ] olcott <NoOne@NoWhere.com> - 2021-07-27 17:20 -0500
Re: André doesn't know Rice's Theorem [ Malcolm ] olcott <NoOne@NoWhere.com> - 2021-07-27 22:11 -0500
Re: André doesn't know Rice's Theorem [ Malcolm ] André G. Isaak <agisaak@gm.invalid> - 2021-07-27 21:39 -0600
Re: André doesn't know Rice's Theorem [ Malcolm ] olcott <NoOne@NoWhere.com> - 2021-07-28 09:09 -0500
Re: André doesn't know Rice's Theorem [ Malcolm ] André G. Isaak <agisaak@gm.invalid> - 2021-07-28 09:31 -0600
Re: André doesn't know Rice's Theorem [ Malcolm ] olcott <NoOne@NoWhere.com> - 2021-07-28 11:38 -0500
Re: André doesn't know Rice's Theorem [ Malcolm ] Richard Damon <Richard@Damon-Family.org> - 2021-07-28 10:08 -0700
Re: André doesn't know Rice's Theorem [ Malcolm ] [ PSR Decider is fully operational ] olcott <NoOne@NoWhere.com> - 2021-07-28 13:35 -0500
Re: André doesn't know Rice's Theorem [ Malcolm ] [ PSR Decider is fully operational ] André G. Isaak <agisaak@gm.invalid> - 2021-07-28 12:47 -0600
Re: André doesn't know Rice's Theorem [ Malcolm ] [ PSR Decider is fully operational ] olcott <NoOne@NoWhere.com> - 2021-07-28 14:07 -0500
Re: André doesn't know Rice's Theorem [ Malcolm ] [ PSR Decider is fully operational ] Richard Damon <Richard@Damon-Family.org> - 2021-07-28 12:56 -0700
Re: André doesn't know Rice's Theorem [ Malcolm ] [ PSR Decider is fully operational ] André G. Isaak <agisaak@gm.invalid> - 2021-07-28 17:25 -0600
Re: André doesn't know Rice's Theorem [ Malcolm ] [ PSR Decider is fully operational ] olcott <NoOne@NoWhere.com> - 2021-07-28 22:25 -0500
Re: André doesn't know Rice's Theorem [ Malcolm ] [ PSR Decider is fully operational ] André G. Isaak <agisaak@gm.invalid> - 2021-07-28 21:36 -0600
Re: André doesn't know Rice's Theorem [ Malcolm ] [ PSR Decider is fully operational ] olcott <NoOne@NoWhere.com> - 2021-07-28 23:09 -0500
Re: André doesn't know Rice's Theorem [ Malcolm ] [ PSR Decider is fully operational ] Richard Damon <Richard@Damon-Family.org> - 2021-07-28 21:50 -0700
Re: André doesn't know Rice's Theorem [ Malcolm ] [ PSR Decider is fully operational ] olcott <NoOne@NoWhere.com> - 2021-07-28 23:57 -0500
Re: André doesn't know Rice's Theorem [ Malcolm ] [ PSR Decider is fully operational ] André G. Isaak <agisaak@gm.invalid> - 2021-07-28 23:10 -0600
Re: André doesn't know Rice's Theorem [ Malcolm ] [ PSR Decider is fully operational ] olcott <NoOne@NoWhere.com> - 2021-07-29 13:07 -0500
Re: André doesn't know Rice's Theorem [ Malcolm ] [ PSR Decider is fully operational ] Richard Damon <Richard@Damon-Family.org> - 2021-07-29 11:52 -0700
Re: André doesn't know Rice's Theorem [ Malcolm ] [ PSR Decider is fully operational ] André G. Isaak <agisaak@gm.invalid> - 2021-07-29 13:52 -0600
Re: André doesn't know Rice's Theorem [ Malcolm ] [ PSR Decider is fully operational ] Richard Damon <Richard@Damon-Family.org> - 2021-07-28 22:35 -0700
Re: André doesn't know Rice's Theorem [ Malcolm ] André G. Isaak <agisaak@gm.invalid> - 2021-07-28 12:40 -0600
Re: André doesn't know Rice's Theorem [ Malcolm ] [ self-contradiction must be treated differently ] olcott <NoOne@NoWhere.com> - 2021-07-28 15:06 -0500
Re: André doesn't know Rice's Theorem [ Malcolm ] [ self-contradiction must be treated differently ] Richard Damon <news.x.richarddamon@xoxy.net> - 2021-07-28 13:35 -0700
Re: André doesn't know Rice's Theorem [ Malcolm ] [ self-contradiction must be treated differently ] André G. Isaak <agisaak@gm.invalid> - 2021-07-28 17:36 -0600
Re: André doesn't know Rice's Theorem [ Malcolm ] [ self-contradiction must be treated differently ] olcott <NoOne@NoWhere.com> - 2021-07-28 22:51 -0500
Re: André doesn't know Rice's Theorem [ Malcolm ] [ self-contradiction must be treated differently ] Richard Damon <Richard@Damon-Family.org> - 2021-07-28 21:08 -0700
Re: André doesn't know Rice's Theorem [ Malcolm ] [ self-contradiction must be treated differently ] André G. Isaak <agisaak@gm.invalid> - 2021-07-28 22:15 -0600
Re: André doesn't know Rice's Theorem [ Malcolm ] [ self-contradiction must be treated differently ] olcott <NoOne@NoWhere.com> - 2021-07-28 23:31 -0500
Re: André doesn't know Rice's Theorem [ Malcolm ] [ self-contradiction must be treated differently ] André G. Isaak <agisaak@gm.invalid> - 2021-07-28 23:00 -0600
Re: André doesn't know Rice's Theorem [ Malcolm ] [ self-contradiction must be treated differently ] olcott <NoOne@NoWhere.com> - 2021-07-29 12:39 -0500
Re: André doesn't know Rice's Theorem [ Malcolm ] [ self-contradiction must be treated differently ] Richard Damon <Richard@Damon-Family.org> - 2021-07-29 12:15 -0700
Re: André doesn't know Rice's Theorem [ Malcolm ] [ self-contradiction must be treated differently ] André G. Isaak <agisaak@gm.invalid> - 2021-07-29 13:50 -0600
Re: André doesn't know Rice's Theorem [ Malcolm ] [ self-contradiction must be treated differently ] Richard Damon <Richard@Damon-Family.org> - 2021-07-28 22:18 -0700
Re: André doesn't know Rice's Theorem [ Malcolm ] [ Try and provide a counter-example ] olcott <NoOne@NoWhere.com> - 2021-07-29 13:15 -0500
Re: André doesn't know Rice's Theorem [ Malcolm ] [ Try and provide a counter-example ] Richard Damon <Richard@Damon-Family.org> - 2021-07-29 12:25 -0700
Re: André doesn't know Rice's Theorem [ Malcolm ] [ Try and provide a counter-example ] André G. Isaak <agisaak@gm.invalid> - 2021-07-29 13:55 -0600
Re: André doesn't know Rice's Theorem [ Malcolm ] [ Try and provide a counter-example ] olcott <NoOne@NoWhere.com> - 2021-07-29 17:50 -0500
Re: André doesn't know Rice's Theorem [ Malcolm ] [ Try and provide a counter-example ] André G. Isaak <agisaak@gm.invalid> - 2021-07-29 16:58 -0600
Re: André doesn't know Rice's Theorem [ Malcolm ] [ Try and provide a counter-example ] olcott <NoOne@NoWhere.com> - 2021-07-29 18:27 -0500
Re: André doesn't know Rice's Theorem [ Malcolm ] [ Try and provide a counter-example ] André G. Isaak <agisaak@gm.invalid> - 2021-07-29 18:25 -0600
Re: André doesn't know Rice's Theorem [ Malcolm ] [ Try and provide a counter-example ] olcott <NoOne@NoWhere.com> - 2021-07-29 19:54 -0500
Re: André doesn't know Rice's Theorem [ Malcolm ] [ Try and provide a counter-example ] Richard Damon <news.x.richarddamon@xoxy.net> - 2021-07-29 18:08 -0700
Re: André doesn't know Rice's Theorem [ Malcolm ] [ Try and provide a counter-example ] André G. Isaak <agisaak@gm.invalid> - 2021-07-29 19:25 -0600
Re: André doesn't know Rice's Theorem [ Malcolm ] [ Try and provide a counter-example ] olcott <NoOne@NoWhere.com> - 2021-07-29 23:34 -0500
Re: André doesn't know Rice's Theorem [ Malcolm ] [ Try and provide a counter-example ] Richard Damon <Richard@Damon-Family.org> - 2021-07-29 22:44 -0700
Re: André doesn't know Rice's Theorem [ Malcolm ] [ Try and provide a counter-example ] olcott <NoOne@NoWhere.com> - 2021-07-30 20:42 -0500
Re: André doesn't know Rice's Theorem [ Malcolm ] [ Try and provide a counter-example ] Richard Damon <Richard@Damon-Family.org> - 2021-07-30 18:57 -0700
Re: André doesn't know Rice's Theorem [ Malcolm ] [ Try and provide a counter-example ] olcott <NoOne@NoWhere.com> - 2021-07-30 21:08 -0500
Re: André doesn't know Rice's Theorem [ Malcolm ] [ Try and provide a counter-example ] Richard Damon <Richard@Damon-Family.org> - 2021-07-30 20:54 -0700
Re: André doesn't know Rice's Theorem [ Malcolm ] [ Try and provide a counter-example ] olcott <NoOne@NoWhere.com> - 2021-07-31 09:14 -0500
Re: André doesn't know Rice's Theorem [ Malcolm ] [ Try and provide a counter-example ] wij <wyniijj@gmail.com> - 2021-07-31 08:02 -0700
Re: André doesn't know Rice's Theorem [ Malcolm ] [ Try and provide a counter-example ] olcott <NoOne@NoWhere.com> - 2021-07-31 10:20 -0500
Re: André doesn't know Rice's Theorem [ Malcolm ] [ Try and provide a counter-example ] Richard Damon <Richard@Damon-Family.org> - 2021-07-31 08:41 -0700
Re: André doesn't know Rice's Theorem [ Malcolm ] [ Try and provide a counter-example ] olcott <NoOne@NoWhere.com> - 2021-07-31 12:00 -0500
Re: André doesn't know Rice's Theorem [ Malcolm ] [ Try and provide a counter-example ] Richard Damon <Richard@Damon-Family.org> - 2021-07-31 11:25 -0700
Re: André doesn't know Rice's Theorem [ Malcolm ] [ Try and provide a counter-example ] olcott <NoOne@NoWhere.com> - 2021-07-31 13:52 -0500
Re: André doesn't know Rice's Theorem [ Malcolm ] [ Try and provide a counter-example ] Richard Damon <Richard@Damon-Family.org> - 2021-07-31 12:14 -0700
Re: André doesn't know Rice's Theorem [ Malcolm ] [ Try and provide a counter-example ] olcott <NoOne@NoWhere.com> - 2021-07-31 14:41 -0500
Re: André doesn't know Rice's Theorem [ Malcolm ] [ Try and provide a counter-example ] Richard Damon <Richard@Damon-Family.org> - 2021-07-31 12:54 -0700
Re: André doesn't know Rice's Theorem [ Malcolm ] [ Try and provide a counter-example ] olcott <NoOne@NoWhere.com> - 2021-07-31 15:39 -0500
Re: André doesn't know Rice's Theorem [ Malcolm ] [ Try and provide a counter-example ] Richard Damon <Richard@Damon-Family.org> - 2021-07-31 15:11 -0700
Re: André doesn't know Rice's Theorem [ Malcolm ] [ Try and provide a counter-example ] Richard Damon <news.x.richarddamon@xoxy.net> - 2021-07-31 15:37 -0700
Re: André doesn't know Rice's Theorem [ Malcolm ] [ Try and provide a counter-example ] Richard Damon <Richard@Damon-Family.org> - 2021-07-31 08:26 -0700
Re: André doesn't know Rice's Theorem [ Malcolm ] [ Try and provide a counter-example ] olcott <NoOne@NoWhere.com> - 2021-07-31 11:35 -0500
Re: André doesn't know Rice's Theorem [ Malcolm ] [ Try and provide a counter-example ] Richard Damon <Richard@Damon-Family.org> - 2021-07-31 11:31 -0700
Re: André doesn't know Rice's Theorem [ Malcolm ] [ Try and provide a counter-example ] olcott <NoOne@NoWhere.com> - 2021-07-31 13:57 -0500
Re: André doesn't know Rice's Theorem [ Malcolm ] [ Try and provide a counter-example ] Richard Damon <Richard@Damon-Family.org> - 2021-07-31 12:23 -0700
Re: André doesn't know Rice's Theorem [ Malcolm ] [ Try and provide a counter-example ][ How can H ignore own behavior? ] olcott <NoOne@NoWhere.com> - 2021-07-31 14:52 -0500
Re: André doesn't know Rice's Theorem [ Malcolm ] [ Try and provide a counter-example ][ How can H ignore own behavior? ] Richard Damon <Richard@Damon-Family.org> - 2021-07-31 13:02 -0700
Re: André doesn't know Rice's Theorem [ Malcolm ] [ Try and provide a counter-example ][ How can H ignore own behavior? ] olcott <NoOne@NoWhere.com> - 2021-07-31 15:43 -0500
Re: André doesn't know Rice's Theorem [ Malcolm ] [ Try and provide a counter-example ][ How can H ignore own behavior? ] Richard Damon <Richard@Damon-Family.org> - 2021-07-31 15:18 -0700
Re: André doesn't know Rice's Theorem [ Malcolm ] [ Try and provide a counter-example ] André G. Isaak <agisaak@gm.invalid> - 2021-07-30 08:54 -0600
Re: André doesn't know Rice's Theorem [ Malcolm ] [ Try and provide a counter-example ] olcott <NoOne@NoWhere.com> - 2021-07-30 10:58 -0500
Re: André doesn't know Rice's Theorem [ Malcolm ] [ Try and provide a counter-example ] Richard Damon <Richard@Damon-Family.org> - 2021-07-30 13:23 -0700
Re: André doesn't know Rice's Theorem [ Malcolm ] [ Try and provide a counter-example ] Richard Damon <news.x.richarddamon@xoxy.net> - 2021-07-29 16:15 -0700
Re: André doesn't know Rice's Theorem [ Malcolm ] Richard Damon <Richard@Damon-Family.org> - 2021-07-28 09:34 -0700
Re: André doesn't know Rice's Theorem [ Malcolm ] Malcolm McLean <malcolm.arthur.mclean@gmail.com> - 2021-07-28 02:41 -0700
Re: André doesn't know Rice's Theorem [ Malcolm ] olcott <NoOne@NoWhere.com> - 2021-07-28 08:56 -0500
Re: André doesn't know Rice's Theorem [ Malcolm ] Richard Damon <Richard@Damon-Family.org> - 2021-07-28 09:37 -0700
Re: André doesn't know Rice's Theorem [ Malcolm ] Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-07-28 22:04 +0100
Re: André doesn't know Rice's Theorem [ Malcolm ] olcott <NoOne@NoWhere.com> - 2021-07-28 16:22 -0500
Re: André doesn't know Rice's Theorem [ Malcolm ] Richard Damon <news.x.richarddamon@xoxy.net> - 2021-07-28 15:06 -0700
Re: André doesn't know Rice's Theorem [ Malcolm ] Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-07-28 21:54 +0100
Re: André doesn't know Rice's Theorem [ Malcolm ] Jeff Barnett <jbb@notatt.com> - 2021-07-27 11:21 -0600
Re: Black box halt decider is NOT a partial decider [ André doesn't know Rice's Theorem ] Richard Damon <Richard@Damon-Family.org> - 2021-07-26 21:17 -0700
Re: Black box halt decider is NOT a partial decider [ André doesn't know Rice's Theorem ] Richard Damon <Richard@Damon-Family.org> - 2021-07-26 20:25 -0700
Re: Black box halt decider is NOT a partial decider [ H refutes Rice's Theorem ] Richard Damon <Richard@Damon-Family.org> - 2021-07-26 19:36 -0700
Re: Black box halt decider is NOT a partial decider [ H refutes Rice's Theorem ] Richard Damon <Richard@Damon-Family.org> - 2021-07-26 18:03 -0700
Re: Black box halt decider is NOT a partial decider Mike Terry <news.dead.person.stones@darjeeling.plus.com> - 2021-07-25 21:28 +0100
Re: Black box halt decider is NOT a partial decider Mike Terry <news.dead.person.stones@darjeeling.plus.com> - 2021-07-25 21:46 +0100
Re: Black box halt decider is NOT a partial decider Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-07-25 23:42 +0100
Re: Black box halt decider is NOT a partial decider Mike Terry <news.dead.person.stones@darjeeling.plus.com> - 2021-07-26 01:08 +0100
Re: Black box halt decider is NOT a partial decider Richard Damon <Richard@Damon-Family.org> - 2021-07-25 18:20 -0700
Re: Black box halt decider is NOT a partial decider [ H(P,P)==0 is correct ] olcott <NoOne@NoWhere.com> - 2021-07-26 09:32 -0500
Re: Black box halt decider is NOT a partial decider [ H(P,P)==0 is correct ] Richard Damon <Richard@Damon-Family.org> - 2021-07-26 07:57 -0700
Re: Black box halt decider is NOT a partial decider [ H(P,P)==0 is correct ] André G. Isaak <agisaak@gm.invalid> - 2021-07-26 09:57 -0600
Re: Black box halt decider is NOT a partial decider [ H(P,P)==0 is correct ] Mike Terry <news.dead.person.stones@darjeeling.plus.com> - 2021-07-27 02:17 +0100
Re: Black box halt decider is NOT a partial decider [ H(P,P)==0 is correct ] olcott <NoOne@NoWhere.com> - 2021-07-26 20:41 -0500
Re: Black box halt decider is NOT a partial decider [ H(P,P)==0 is correct ] Richard Damon <Richard@Damon-Family.org> - 2021-07-26 19:57 -0700
Re: Black box halt decider is NOT a partial decider [ H(P,P)==0 is correct ] olcott <NoOne@NoWhere.com> - 2021-07-26 09:38 -0500
Re: Black box halt decider is NOT a partial decider [ H(P,P)==0 is correct ] Richard Damon <Richard@Damon-Family.org> - 2021-07-26 08:03 -0700
Re: Black box halt decider is NOT a partial decider [ H(P,P)==0 is correct ] Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-07-27 00:48 +0100
Re: Black box halt decider is NOT a partial decider [ H(P,P)==0 is correct ] olcott <NoOne@NoWhere.com> - 2021-07-26 20:06 -0500
Re: Black box halt decider is NOT a partial decider [ H(P,P)==0 is correct ] Richard Damon <Richard@Damon-Family.org> - 2021-07-26 19:40 -0700
Re: Black box halt decider is NOT a partial decider [ H(P,P)==0 is correct ] Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-07-28 22:44 +0100
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] olcott <NoOne@NoWhere.com> - 2021-07-28 17:08 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] Richard Damon <Richard@Damon-Family.org> - 2021-07-28 15:22 -0700
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] olcott <NoOne@NoWhere.com> - 2021-07-28 18:21 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] Richard Damon <Richard@Damon-Family.org> - 2021-07-28 20:52 -0700
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-07-29 00:22 +0100
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] olcott <NoOne@NoWhere.com> - 2021-07-28 18:35 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-07-29 01:58 +0100
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] olcott <NoOne@NoWhere.com> - 2021-07-28 20:54 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] Richard Damon <Richard@Damon-Family.org> - 2021-07-28 20:56 -0700
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-07-30 01:30 +0100
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] olcott <NoOne@NoWhere.com> - 2021-07-29 20:00 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] Richard Damon <news.x.richarddamon@xoxy.net> - 2021-07-29 18:11 -0700
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-07-30 02:52 +0100
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] olcott <NoOne@NoWhere.com> - 2021-07-29 21:08 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-07-30 12:39 +0100
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] olcott <NoOne@NoWhere.com> - 2021-07-30 09:38 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-07-30 20:30 +0100
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] olcott <NoOne@NoWhere.com> - 2021-07-29 21:28 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] Richard Damon <Richard@Damon-Family.org> - 2021-07-29 19:38 -0700
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-07-30 13:39 +0100
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] olcott <NoOne@NoWhere.com> - 2021-07-30 09:54 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-07-30 20:58 +0100
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ] olcott <NoOne@NoWhere.com> - 2021-07-30 20:16 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ] Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-07-31 23:08 +0100
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ] olcott <NoOne@NoWhere.com> - 2021-07-31 21:20 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ] Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-01 11:54 +0100
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ] Malcolm McLean <malcolm.arthur.mclean@gmail.com> - 2021-08-01 05:12 -0700
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ] Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-01 13:41 +0100
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ] Malcolm McLean <malcolm.arthur.mclean@gmail.com> - 2021-08-01 07:25 -0700
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ] Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-01 16:30 +0100
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ] Malcolm McLean <malcolm.arthur.mclean@gmail.com> - 2021-08-01 11:41 -0700
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ] Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-01 20:26 +0100
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ] olcott <NoOne@NoWhere.com> - 2021-08-01 14:45 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ] Richard Damon <Richard@Damon-Family.org> - 2021-08-01 13:28 -0700
Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn [ succinct ] olcott <NoOne@NoWhere.com> - 2021-08-01 11:02 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ][ GIGO ] olcott <NoOne@NoWhere.com> - 2021-08-01 10:02 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ][ GIGO ] Richard Damon <Richard@Damon-Family.org> - 2021-08-01 08:21 -0700
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ][ GIGO ] Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-01 17:00 +0100
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ][ GIGO ] olcott <NoOne@NoWhere.com> - 2021-08-04 10:48 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ][ GIGO ] Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-04 19:51 +0100
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ][ GIGO ] olcott <NoOne@NoWhere.com> - 2021-08-04 17:31 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ][ GIGO ] Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-05 00:23 +0100
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ][ GIGO ] olcott <NoOne@NoWhere.com> - 2021-08-04 22:33 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ][ GIGO ] Richard Damon <Richard@Damon-Family.org> - 2021-08-04 22:56 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ][ GIGO ] Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-05 23:12 +0100
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ][ GIGO ] olcott <NoOne@NoWhere.com> - 2021-08-05 20:17 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ][ GIGO ] Richard Damon <Richard@Damon-Family.org> - 2021-08-05 20:30 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ][ GIGO ] Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-06 03:36 +0100
Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. olcott <NoOne@NoWhere.com> - 2021-08-05 21:50 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-08 01:34 +0100
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ][ GIGO ] Richard Damon <Richard@Damon-Family.org> - 2021-08-04 19:05 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ] olcott <NoOne@NoWhere.com> - 2021-08-01 09:45 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ] Richard Damon <Richard@Damon-Family.org> - 2021-08-01 08:24 -0700
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ] olcott <NoOne@NoWhere.com> - 2021-08-01 22:45 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ] Richard Damon <Richard@Damon-Family.org> - 2021-08-01 22:12 -0700
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ] Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-02 20:10 +0100
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ] olcott <NoOne@NoWhere.com> - 2021-08-02 15:53 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ] Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-03 01:11 +0100
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ] olcott <NoOne@NoWhere.com> - 2021-08-02 19:55 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ] Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-03 02:45 +0100
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ] olcott <NoOne@NoWhere.com> - 2021-08-02 21:11 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ] Richard Damon <Richard@Damon-Family.org> - 2021-08-02 21:57 -0700
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ] Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-04 13:53 +0100
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ] olcott <NoOne@NoWhere.com> - 2021-08-04 11:15 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ] Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-04 20:22 +0100
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ] olcott <NoOne@NoWhere.com> - 2021-08-04 17:38 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ] Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-05 00:22 +0100
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ] olcott <NoOne@NoWhere.com> - 2021-08-04 22:18 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ] Richard Damon <Richard@Damon-Family.org> - 2021-08-04 23:05 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ] Malcolm McLean <malcolm.arthur.mclean@gmail.com> - 2021-08-05 02:02 -0700
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ] olcott <NoOne@NoWhere.com> - 2021-08-05 07:07 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ] Richard Damon <Richard@Damon-Family.org> - 2021-08-05 20:35 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ] Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-05 23:15 +0100
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ] olcott <NoOne@NoWhere.com> - 2021-08-05 20:48 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ] Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-06 03:35 +0100
Page 6 conclusively proves that H(P,P)==0 is correct. olcott <NoOne@NoWhere.com> - 2021-08-05 21:46 -0500
Re: Page 6 conclusively proves that H(P,P)==0 is correct. Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-08 01:38 +0100
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ] Richard Damon <Richard@Damon-Family.org> - 2021-08-05 22:01 -0500
Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. olcott <NoOne@NoWhere.com> - 2021-08-05 22:13 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. Richard Damon <Richard@Damon-Family.org> - 2021-08-05 22:29 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ] Richard Damon <Richard@Damon-Family.org> - 2021-08-04 20:21 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ Only Inputs Count ] olcott <NoOne@NoWhere.com> - 2021-08-03 22:23 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ Only Inputs Count ] Richard Damon <Richard@Damon-Family.org> - 2021-08-03 21:44 -0600
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ Only Inputs Count ] André G. Isaak <agisaak@gm.invalid> - 2021-08-03 21:56 -0600
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ Only Inputs Count ] olcott <NoOne@NoWhere.com> - 2021-08-03 23:00 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ Only Inputs Count ] wij <wyniijj@gmail.com> - 2021-08-03 21:12 -0700
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ Only Inputs Count ] André G. Isaak <agisaak@gm.invalid> - 2021-08-03 22:16 -0600
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ Only Inputs Count ] olcott <NoOne@NoWhere.com> - 2021-08-03 23:25 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ Only Inputs Count ] André G. Isaak <agisaak@gm.invalid> - 2021-08-03 22:36 -0600
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ Only Inputs Count ] olcott <NoOne@NoWhere.com> - 2021-08-03 23:38 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ Only Inputs Count ] olcott <NoOne@NoWhere.com> - 2021-08-03 23:55 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ Only Inputs Count ] André G. Isaak <agisaak@gm.invalid> - 2021-08-03 23:36 -0600
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ Only Inputs Count ] olcott <NoOne@NoWhere.com> - 2021-08-04 10:14 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ Only Inputs Count ] Richard Damon <Richard@Damon-Family.org> - 2021-08-04 21:05 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ Only Inputs Count ] Malcolm McLean <malcolm.arthur.mclean@gmail.com> - 2021-08-04 07:13 -0700
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ Only Inputs Count ]( Honest Dialogue ) olcott <NoOne@NoWhere.com> - 2021-08-04 10:11 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ Only Inputs Count ] Richard Damon <Richard@Damon-Family.org> - 2021-08-04 20:29 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ Only Inputs Count ] Richard Damon <Richard@Damon-Family.org> - 2021-08-03 22:35 -0600
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ Only Inputs Count ] Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-04 19:37 +0100
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ Only Inputs Count ] olcott <NoOne@NoWhere.com> - 2021-08-04 15:37 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ Only Inputs Count ] Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-04 23:23 +0100
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ Only Inputs Count ] olcott <NoOne@NoWhere.com> - 2021-08-04 22:37 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ Only Inputs Count ] Richard Damon <Richard@Damon-Family.org> - 2021-08-04 22:48 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ Only Inputs Count ] Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-05 23:14 +0100
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ Only Inputs Count ] olcott <NoOne@NoWhere.com> - 2021-08-05 20:21 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ Only Inputs Count ] Richard Damon <Richard@Damon-Family.org> - 2021-08-05 20:41 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ Only Inputs Count ] Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-06 03:36 +0100
Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. olcott <NoOne@NoWhere.com> - 2021-08-05 21:54 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. Richard Damon <Richard@Damon-Family.org> - 2021-08-05 22:37 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. olcott <NoOne@NoWhere.com> - 2021-08-05 22:44 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. Richard Damon <news.x.richarddamon@xoxy.net> - 2021-08-05 22:51 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-08 01:34 +0100
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. olcott <NoOne@NoWhere.com> - 2021-08-09 17:32 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. Richard Damon <Richard@Damon-Family.org> - 2021-08-09 21:14 -0400
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-11 01:42 +0100
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. olcott <NoOne@NoWhere.com> - 2021-08-10 19:46 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. olcott <NoOne@NoWhere.com> - 2021-08-10 20:06 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-11 02:41 +0100
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. olcott <NoOne@NoWhere.com> - 2021-08-10 20:53 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-11 03:26 +0100
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. olcott <NoOne@NoWhere.com> - 2021-08-10 21:40 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-11 16:04 +0100
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. olcott <NoOne@NoWhere.com> - 2021-08-11 10:10 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. olcott <NoOne@NoWhere.com> - 2021-08-11 10:15 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-12 00:04 +0100
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. olcott <NoOne@NoWhere.com> - 2021-08-11 18:16 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-12 02:20 +0100
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. olcott <NoOne@NoWhere.com> - 2021-08-11 21:03 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-12 21:09 +0100
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. [ Ben's key param agreement ] olcott <NoOne@NoWhere.com> - 2021-08-11 21:08 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. Jeff Barnett <jbb@notatt.com> - 2021-08-11 17:32 -0600
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. olcott <NoOne@NoWhere.com> - 2021-08-11 18:40 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. Jeff Barnett <jbb@notatt.com> - 2021-08-11 23:11 -0600
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. Malcolm McLean <malcolm.arthur.mclean@gmail.com> - 2021-08-12 01:36 -0700
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. olcott <NoOne@NoWhere.com> - 2021-08-12 07:24 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. Malcolm McLean <malcolm.arthur.mclean@gmail.com> - 2021-08-12 08:40 -0700
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. olcott <NoOne@NoWhere.com> - 2021-08-12 10:50 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. Malcolm McLean <malcolm.arthur.mclean@gmail.com> - 2021-08-13 01:58 -0700
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. olcott <NoOne@NoWhere.com> - 2021-08-13 08:30 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. Richard Damon <Richard@Damon-Family.org> - 2021-08-12 22:01 -0400
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-12 16:15 +0100
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. olcott <NoOne@NoWhere.com> - 2021-08-12 10:29 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. (fixed type) olcott <NoOne@NoWhere.com> - 2021-08-10 21:42 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. // fixed typo (link added) olcott <NoOne@NoWhere.com> - 2021-08-10 23:36 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. [ Is Ben a Liar or simply woefully ignorant? ] olcott <NoOne@NoWhere.com> - 2021-08-11 09:28 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. [ Is Ben a Liar or simply woefully ignorant? ] olcott <NoOne@NoWhere.com> - 2021-08-11 09:58 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. [ Is Ben a Liar or simply woefully ignorant? ] Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-11 17:10 +0100
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. [ Is Ben a Liar or simply woefully ignorant? ] olcott <NoOne@NoWhere.com> - 2021-08-11 11:52 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. [ Is Ben a Liar or simply woefully ignorant? ] Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-12 01:35 +0100
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. [ Ben accepts one point? ] olcott <NoOne@NoWhere.com> - 2021-08-11 19:40 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. [ Ben accepts one point? ] (typo fixed ) olcott <NoOne@NoWhere.com> - 2021-08-11 19:44 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. [ Ben accepts one point? ] (typo fixed ) Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-12 21:00 +0100
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. [ Ben accepts one point? ] (typo fixed ) olcott <NoOne@NoWhere.com> - 2021-08-12 15:36 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. [ Ben accepts one point? ] (typo fixed ) Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-12 22:10 +0100
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. [ Ben accepts one point? ] (typo fixed ) olcott <NoOne@NoWhere.com> - 2021-08-12 16:26 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. [ Ben accepts one point? ] (typo fixed ) Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-13 00:00 +0100
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. [ Ben accepts one point? ] (typo fixed ) olcott <NoOne@NoWhere.com> - 2021-08-12 18:28 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. [ Ben accepts one point? ] (another typo fixed ) olcott <NoOne@NoWhere.com> - 2021-08-12 18:33 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. [ Ben accepts one point? ] (another typo fixed ) Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-13 01:26 +0100
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. [ Ben accepts one point? ] (another typo fixed ) olcott <NoOne@NoWhere.com> - 2021-08-12 19:49 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. [ Ben accepts one point? ] (another typo fixed ) Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-13 02:05 +0100
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. [ Ben accepts one point? ] (another typo fixed ) olcott <NoOne@NoWhere.com> - 2021-08-12 20:19 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. [ Ben accepts one point? ] (another typo fixed ) Richard Damon <Richard@Damon-Family.org> - 2021-08-12 21:44 -0400
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. [ Ben accepts one point? ] (another typo fixed ) Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-13 02:49 +0100
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. [ Ben accepts one point? ] (another typo fixed ) olcott <NoOne@NoWhere.com> - 2021-08-12 21:20 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. [ Ben accepts one point? ] (another typo fixed ) Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-13 10:01 +0100
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. [ Ben accepts one point? ] (another typo fixed ) olcott <NoOne@NoWhere.com> - 2021-08-13 08:35 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. [ Ben accepts one point? ] (another typo fixed ) Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-13 21:20 +0100
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. [ Ben accepts one point? ] (another typo fixed ) olcott <NoOne@NoWhere.com> - 2021-08-13 15:56 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. [ Ben accepts one point? ] (another typo fixed ) Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-13 22:28 +0100
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. [ Ben accepts one point? ] (another typo fixed ) olcott <NoOne@NoWhere.com> - 2021-08-13 16:33 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. [ Ben accepts one point? ] (another typo fixed ) Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-13 23:06 +0100
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. [ Ben accepts one point? ] (another typo fixed ) olcott <NoOne@NoWhere.com> - 2021-08-13 17:12 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. [ Ben accepts one point? ] (another typo fixed ) Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-13 23:25 +0100
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. [ Ben accepts one point? ] (another typo fixed ) olcott <NoOne@NoWhere.com> - 2021-08-13 17:47 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. "dklei...@gmail.com" <dkleinecke@gmail.com> - 2021-08-13 16:54 -0700
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. olcott <NoOne@NoWhere.com> - 2021-08-13 22:35 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. olcott <NoOne@NoWhere.com> - 2021-08-14 13:22 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. [ Ben accepts one point? ] (another typo fixed ) Richard Damon <Richard@Damon-Family.org> - 2021-08-13 20:41 -0400
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. [ Ben accepts one point? ] (another typo fixed ) olcott <NoOne@NoWhere.com> - 2021-08-13 17:24 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. [ Ben accepts one point? ] (typo fixed ) Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-13 01:53 +0100
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. [ Ben accepts one point? ] (typo fixed ) olcott <NoOne@NoWhere.com> - 2021-08-12 20:14 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. [ Ben accepts one point? ] (typo fixed ) Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-13 02:51 +0100
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. [ Ben accepts one point? ] (typo fixed ) olcott <NoOne@NoWhere.com> - 2021-08-12 21:21 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. [ Ben accepts one point? ] (typo fixed ) Richard Damon <Richard@Damon-Family.org> - 2021-08-12 22:57 -0400
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. [ Ben accepts one point? ] (typo fixed ) Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-13 09:53 +0100
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. [ Ben accepts one point? ] (typo fixed ) olcott <NoOne@NoWhere.com> - 2021-08-13 08:31 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. [ Ben accepts one point? ] (typo fixed ) Richard Damon <Richard@Damon-Family.org> - 2021-08-12 21:38 -0400
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. [ Ben accepts one point? ] (typo fixed ) Richard Damon <Richard@Damon-Family.org> - 2021-08-12 22:09 -0400
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. [ Is Ben a Liar or simply woefully ignorant? ] olcott <NoOne@NoWhere.com> - 2021-08-11 14:53 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. [ Is Ben a Liar or simply woefully ignorant? ] Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-12 01:01 +0100
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. [ Is Ben a Liar or simply woefully ignorant? ] olcott <NoOne@NoWhere.com> - 2021-08-11 19:26 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. [ Is Ben a Liar or simply woefully ignorant? ] Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-12 02:28 +0100
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. olcott <NoOne@NoWhere.com> - 2021-08-11 18:07 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-12 02:35 +0100
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. [ Halting Problem is solved for Ĥ on ⟨Ĥ⟩ ] olcott <NoOne@NoWhere.com> - 2021-08-11 21:14 -0500
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. [ Is Ben a Liar or simply woefully ignorant? ] Richard Damon <Richard@Damon-Family.org> - 2021-08-12 07:49 -0400
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. Malcolm McLean <malcolm.arthur.mclean@gmail.com> - 2021-08-10 23:40 -0700
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-11 11:48 +0100
Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. Malcolm McLean <malcolm.arthur.mclean@gmail.com> - 2021-08-11 04:09 -0700
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ] olcott <NoOne@NoWhere.com> - 2021-08-01 22:56 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ] Richard Damon <Richard@Damon-Family.org> - 2021-08-01 22:13 -0700
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ] Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-02 20:11 +0100
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ] Richard Damon <Richard@Damon-Family.org> - 2021-08-04 20:38 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ succinct ] Richard Damon <news.x.richarddamon@xoxy.net> - 2021-07-31 15:47 -0700
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? ) olcott <NoOne@NoWhere.com> - 2021-07-28 21:52 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? ) Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-07-30 02:18 +0100
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? ) olcott <NoOne@NoWhere.com> - 2021-07-29 21:05 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? ) Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-07-30 12:00 +0100
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? ) olcott <NoOne@NoWhere.com> - 2021-07-30 09:35 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? ) Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-07-30 20:22 +0100
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? ) olcott <NoOne@NoWhere.com> - 2021-07-30 19:42 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? ) Richard Damon <news.x.richarddamon@xoxy.net> - 2021-07-30 18:27 -0700
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? ) Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-07-31 22:54 +0100
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? ) olcott <NoOne@NoWhere.com> - 2021-07-31 16:57 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? ) Richard Damon <news.x.richarddamon@xoxy.net> - 2021-07-31 15:48 -0700
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? ) Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-01 11:39 +0100
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? ) olcott <NoOne@NoWhere.com> - 2021-08-01 22:17 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? ) Richard Damon <Richard@Damon-Family.org> - 2021-08-01 20:36 -0700
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? ) Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-02 17:31 +0100
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? ) olcott <NoOne@NoWhere.com> - 2021-08-02 13:16 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? ) olcott <NoOne@NoWhere.com> - 2021-08-02 13:25 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? ) Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-03 01:20 +0100
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? ) olcott <NoOne@NoWhere.com> - 2021-08-02 20:01 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? ) Richard Damon <Richard@Damon-Family.org> - 2021-08-02 22:03 -0700
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? ) Malcolm McLean <malcolm.arthur.mclean@gmail.com> - 2021-08-02 22:29 -0700
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? ) olcott <NoOne@NoWhere.com> - 2021-08-03 08:00 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? ) Malcolm McLean <malcolm.arthur.mclean@gmail.com> - 2021-08-03 07:33 -0700
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? ) olcott <NoOne@NoWhere.com> - 2021-08-03 10:21 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? ) André G. Isaak <agisaak@gm.invalid> - 2021-08-03 11:11 -0600
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? ) olcott <NoOne@NoWhere.com> - 2021-08-03 14:26 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? ) André G. Isaak <agisaak@gm.invalid> - 2021-08-03 14:08 -0600
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? ) olcott <NoOne@NoWhere.com> - 2021-08-03 15:47 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? ) André G. Isaak <agisaak@gm.invalid> - 2021-08-03 14:56 -0600
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? ) olcott <NoOne@NoWhere.com> - 2021-08-03 16:03 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? ) André G. Isaak <agisaak@gm.invalid> - 2021-08-03 15:26 -0600
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? ) olcott <NoOne@NoWhere.com> - 2021-08-03 16:50 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? ) André G. Isaak <agisaak@gm.invalid> - 2021-08-03 16:35 -0600
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? ) olcott <NoOne@NoWhere.com> - 2021-08-03 19:42 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? ) André G. Isaak <agisaak@gm.invalid> - 2021-08-03 19:00 -0600
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? ) olcott <NoOne@NoWhere.com> - 2021-08-03 20:24 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? ) André G. Isaak <agisaak@gm.invalid> - 2021-08-03 21:00 -0600
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? ) olcott <NoOne@NoWhere.com> - 2021-08-03 22:30 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? ) André G. Isaak <agisaak@gm.invalid> - 2021-08-03 22:00 -0600
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? ) olcott <NoOne@NoWhere.com> - 2021-08-03 23:03 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? ) Richard Damon <Richard@Damon-Family.org> - 2021-08-03 22:08 -0600
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? ) Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-08-04 10:48 +0100
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? ) Richard Damon <Richard@Damon-Family.org> - 2021-08-03 21:52 -0600
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? )[ Only: H(P,P)==0 ] olcott <NoOne@NoWhere.com> - 2021-08-04 09:38 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? )[ Only: H(P,P)==0 ] Richard Damon <Richard@Damon-Family.org> - 2021-08-04 20:43 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? )[ Only: H(P,P)==0 ][ André refuses an honest dialogue ] olcott <NoOne@NoWhere.com> - 2021-08-05 09:04 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? )[ Only: H(P,P)==0 ][ André refuses an honest dialogue ] Richard Damon <Richard@Damon-Family.org> - 2021-08-05 20:41 -0500
H(P,P)==0 is proven to be correct [ André refuses an honest dialogue ] olcott <NoOne@NoWhere.com> - 2021-08-05 09:07 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? ) Richard Damon <Richard@Damon-Family.org> - 2021-08-03 07:36 -0700
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? ) Andy Walker <anw@cuboid.co.uk> - 2021-07-31 23:53 +0100
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? ) olcott <NoOne@NoWhere.com> - 2021-07-31 21:47 -0500
Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] ( Are you game ? ) Richard Damon <Richard@Damon-Family.org> - 2021-07-31 20:07 -0700
Re: Black box halt decider is NOT a partial decider [ H(P,P)==0 is correct ] olcott <NoOne@NoWhere.com> - 2021-07-26 09:46 -0500
Re: Black box halt decider is NOT a partial decider [ H(P,P)==0 is correct ] Richard Damon <Richard@Damon-Family.org> - 2021-07-26 08:05 -0700
Re: Black box halt decider is NOT a partial decider Andy Walker <anw@cuboid.co.uk> - 2021-07-25 21:32 +0100
Re: Black box halt decider is NOT a partial decider Mike Terry <news.dead.person.stones@darjeeling.plus.com> - 2021-07-25 15:10 +0100
Re: Black box halt decider is NOT a partial decider Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-07-25 15:26 +0100
Re: Black box halt decider is NOT a partial decider Andy Walker <anw@cuboid.co.uk> - 2021-07-25 16:56 +0100
Re: Black box halt decider is NOT a partial decider Mike Terry <news.dead.person.stones@darjeeling.plus.com> - 2021-07-25 23:21 +0100
Re: Black box halt decider is NOT a partial decider Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-07-25 23:44 +0100
Re: Black box halt decider is NOT a partial decider Mike Terry <news.dead.person.stones@darjeeling.plus.com> - 2021-07-25 17:18 +0100
Re: Black box halt decider is NOT a partial decider Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-07-25 19:15 +0100
Re: Black box halt decider is NOT a partial decider Mike Terry <news.dead.person.stones@darjeeling.plus.com> - 2021-07-25 23:04 +0100
Re: Black box halt decider is NOT a partial decider Alan Mackenzie <acm@muc.de> - 2021-07-26 11:06 +0000
Re: Black box halt decider is NOT a partial decider Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-07-26 14:17 +0100
Re: Black box halt decider is NOT a partial decider Malcolm McLean <malcolm.arthur.mclean@gmail.com> - 2021-07-26 06:29 -0700
Re: Black box halt decider is NOT a partial decider Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-07-26 14:32 +0100
Re: Black box halt decider is NOT a partial decider Malcolm McLean <malcolm.arthur.mclean@gmail.com> - 2021-07-26 07:08 -0700
Re: Black box halt decider is NOT a partial decider Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-07-26 15:36 +0100
Re: Black box halt decider is NOT a partial decider Malcolm McLean <malcolm.arthur.mclean@gmail.com> - 2021-07-26 08:32 -0700
Re: Black box halt decider is NOT a partial decider Andy Walker <anw@cuboid.co.uk> - 2021-07-26 18:08 +0100
Re: Black box halt decider is NOT a partial decider Jeff Barnett <jbb@notatt.com> - 2021-07-26 11:38 -0600
Re: Black box halt decider is NOT a partial decider Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-07-26 19:31 +0100
Re: Black box halt decider is NOT a partial decider Jeff Barnett <jbb@notatt.com> - 2021-07-26 13:42 -0600
Re: Black box halt decider is NOT a partial decider Peter <peterxpercival@hotmail.com> - 2021-07-26 22:49 +0100
Re: Black box halt decider is NOT a partial decider Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-07-26 23:57 +0100
Re: Black box halt decider is NOT a partial decider Peter <peterxpercival@hotmail.com> - 2021-07-27 13:47 +0100
Re: Black box halt decider is NOT a partial decider Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-07-26 23:16 +0100
Re: Black box halt decider is NOT a partial decider Andy Walker <anw@cuboid.co.uk> - 2021-07-27 12:10 +0100
Re: Black box halt decider is NOT a partial decider Jeff Barnett <jbb@notatt.com> - 2021-07-27 12:48 -0600
Re: Black box halt decider is NOT a partial decider Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-07-28 17:25 +0100
Re: Black box halt decider is NOT a partial decider Jeff Barnett <jbb@notatt.com> - 2021-07-28 11:32 -0600
Re: Black box halt decider is NOT a partial decider Peter <peterxpercival@hotmail.com> - 2021-07-26 15:13 +0100
Re: Black box halt decider is NOT a partial decider wij <wyniijj@gmail.com> - 2021-07-24 20:35 -0700
Re: Black box halt decider is NOT a partial decider Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-07-25 10:54 +0100
Re: Black box halt decider is NOT a partial decider wij <wyniijj@gmail.com> - 2021-07-25 07:10 -0700
Re: Black box halt decider is NOT a partial decider "Chris M. Thomasson" <chris.m.thomasson.1@gmail.com> - 2021-07-25 12:56 -0700
Re: Black box halt decider is NOT a partial decider Richard Damon <Richard@Damon-Family.org> - 2021-07-22 14:52 -0700
Re: Black box halt decider is NOT a partial decider "Chris M. Thomasson" <chris.m.thomasson.1@gmail.com> - 2021-07-23 14:20 -0700
Re: Black box halt decider is NOT a partial decider Richard Damon <Richard@Damon-Family.org> - 2021-07-23 14:34 -0700
Re: Black box halt decider is NOT a partial decider Malcolm McLean <malcolm.arthur.mclean@gmail.com> - 2021-07-21 05:46 -0700
Re: Black box halt decider is NOT a partial decider Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-07-21 14:12 +0100
Re: Black box halt decider is NOT a partial decider Malcolm McLean <malcolm.arthur.mclean@gmail.com> - 2021-07-21 06:27 -0700
Re: Black box halt decider is NOT a partial decider Ben Bacarisse <ben.usenet@bsb.me.uk> - 2021-07-21 16:28 +0100
Re: Black box halt decider is NOT a partial decider Jeff Barnett <jbb@notatt.com> - 2021-07-20 15:14 -0600
Re: Black box halt decider is NOT a partial decider "Chris M. Thomasson" <chris.m.thomasson.1@gmail.com> - 2021-07-20 14:17 -0700
Page 17 of 27 — ← Prev page 1 … 15 16 [17] 18 19 … 27 Next page →
| From | Richard Damon <Richard@Damon-Family.org> |
|---|---|
| Date | 2021-08-04 20:29 -0500 |
| Subject | Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ Only Inputs Count ] |
| Message-ID | <faHOI.605$6p.291@fx36.iad> |
| In reply to | #37584 |
On 8/3/21 10:55 PM, olcott wrote: > I am not willing to talk about anything besides page 6 until we have > mutual agreement on page 6. > > https://www.researchgate.net/publication/351947980_Halting_problem_undecidability_and_infinitely_nested_simulation Errors in first Paragraph. Because H acts like a pure simulator JSUT until it decides and then (if it decides non-halting) aborts its simulation means that it NOT a pure simulator, PERIOD. DEFINITION: A Pure simulator is one that will accurate simulate the machie until it reaches its final halting state. (A Pure simulator of a non-hating computation is non-halting). A given instance of H may not affect the copy of the machine it is simuulating, but it DOES affect the machine it is part of, so H MUST take that into account when simulating another copy of itself. To omit that is to miss some of the behavior of the machine it is simulating and thus is unsound. THe replacement of a simulation of a simulator with the simulation of the machihe it is simulating only is valid if you have a REALLY PURE simulator, it does NOT apply if the simulator can ever abort its simulation, thus the transformation being done is invalid. Please provide what youy disagree about this, and PROOF that what I say is wrong. FAIR WARNING. These error invalidate the whole rest of your paper
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| From | Richard Damon <Richard@Damon-Family.org> |
|---|---|
| Date | 2021-08-03 22:35 -0600 |
| Subject | Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ Only Inputs Count ] |
| Message-ID | <uOoOI.1060$Fx8.30@fx45.iad> |
| In reply to | #37574 |
On 8/3/21 9:00 PM, olcott wrote: > On 8/3/2021 10:56 PM, André G. Isaak wrote: >> On 2021-08-03 21:23, olcott wrote: >> >>> The key point is that only the input to the halt decider is within >>> the scope of the halting problem. >>> >>> As long as the halt decider correctly decides its input what these >>> same programs do what they are not inputs to the halt decider make no >>> difference to the actual halting problem. >> >> You have this completely back-assward. >> >> How the TM described by the input to a halt decider behaves when they >> are run as *independent* computations (i.e. not as inputs to the halt >> decider) is the question a halt decider is supposed to answer by the >> very definition of a 'halt decider'. If the answer provided by the >> decider does not match the behavior of the *independent* computation, >> then that answer is wrong. >> >> Talking about how the description behaves "as an input" isn't even >> coherent. Inputs don't behave like anything. They are just data. >> >> André >> > > In computability theory, the halting problem is the > problem of determining, > > from a description of an arbitrary computer program and an input, > from a description of an arbitrary computer program and an input, > from a description of an arbitrary computer program and an input, > from a description of an arbitrary computer program and an input, > > whether the program will > finish running, or continue to run forever. > https://en.wikipedia.org/wiki/Halting_problem > > I have proved that the input to H(P,P) never halts whether or not it is > aborted by H, are you going to have an honest dialogue about the steps > of the proof or not? > > You just don't understand thw words do you. H is given on its tape, the description of the machine P and its input I. The job of H is from this description, which has been given to it on its (H's) tape, determine whether the program (ie P) and its input (ie I) when run will finish running or not. ie, will P(I) Halt when run of run forever. H's 'input' never does anything, it is just data. The job of H was to determine what the machine which that input describes (ie P(I) ) will do. I.e. H(H^,H^) needs to answer what H^(H^) does. H^(H^) has been shown to Halt, and H(H^,H^) says it doesn't Halt. Halt != Doesn't Halt, so H was WRONG.
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| From | Ben Bacarisse <ben.usenet@bsb.me.uk> |
|---|---|
| Date | 2021-08-04 19:37 +0100 |
| Subject | Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ Only Inputs Count ] |
| Message-ID | <87tuk52h0e.fsf@bsb.me.uk> |
| In reply to | #37568 |
olcott <NoOne@NoWhere.com> writes: > On 8/2/2021 7:11 PM, Ben Bacarisse wrote: >> olcott <NoOne@NoWhere.com> writes: >> >>> On 8/2/2021 2:10 PM, Ben Bacarisse wrote: >>>> olcott <NoOne@NoWhere.com> writes: >>>> >>>>> On 8/1/2021 5:54 AM, Ben Bacarisse wrote: >>>> >>>>>> I am happy you have a notation you like. Are you prepared to address >>>>>> that fact that your H^ is not "as in Linz"? >>>>> >>>>> My Ĥ is exactly the Linz Ĥ with the additional elaboration that the >>>>> second wildcard state transition ⊢* is defined to be a simulating halt >>>>> decider. >>>> No. I've explained many times now why your Ĥ is not at all "the Linz >>>> Ĥ". Do you see any point in my doing so again? >> I suspect not. You certainly have not asked a single question that >> could help you to understand why your Ĥ is irrelevant. >> >>>>>> We all know you are declaring that to be correct. Here's why your Ĥ is >>>>>> not "as in Linz". Linz requires that >>>>>> >>>>>> Ĥ.q0 wM ⊢* Ĥ.qx wM wM ⊢* Ĥ.qn >>>>>> if M applied to wM does not halt >>>>>> >>>>>> Any Ĥ that eventually transitions to Ĥ.qn on input wM must do so >>>>>> if, and only if, the encoded M applied to wM does not halt. But you've >>>>>> given us a case where your Ĥ is not like this: >>>>>> >>>>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn >>>>> >>>>> And when we eliminate the fallacy of equivocation error we have >>>>> >>>>> Ĥ[0].q0 ⟨Ĥ⟩ ⊢* Ĥ[0].qx ⟨Ĥ[1]⟩ ⟨Ĥ[2]⟩ ⊢* Ĥ[0].qn >>>> The only thing I think you are equivocating on is pretending that Ĥ[0] >>>> is not Ĥ, and it doesn't look as if you've removed that error. I think >>>> you /should/ remove it so that you can be saying something of value >>>> about Ĥ. >>> >>> It is clear from the text that Linz does specify at least three >>> different instances of Ĥ, The TM the TMD input ⟨Ĥ⟩ and a copy of this >>> TMD input. >> Still equivocating. Either Ĥ[0] = Ĥ or you are wasting everyone's time. >> (This is mathematical equality. Ĥ is a tuple of sets. If Ĥ[0] is not >> exactly identical in every way to Ĥ then I don't care about it. Note >> that I'm not disputing your right, for ease of explanation, to give >> identical things more than one name. But the same permission allows me >> to use any of the names because they name the same thing.) >> You are wrong because >> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qn >> where Linz requires that >> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qn >> if (and only if) Ĥ applied to ⟨Ĥ⟩ does not halt. > > You have the above incorrectly in these two > M refers to the Turing Machine described by wM. > > Ĥ.q0 wM ⊢* Ĥ.qx wM wM ⊢* Ĥ.qy ∞ > if M applied to wM halts, and > > Ĥ.q0 wM ⊢* Ĥ.qx wM wM ⊢* Ĥ.qn > if M applied to wM does not halt > > This is *NOT* the Ĥ that is executed. I have no idea what you are objecting to. You can substitute Ĥ and ⟨Ĥ⟩ into what Linz says, can't you? I did it above and you don't like it: For M = Ĥ and wM = ⟨Ĥ⟩ Linz tells us that Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn if Ĥ applied to ⟨Ĥ⟩ does not halt. Your Ĥ is not like that. Its behaviour is boring and obvious and trivial. -- Ben.
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| From | olcott <NoOne@NoWhere.com> |
|---|---|
| Date | 2021-08-04 15:37 -0500 |
| Subject | Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ Only Inputs Count ] |
| Message-ID | <zcadnTSOD5rtZ5f8nZ2dnUU7-T3NnZ2d@giganews.com> |
| In reply to | #37606 |
On 8/4/2021 1:37 PM, Ben Bacarisse wrote: > olcott <NoOne@NoWhere.com> writes: > >> On 8/2/2021 7:11 PM, Ben Bacarisse wrote: >>> olcott <NoOne@NoWhere.com> writes: >>> >>>> On 8/2/2021 2:10 PM, Ben Bacarisse wrote: >>>>> olcott <NoOne@NoWhere.com> writes: >>>>> >>>>>> On 8/1/2021 5:54 AM, Ben Bacarisse wrote: >>>>> >>>>>>> I am happy you have a notation you like. Are you prepared to address >>>>>>> that fact that your H^ is not "as in Linz"? >>>>>> >>>>>> My Ĥ is exactly the Linz Ĥ with the additional elaboration that the >>>>>> second wildcard state transition ⊢* is defined to be a simulating halt >>>>>> decider. >>>>> No. I've explained many times now why your Ĥ is not at all "the Linz >>>>> Ĥ". Do you see any point in my doing so again? >>> I suspect not. You certainly have not asked a single question that >>> could help you to understand why your Ĥ is irrelevant. >>> >>>>>>> We all know you are declaring that to be correct. Here's why your Ĥ is >>>>>>> not "as in Linz". Linz requires that >>>>>>> >>>>>>> Ĥ.q0 wM ⊢* Ĥ.qx wM wM ⊢* Ĥ.qn >>>>>>> if M applied to wM does not halt >>>>>>> >>>>>>> Any Ĥ that eventually transitions to Ĥ.qn on input wM must do so >>>>>>> if, and only if, the encoded M applied to wM does not halt. But you've >>>>>>> given us a case where your Ĥ is not like this: >>>>>>> >>>>>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn >>>>>> >>>>>> And when we eliminate the fallacy of equivocation error we have >>>>>> >>>>>> Ĥ[0].q0 ⟨Ĥ⟩ ⊢* Ĥ[0].qx ⟨Ĥ[1]⟩ ⟨Ĥ[2]⟩ ⊢* Ĥ[0].qn >>>>> The only thing I think you are equivocating on is pretending that Ĥ[0] >>>>> is not Ĥ, and it doesn't look as if you've removed that error. I think >>>>> you /should/ remove it so that you can be saying something of value >>>>> about Ĥ. >>>> >>>> It is clear from the text that Linz does specify at least three >>>> different instances of Ĥ, The TM the TMD input ⟨Ĥ⟩ and a copy of this >>>> TMD input. >>> Still equivocating. Either Ĥ[0] = Ĥ or you are wasting everyone's time. >>> (This is mathematical equality. Ĥ is a tuple of sets. If Ĥ[0] is not >>> exactly identical in every way to Ĥ then I don't care about it. Note >>> that I'm not disputing your right, for ease of explanation, to give >>> identical things more than one name. But the same permission allows me >>> to use any of the names because they name the same thing.) >>> You are wrong because >>> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qn >>> where Linz requires that >>> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qn >>> if (and only if) Ĥ applied to ⟨Ĥ⟩ does not halt. >> >> You have the above incorrectly in these two >> M refers to the Turing Machine described by wM. >> >> Ĥ.q0 wM ⊢* Ĥ.qx wM wM ⊢* Ĥ.qy ∞ >> if M applied to wM halts, and >> >> Ĥ.q0 wM ⊢* Ĥ.qx wM wM ⊢* Ĥ.qn >> if M applied to wM does not halt >> >> This is *NOT* the Ĥ that is executed. > > I have no idea what you are objecting to. You can substitute Ĥ and ⟨Ĥ⟩ > into what Linz says, can't you? I did it above and you don't like it: > > For M = Ĥ and wM = ⟨Ĥ⟩ Linz tells us that > > Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn > if Ĥ applied to ⟨Ĥ⟩ does not halt. > > Your Ĥ is not like that. Its behaviour is boring and obvious and > trivial. > This is how it really is: if ⟨Ĥ⟩ applied to ⟨Ĥ⟩ does not halt. and ⟨Ĥ⟩ applied to ⟨Ĥ⟩ never reaches its final state. -- Copyright 2021 Pete Olcott "Great spirits have always encountered violent opposition from mediocre minds." Einstein
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| From | Ben Bacarisse <ben.usenet@bsb.me.uk> |
|---|---|
| Date | 2021-08-04 23:23 +0100 |
| Subject | Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ Only Inputs Count ] |
| Message-ID | <877dh03l3c.fsf@bsb.me.uk> |
| In reply to | #37612 |
olcott <NoOne@NoWhere.com> writes: > On 8/4/2021 1:37 PM, Ben Bacarisse wrote: >> olcott <NoOne@NoWhere.com> writes: >> >>> On 8/2/2021 7:11 PM, Ben Bacarisse wrote: >>>> olcott <NoOne@NoWhere.com> writes: >>>> >>>>> On 8/2/2021 2:10 PM, Ben Bacarisse wrote: >>>>>> olcott <NoOne@NoWhere.com> writes: >>>>>> >>>>>>> On 8/1/2021 5:54 AM, Ben Bacarisse wrote: >>>>>> >>>>>>>> I am happy you have a notation you like. Are you prepared to address >>>>>>>> that fact that your H^ is not "as in Linz"? >>>>>>> >>>>>>> My Ĥ is exactly the Linz Ĥ with the additional elaboration that the >>>>>>> second wildcard state transition ⊢* is defined to be a simulating halt >>>>>>> decider. >>>>>> No. I've explained many times now why your Ĥ is not at all "the Linz >>>>>> Ĥ". Do you see any point in my doing so again? >>>> I suspect not. You certainly have not asked a single question that >>>> could help you to understand why your Ĥ is irrelevant. >>>> >>>>>>>> We all know you are declaring that to be correct. Here's why your Ĥ is >>>>>>>> not "as in Linz". Linz requires that >>>>>>>> >>>>>>>> Ĥ.q0 wM ⊢* Ĥ.qx wM wM ⊢* Ĥ.qn >>>>>>>> if M applied to wM does not halt >>>>>>>> >>>>>>>> Any Ĥ that eventually transitions to Ĥ.qn on input wM must do so >>>>>>>> if, and only if, the encoded M applied to wM does not halt. But you've >>>>>>>> given us a case where your Ĥ is not like this: >>>>>>>> >>>>>>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn >>>>>>> >>>>>>> And when we eliminate the fallacy of equivocation error we have >>>>>>> >>>>>>> Ĥ[0].q0 ⟨Ĥ⟩ ⊢* Ĥ[0].qx ⟨Ĥ[1]⟩ ⟨Ĥ[2]⟩ ⊢* Ĥ[0].qn >>>>>> The only thing I think you are equivocating on is pretending that Ĥ[0] >>>>>> is not Ĥ, and it doesn't look as if you've removed that error. I think >>>>>> you /should/ remove it so that you can be saying something of value >>>>>> about Ĥ. >>>>> >>>>> It is clear from the text that Linz does specify at least three >>>>> different instances of Ĥ, The TM the TMD input ⟨Ĥ⟩ and a copy of this >>>>> TMD input. >>>> Still equivocating. Either Ĥ[0] = Ĥ or you are wasting everyone's time. >>>> (This is mathematical equality. Ĥ is a tuple of sets. If Ĥ[0] is not >>>> exactly identical in every way to Ĥ then I don't care about it. Note >>>> that I'm not disputing your right, for ease of explanation, to give >>>> identical things more than one name. But the same permission allows me >>>> to use any of the names because they name the same thing.) >>>> You are wrong because >>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qn >>>> where Linz requires that >>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qn >>>> if (and only if) Ĥ applied to ⟨Ĥ⟩ does not halt. >>> >>> You have the above incorrectly in these two >>> M refers to the Turing Machine described by wM. >>> >>> Ĥ.q0 wM ⊢* Ĥ.qx wM wM ⊢* Ĥ.qy ∞ >>> if M applied to wM halts, and >>> >>> Ĥ.q0 wM ⊢* Ĥ.qx wM wM ⊢* Ĥ.qn >>> if M applied to wM does not halt >>> >>> This is *NOT* the Ĥ that is executed. >> I have no idea what you are objecting to. You can substitute Ĥ and ⟨Ĥ⟩ >> into what Linz says, can't you? I did it above and you don't like it: >> For M = Ĥ and wM = ⟨Ĥ⟩ Linz tells us that >> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn >> if Ĥ applied to ⟨Ĥ⟩ does not halt. >> Your Ĥ is not like that. Its behaviour is boring and obvious and >> trivial. > > This is how it really is: > if ⟨Ĥ⟩ applied to ⟨Ĥ⟩ does not halt. > and ⟨Ĥ⟩ applied to ⟨Ĥ⟩ never reaches its final state. No. ⟨Ĥ⟩ is a string, not a TM. The TM that string represents is Ĥ and Ĥ applied to ⟨Ĥ⟩ does halt. -- Ben.
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| From | olcott <NoOne@NoWhere.com> |
|---|---|
| Date | 2021-08-04 22:37 -0500 |
| Subject | Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ Only Inputs Count ] |
| Message-ID | <Z5adnd038KGXwJb8nZ2dnUU7-I_NnZ2d@giganews.com> |
| In reply to | #37615 |
On 8/4/2021 5:23 PM, Ben Bacarisse wrote: > olcott <NoOne@NoWhere.com> writes: > >> On 8/4/2021 1:37 PM, Ben Bacarisse wrote: >>> olcott <NoOne@NoWhere.com> writes: >>> >>>> On 8/2/2021 7:11 PM, Ben Bacarisse wrote: >>>>> olcott <NoOne@NoWhere.com> writes: >>>>> >>>>>> On 8/2/2021 2:10 PM, Ben Bacarisse wrote: >>>>>>> olcott <NoOne@NoWhere.com> writes: >>>>>>> >>>>>>>> On 8/1/2021 5:54 AM, Ben Bacarisse wrote: >>>>>>> >>>>>>>>> I am happy you have a notation you like. Are you prepared to address >>>>>>>>> that fact that your H^ is not "as in Linz"? >>>>>>>> >>>>>>>> My Ĥ is exactly the Linz Ĥ with the additional elaboration that the >>>>>>>> second wildcard state transition ⊢* is defined to be a simulating halt >>>>>>>> decider. >>>>>>> No. I've explained many times now why your Ĥ is not at all "the Linz >>>>>>> Ĥ". Do you see any point in my doing so again? >>>>> I suspect not. You certainly have not asked a single question that >>>>> could help you to understand why your Ĥ is irrelevant. >>>>> >>>>>>>>> We all know you are declaring that to be correct. Here's why your Ĥ is >>>>>>>>> not "as in Linz". Linz requires that >>>>>>>>> >>>>>>>>> Ĥ.q0 wM ⊢* Ĥ.qx wM wM ⊢* Ĥ.qn >>>>>>>>> if M applied to wM does not halt >>>>>>>>> >>>>>>>>> Any Ĥ that eventually transitions to Ĥ.qn on input wM must do so >>>>>>>>> if, and only if, the encoded M applied to wM does not halt. But you've >>>>>>>>> given us a case where your Ĥ is not like this: >>>>>>>>> >>>>>>>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn >>>>>>>> >>>>>>>> And when we eliminate the fallacy of equivocation error we have >>>>>>>> >>>>>>>> Ĥ[0].q0 ⟨Ĥ⟩ ⊢* Ĥ[0].qx ⟨Ĥ[1]⟩ ⟨Ĥ[2]⟩ ⊢* Ĥ[0].qn >>>>>>> The only thing I think you are equivocating on is pretending that Ĥ[0] >>>>>>> is not Ĥ, and it doesn't look as if you've removed that error. I think >>>>>>> you /should/ remove it so that you can be saying something of value >>>>>>> about Ĥ. >>>>>> >>>>>> It is clear from the text that Linz does specify at least three >>>>>> different instances of Ĥ, The TM the TMD input ⟨Ĥ⟩ and a copy of this >>>>>> TMD input. >>>>> Still equivocating. Either Ĥ[0] = Ĥ or you are wasting everyone's time. >>>>> (This is mathematical equality. Ĥ is a tuple of sets. If Ĥ[0] is not >>>>> exactly identical in every way to Ĥ then I don't care about it. Note >>>>> that I'm not disputing your right, for ease of explanation, to give >>>>> identical things more than one name. But the same permission allows me >>>>> to use any of the names because they name the same thing.) >>>>> You are wrong because >>>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qn >>>>> where Linz requires that >>>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qn >>>>> if (and only if) Ĥ applied to ⟨Ĥ⟩ does not halt. >>>> >>>> You have the above incorrectly in these two >>>> M refers to the Turing Machine described by wM. >>>> >>>> Ĥ.q0 wM ⊢* Ĥ.qx wM wM ⊢* Ĥ.qy ∞ >>>> if M applied to wM halts, and >>>> >>>> Ĥ.q0 wM ⊢* Ĥ.qx wM wM ⊢* Ĥ.qn >>>> if M applied to wM does not halt >>>> >>>> This is *NOT* the Ĥ that is executed. >>> I have no idea what you are objecting to. You can substitute Ĥ and ⟨Ĥ⟩ >>> into what Linz says, can't you? I did it above and you don't like it: >>> For M = Ĥ and wM = ⟨Ĥ⟩ Linz tells us that >>> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn >>> if Ĥ applied to ⟨Ĥ⟩ does not halt. >>> Your Ĥ is not like that. Its behaviour is boring and obvious and >>> trivial. >> >> This is how it really is: >> if ⟨Ĥ⟩ applied to ⟨Ĥ⟩ does not halt. >> and ⟨Ĥ⟩ applied to ⟨Ĥ⟩ never reaches its final state. > > No. ⟨Ĥ⟩ is a string, not a TM. The TM that string represents is Ĥ and > Ĥ applied to ⟨Ĥ⟩ does halt. > Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qy ∞ Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn The question is not: Does Ĥ halt on its input? The question is: Does the Turing Machine description ⟨Ĥ⟩ specify a computation that reaches its final state on input ⟨Ĥ⟩? Do you agree with this? -- Copyright 2021 Pete Olcott "Great spirits have always encountered violent opposition from mediocre minds." Einstein
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| From | Richard Damon <Richard@Damon-Family.org> |
|---|---|
| Date | 2021-08-04 22:48 -0500 |
| Subject | Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ Only Inputs Count ] |
| Message-ID | <GcJOI.2151$lK.2002@fx41.iad> |
| In reply to | #37630 |
On 8/4/21 9:37 PM, olcott wrote: > On 8/4/2021 5:23 PM, Ben Bacarisse wrote: >> olcott <NoOne@NoWhere.com> writes: >> >>> On 8/4/2021 1:37 PM, Ben Bacarisse wrote: >>>> olcott <NoOne@NoWhere.com> writes: >>>> >>>>> On 8/2/2021 7:11 PM, Ben Bacarisse wrote: >>>>>> olcott <NoOne@NoWhere.com> writes: >>>>>> >>>>>>> On 8/2/2021 2:10 PM, Ben Bacarisse wrote: >>>>>>>> olcott <NoOne@NoWhere.com> writes: >>>>>>>> >>>>>>>>> On 8/1/2021 5:54 AM, Ben Bacarisse wrote: >>>>>>>> >>>>>>>>>> I am happy you have a notation you like. Are you prepared to >>>>>>>>>> address >>>>>>>>>> that fact that your H^ is not "as in Linz"? >>>>>>>>> >>>>>>>>> My Ĥ is exactly the Linz Ĥ with the additional elaboration that >>>>>>>>> the >>>>>>>>> second wildcard state transition ⊢* is defined to be a >>>>>>>>> simulating halt >>>>>>>>> decider. >>>>>>>> No. I've explained many times now why your Ĥ is not at all "the >>>>>>>> Linz >>>>>>>> Ĥ". Do you see any point in my doing so again? >>>>>> I suspect not. You certainly have not asked a single question that >>>>>> could help you to understand why your Ĥ is irrelevant. >>>>>> >>>>>>>>>> We all know you are declaring that to be correct. Here's why >>>>>>>>>> your Ĥ is >>>>>>>>>> not "as in Linz". Linz requires that >>>>>>>>>> >>>>>>>>>> Ĥ.q0 wM ⊢* Ĥ.qx wM wM ⊢* Ĥ.qn >>>>>>>>>> if M applied to wM does not halt >>>>>>>>>> >>>>>>>>>> Any Ĥ that eventually transitions to Ĥ.qn on input wM must do so >>>>>>>>>> if, and only if, the encoded M applied to wM does not halt. >>>>>>>>>> But you've >>>>>>>>>> given us a case where your Ĥ is not like this: >>>>>>>>>> >>>>>>>>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn >>>>>>>>> >>>>>>>>> And when we eliminate the fallacy of equivocation error we have >>>>>>>>> >>>>>>>>> Ĥ[0].q0 ⟨Ĥ⟩ ⊢* Ĥ[0].qx ⟨Ĥ[1]⟩ ⟨Ĥ[2]⟩ ⊢* Ĥ[0].qn >>>>>>>> The only thing I think you are equivocating on is pretending >>>>>>>> that Ĥ[0] >>>>>>>> is not Ĥ, and it doesn't look as if you've removed that error. >>>>>>>> I think >>>>>>>> you /should/ remove it so that you can be saying something of value >>>>>>>> about Ĥ. >>>>>>> >>>>>>> It is clear from the text that Linz does specify at least three >>>>>>> different instances of Ĥ, The TM the TMD input ⟨Ĥ⟩ and a copy of >>>>>>> this >>>>>>> TMD input. >>>>>> Still equivocating. Either Ĥ[0] = Ĥ or you are wasting everyone's >>>>>> time. >>>>>> (This is mathematical equality. Ĥ is a tuple of sets. If Ĥ[0] is >>>>>> not >>>>>> exactly identical in every way to Ĥ then I don't care about it. Note >>>>>> that I'm not disputing your right, for ease of explanation, to give >>>>>> identical things more than one name. But the same permission >>>>>> allows me >>>>>> to use any of the names because they name the same thing.) >>>>>> You are wrong because >>>>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qn >>>>>> where Linz requires that >>>>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qn >>>>>> if (and only if) Ĥ applied to ⟨Ĥ⟩ does not halt. >>>>> >>>>> You have the above incorrectly in these two >>>>> M refers to the Turing Machine described by wM. >>>>> >>>>> Ĥ.q0 wM ⊢* Ĥ.qx wM wM ⊢* Ĥ.qy ∞ >>>>> if M applied to wM halts, and >>>>> >>>>> Ĥ.q0 wM ⊢* Ĥ.qx wM wM ⊢* Ĥ.qn >>>>> if M applied to wM does not halt >>>>> >>>>> This is *NOT* the Ĥ that is executed. >>>> I have no idea what you are objecting to. You can substitute Ĥ and ⟨Ĥ⟩ >>>> into what Linz says, can't you? I did it above and you don't like it: >>>> For M = Ĥ and wM = ⟨Ĥ⟩ Linz tells us that >>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn >>>> if Ĥ applied to ⟨Ĥ⟩ does not halt. >>>> Your Ĥ is not like that. Its behaviour is boring and obvious and >>>> trivial. >>> >>> This is how it really is: >>> if ⟨Ĥ⟩ applied to ⟨Ĥ⟩ does not halt. >>> and ⟨Ĥ⟩ applied to ⟨Ĥ⟩ never reaches its final state. >> >> No. ⟨Ĥ⟩ is a string, not a TM. The TM that string represents is Ĥ and >> Ĥ applied to ⟨Ĥ⟩ does halt. >> > > Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qy ∞ > Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn > > The question is not: Does Ĥ halt on its input? > > The question is: Does the Turing Machine description ⟨Ĥ⟩ specify a > computation that reaches its final state on input ⟨Ĥ⟩? > > Do you agree with this? > > The question is does the machine specified by description reach its final state when given the specified input in a finite number of steps. Description ONLY specify Computation via the Turing Machine they represent. Maybe that is your confusion.
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| From | Ben Bacarisse <ben.usenet@bsb.me.uk> |
|---|---|
| Date | 2021-08-05 23:14 +0100 |
| Subject | Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ Only Inputs Count ] |
| Message-ID | <8735rn1qvj.fsf@bsb.me.uk> |
| In reply to | #37630 |
olcott <NoOne@NoWhere.com> writes: > On 8/4/2021 5:23 PM, Ben Bacarisse wrote: >> olcott <NoOne@NoWhere.com> writes: >> >>> On 8/4/2021 1:37 PM, Ben Bacarisse wrote: >>>> olcott <NoOne@NoWhere.com> writes: >>>> >>>>> On 8/2/2021 7:11 PM, Ben Bacarisse wrote: >>>>>> You are wrong because >>>>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qn >>>>>> where Linz requires that >>>>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qn >>>>>> if (and only if) Ĥ applied to ⟨Ĥ⟩ does not halt. >>>>> >>>>> You have the above incorrectly in these two >>>>> M refers to the Turing Machine described by wM. >>>>> >>>>> Ĥ.q0 wM ⊢* Ĥ.qx wM wM ⊢* Ĥ.qy ∞ >>>>> if M applied to wM halts, and >>>>> >>>>> Ĥ.q0 wM ⊢* Ĥ.qx wM wM ⊢* Ĥ.qn >>>>> if M applied to wM does not halt >>>>> >>>>> This is *NOT* the Ĥ that is executed. >>>> >>>> I have no idea what you are objecting to. You can substitute Ĥ and ⟨Ĥ⟩ >>>> into what Linz says, can't you? I did it above and you don't like it: >>>> For M = Ĥ and wM = ⟨Ĥ⟩ Linz tells us that >>>> >>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn >>>> if Ĥ applied to ⟨Ĥ⟩ does not halt. >>>> >>>> Your Ĥ is not like that. Its behaviour is boring and obvious and >>>> trivial. >>> >>> This is how it really is: >>> if ⟨Ĥ⟩ applied to ⟨Ĥ⟩ does not halt. >>> and ⟨Ĥ⟩ applied to ⟨Ĥ⟩ never reaches its final state. >> No. ⟨Ĥ⟩ is a string, not a TM. The TM that string represents is Ĥ and >> Ĥ applied to ⟨Ĥ⟩ does halt. > > Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qy ∞ > Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn > > The question is not: Does Ĥ halt on its input? Yes it is. You deliberately missed out the words used by Linz for each of those cases: "if Ĥ applied to ŵ halts", and "if Ĥ applied to ŵ does not halt" (ŵ is his name for ⟨Ĥ⟩). As you can see this is /exactly/ the question that matters. Mind you, it's better to specify the input (as Linz does) rather than to say "its input". The context (Ĥ.q0 ⟨Ĥ⟩) makes it clear in this case, but there are lots of times when I have no idea what "its" refers to. You do it with "its simulation" too. > The question is: Does the Turing Machine description ⟨Ĥ⟩ specify a > computation that reaches its final state on input ⟨Ĥ⟩? > > Do you agree with this? No. ⟨Ĥ⟩ does not specify a computation. -- Ben.
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| From | olcott <NoOne@NoWhere.com> |
|---|---|
| Date | 2021-08-05 20:21 -0500 |
| Subject | Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ Only Inputs Count ] |
| Message-ID | <goydnfCCIYUWE5H8nZ2dnUU7-e_NnZ2d@giganews.com> |
| In reply to | #37655 |
On 8/5/2021 5:14 PM, Ben Bacarisse wrote: > olcott <NoOne@NoWhere.com> writes: > >> On 8/4/2021 5:23 PM, Ben Bacarisse wrote: >>> olcott <NoOne@NoWhere.com> writes: >>> >>>> On 8/4/2021 1:37 PM, Ben Bacarisse wrote: >>>>> olcott <NoOne@NoWhere.com> writes: >>>>> >>>>>> On 8/2/2021 7:11 PM, Ben Bacarisse wrote: > >>>>>>> You are wrong because >>>>>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qn >>>>>>> where Linz requires that >>>>>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qn >>>>>>> if (and only if) Ĥ applied to ⟨Ĥ⟩ does not halt. >>>>>> >>>>>> You have the above incorrectly in these two >>>>>> M refers to the Turing Machine described by wM. >>>>>> >>>>>> Ĥ.q0 wM ⊢* Ĥ.qx wM wM ⊢* Ĥ.qy ∞ >>>>>> if M applied to wM halts, and >>>>>> >>>>>> Ĥ.q0 wM ⊢* Ĥ.qx wM wM ⊢* Ĥ.qn >>>>>> if M applied to wM does not halt >>>>>> >>>>>> This is *NOT* the Ĥ that is executed. >>>>> >>>>> I have no idea what you are objecting to. You can substitute Ĥ and ⟨Ĥ⟩ >>>>> into what Linz says, can't you? I did it above and you don't like it: >>>>> For M = Ĥ and wM = ⟨Ĥ⟩ Linz tells us that >>>>> >>>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn >>>>> if Ĥ applied to ⟨Ĥ⟩ does not halt. >>>>> >>>>> Your Ĥ is not like that. Its behaviour is boring and obvious and >>>>> trivial. >>>> >>>> This is how it really is: >>>> if ⟨Ĥ⟩ applied to ⟨Ĥ⟩ does not halt. >>>> and ⟨Ĥ⟩ applied to ⟨Ĥ⟩ never reaches its final state. >>> No. ⟨Ĥ⟩ is a string, not a TM. The TM that string represents is Ĥ and >>> Ĥ applied to ⟨Ĥ⟩ does halt. >> >> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qy ∞ >> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn >> >> The question is not: Does Ĥ halt on its input? > > Yes it is. The question is: Does the Ĥ specified by the first ⟨Ĥ⟩ halt on its input ⟨Ĥ⟩ ? The ansswer to this question is provably no! Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn THIS IS NOT A CONTRADICTION > You deliberately missed out the words used by Linz for each > of those cases: "if Ĥ applied to ŵ halts", and "if Ĥ applied to ŵ does > not halt" (ŵ is his name for ⟨Ĥ⟩). As you can see this is /exactly/ the > question that matters. > > Mind you, it's better to specify the input (as Linz does) rather than to > say "its input". The context (Ĥ.q0 ⟨Ĥ⟩) makes it clear in this case, > but there are lots of times when I have no idea what "its" refers to. > You do it with "its simulation" too. > >> The question is: Does the Turing Machine description ⟨Ĥ⟩ specify a >> computation that reaches its final state on input ⟨Ĥ⟩? >> >> Do you agree with this? > > No. ⟨Ĥ⟩ does not specify a computation. > -- Copyright 2021 Pete Olcott "Great spirits have always encountered violent opposition from mediocre minds." Einstein
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| From | Richard Damon <Richard@Damon-Family.org> |
|---|---|
| Date | 2021-08-05 20:41 -0500 |
| Subject | Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ Only Inputs Count ] |
| Message-ID | <Tq0PI.2097$xY.185@fx05.iad> |
| In reply to | #37663 |
On 8/5/21 8:21 PM, olcott wrote: > On 8/5/2021 5:14 PM, Ben Bacarisse wrote: >> olcott <NoOne@NoWhere.com> writes: >> >>> On 8/4/2021 5:23 PM, Ben Bacarisse wrote: >>>> olcott <NoOne@NoWhere.com> writes: >>>> >>>>> On 8/4/2021 1:37 PM, Ben Bacarisse wrote: >>>>>> olcott <NoOne@NoWhere.com> writes: >>>>>> >>>>>>> On 8/2/2021 7:11 PM, Ben Bacarisse wrote: >> >>>>>>>> You are wrong because >>>>>>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qn >>>>>>>> where Linz requires that >>>>>>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qn >>>>>>>> if (and only if) Ĥ applied to ⟨Ĥ⟩ does not halt. >>>>>>> >>>>>>> You have the above incorrectly in these two >>>>>>> M refers to the Turing Machine described by wM. >>>>>>> >>>>>>> Ĥ.q0 wM ⊢* Ĥ.qx wM wM ⊢* Ĥ.qy ∞ >>>>>>> if M applied to wM halts, and >>>>>>> >>>>>>> Ĥ.q0 wM ⊢* Ĥ.qx wM wM ⊢* Ĥ.qn >>>>>>> if M applied to wM does not halt >>>>>>> >>>>>>> This is *NOT* the Ĥ that is executed. >>>>>> >>>>>> I have no idea what you are objecting to. You can substitute Ĥ >>>>>> and ⟨Ĥ⟩ >>>>>> into what Linz says, can't you? I did it above and you don't like >>>>>> it: >>>>>> For M = Ĥ and wM = ⟨Ĥ⟩ Linz tells us that >>>>>> >>>>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn >>>>>> if Ĥ applied to ⟨Ĥ⟩ does not halt. >>>>>> >>>>>> Your Ĥ is not like that. Its behaviour is boring and obvious and >>>>>> trivial. >>>>> >>>>> This is how it really is: >>>>> if ⟨Ĥ⟩ applied to ⟨Ĥ⟩ does not halt. >>>>> and ⟨Ĥ⟩ applied to ⟨Ĥ⟩ never reaches its final state. >>>> No. ⟨Ĥ⟩ is a string, not a TM. The TM that string represents is Ĥ and >>>> Ĥ applied to ⟨Ĥ⟩ does halt. >>> >>> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qy ∞ >>> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn >>> >>> The question is not: Does Ĥ halt on its input? >> >> Yes it is. > > The question is: > Does the Ĥ specified by the first ⟨Ĥ⟩ halt on its input ⟨Ĥ⟩ ? > The ansswer to this question is provably no! > > Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn THIS IS NOT A CONTRADICTION > It is provably that it does. Remember ALL copies of a given Turing Machine behave the same, so since one copy of H^(H^) is show to halt, ALL copies of it are also proved to Halt. If you claim that this copy of H^(H^) doesn't halt then either: The representation isn't correct, and your proof is thus bogus. H^ isn't actually a Turing Machine, which implies that H isn't a Turing Machine and your proof is thus bogus. or H^ isn't actual;y a Turing Machine because H^ wasn't built correctly according the the Linz etc formula, and thus your proof is bogus. Or, you proof is just bogus and it never proved what you claim it is. Which one is it? In my opinion, it really is all of the above.
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| From | Ben Bacarisse <ben.usenet@bsb.me.uk> |
|---|---|
| Date | 2021-08-06 03:36 +0100 |
| Subject | Re: Black box halt decider is NOT a partial decider [ Ĥ.qx(⟨Ĥ⟩,⟨Ĥ⟩) == Ĥ.qn ] [ Only Inputs Count ] |
| Message-ID | <87eeb7z4d1.fsf@bsb.me.uk> |
| In reply to | #37663 |
olcott <NoOne@NoWhere.com> writes: > On 8/5/2021 5:14 PM, Ben Bacarisse wrote: >> olcott <NoOne@NoWhere.com> writes: >>> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qy ∞ >>> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn >>> >>> The question is not: Does Ĥ halt on its input? >> Yes it is. > > The question is: > Does the Ĥ specified by the first ⟨Ĥ⟩ halt on its input ⟨Ĥ⟩ ? > The ansswer to this question is provably no! The question is: does Ĥ applied to ⟨Ĥ⟩ halt. It does: > Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn THIS IS NOT A CONTRADICTION Indeed. There is no contradiction. Just an Ĥ that does not meet Linz spec. -- Ben.
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| From | olcott <NoOne@NoWhere.com> |
|---|---|
| Date | 2021-08-05 21:54 -0500 |
| Subject | Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. |
| Message-ID | <0_Sdnb6Qe8XGOZH8nZ2dnUU7-U3NnZ2d@giganews.com> |
| In reply to | #37673 |
On 8/5/2021 9:36 PM, Ben Bacarisse wrote: > olcott <NoOne@NoWhere.com> writes: > >> On 8/5/2021 5:14 PM, Ben Bacarisse wrote: >>> olcott <NoOne@NoWhere.com> writes: > >>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qy ∞ >>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn >>>> >>>> The question is not: Does Ĥ halt on its input? >>> Yes it is. >> >> The question is: >> Does the Ĥ specified by the first ⟨Ĥ⟩ halt on its input ⟨Ĥ⟩ ? >> The ansswer to this question is provably no! > > The question is: does Ĥ applied to ⟨Ĥ⟩ halt. It does: > >> Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn THIS IS NOT A CONTRADICTION > > Indeed. There is no contradiction. Just an Ĥ that does not meet Linz > spec. > Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. Because it is correct it meets the Linz spec. if M applied to wM does not halt means if the execution of the machine of the first ⟨Ĥ⟩ on its input of the seocond ⟨Ĥ⟩ does not halt then ⊢* Ĥ.qn I have proved that the execution of the machine of the first ⟨Ĥ⟩ on its input of the second ⟨Ĥ⟩ does not halt. -- Copyright 2021 Pete Olcott "Great spirits have always encountered violent opposition from mediocre minds." Einstein
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| From | Richard Damon <Richard@Damon-Family.org> |
|---|---|
| Date | 2021-08-05 22:37 -0500 |
| Subject | Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. |
| Message-ID | <982PI.4528$Fx8.3541@fx45.iad> |
| In reply to | #37676 |
On 8/5/21 9:54 PM, olcott wrote: > On 8/5/2021 9:36 PM, Ben Bacarisse wrote: >> olcott <NoOne@NoWhere.com> writes: >> >>> On 8/5/2021 5:14 PM, Ben Bacarisse wrote: >>>> olcott <NoOne@NoWhere.com> writes: >> >>>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qy ∞ >>>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn >>>>> >>>>> The question is not: Does Ĥ halt on its input? >>>> Yes it is. >>> >>> The question is: >>> Does the Ĥ specified by the first ⟨Ĥ⟩ halt on its input ⟨Ĥ⟩ ? >>> The ansswer to this question is provably no! >> >> The question is: does Ĥ applied to ⟨Ĥ⟩ halt. It does: >> >>> Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn THIS IS NOT A CONTRADICTION >> >> Indeed. There is no contradiction. Just an Ĥ that does not meet Linz >> spec. >> > > Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. > Because it is correct it meets the Linz spec. > > if M applied to wM does not halt > means if the execution of the machine of the first ⟨Ĥ⟩ on its input of > the seocond ⟨Ĥ⟩ does not halt then ⊢* Ĥ.qn > > I have proved that the execution of the machine of the first ⟨Ĥ⟩ on its > input of the second ⟨Ĥ⟩ does not halt. > > Since M is H^, and H^ applied to H^, in other notations H^(<H^>), has been PROVED and accepted by you, to Halt when run as the actual Turing Machine What you have shown is that the ABORTED simulation done by H of H^ applied to H^ didn't reach its final state in the limited number of steps simulated, but from the trace of the actual run of H^(<H^>) we know that that exact same computation with the exact same trace segment, when it continues does reach that halting state. That H^.q0 <H^> reached H^.qn is PROOF that H^(<H^>) is a Halting computation, as H^.qn is a terminal Halting State off H^ We also have that since H^.qx is the equivalent of H.q0, and H^.qn is the equivalent of H.qn, the state where H responds that H has decided that its input is non-Halting, we also know that H(<H^>, <H^>) has decided the H^(<H^>) is non-Halting, and since we have just also showed that it actually is Halting (as the H^.qn is a halting state) we have shown that H was WRONG.
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| From | olcott <NoOne@NoWhere.com> |
|---|---|
| Date | 2021-08-05 22:44 -0500 |
| Subject | Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. |
| Message-ID | <rP2dnRpdyrC_LZH8nZ2dnUU7-e2dnZ2d@giganews.com> |
| In reply to | #37681 |
On 8/5/2021 10:37 PM, Richard Damon wrote: > On 8/5/21 9:54 PM, olcott wrote: >> On 8/5/2021 9:36 PM, Ben Bacarisse wrote: >>> olcott <NoOne@NoWhere.com> writes: >>> >>>> On 8/5/2021 5:14 PM, Ben Bacarisse wrote: >>>>> olcott <NoOne@NoWhere.com> writes: >>> >>>>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qy ∞ >>>>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn >>>>>> >>>>>> The question is not: Does Ĥ halt on its input? >>>>> Yes it is. >>>> >>>> The question is: >>>> Does the Ĥ specified by the first ⟨Ĥ⟩ halt on its input ⟨Ĥ⟩ ? >>>> The ansswer to this question is provably no! >>> >>> The question is: does Ĥ applied to ⟨Ĥ⟩ halt. It does: >>> >>>> Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn THIS IS NOT A CONTRADICTION >>> >>> Indeed. There is no contradiction. Just an Ĥ that does not meet Linz >>> spec. >>> >> >> Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. >> Because it is correct it meets the Linz spec. >> >> if M applied to wM does not halt >> means if the execution of the machine of the first ⟨Ĥ⟩ on its input of >> the seocond ⟨Ĥ⟩ does not halt then ⊢* Ĥ.qn >> >> I have proved that the execution of the machine of the first ⟨Ĥ⟩ on its >> input of the second ⟨Ĥ⟩ does not halt. >> >> > > Since M is H^, and H^ applied to H^, in other notations H^(<H^>), has > been PROVED and accepted by you, to Halt when run as the actual Turing > Machine > The input to Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ never halts. -- Copyright 2021 Pete Olcott "Great spirits have always encountered violent opposition from mediocre minds." Einstein
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| From | Richard Damon <news.x.richarddamon@xoxy.net> |
|---|---|
| Date | 2021-08-05 22:51 -0500 |
| Subject | Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. |
| Message-ID | <seibjs$k2d$1@dont-email.me> |
| In reply to | #37682 |
On 8/5/21 10:44 PM, olcott wrote: > On 8/5/2021 10:37 PM, Richard Damon wrote: >> On 8/5/21 9:54 PM, olcott wrote: >>> On 8/5/2021 9:36 PM, Ben Bacarisse wrote: >>>> olcott <NoOne@NoWhere.com> writes: >>>> >>>>> On 8/5/2021 5:14 PM, Ben Bacarisse wrote: >>>>>> olcott <NoOne@NoWhere.com> writes: >>>> >>>>>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qy ∞ >>>>>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn >>>>>>> >>>>>>> The question is not: Does Ĥ halt on its input? >>>>>> Yes it is. >>>>> >>>>> The question is: >>>>> Does the Ĥ specified by the first ⟨Ĥ⟩ halt on its input ⟨Ĥ⟩ ? >>>>> The ansswer to this question is provably no! >>>> >>>> The question is: does Ĥ applied to ⟨Ĥ⟩ halt. It does: >>>> >>>>> Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn THIS IS NOT A CONTRADICTION >>>> >>>> Indeed. There is no contradiction. Just an Ĥ that does not meet Linz >>>> spec. >>>> >>> >>> Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. >>> Because it is correct it meets the Linz spec. >>> >>> if M applied to wM does not halt >>> means if the execution of the machine of the first ⟨Ĥ⟩ on its input of >>> the seocond ⟨Ĥ⟩ does not halt then ⊢* Ĥ.qn >>> >>> I have proved that the execution of the machine of the first ⟨Ĥ⟩ on its >>> input of the second ⟨Ĥ⟩ does not halt. >>> >>> >> >> Since M is H^, and H^ applied to H^, in other notations H^(<H^>), has >> been PROVED and accepted by you, to Halt when run as the actual Turing >> Machine >> > > The input to Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ never halts. > Category error. Input don't halt or not, Machines Halt or not on an input. The machine that is described by <H^> <H^> is H^(<H^>) which has been accepted to be a Halting Computation, even by you, so your claim is false. The fact that an H that can answer H(<H^>, <H^>) will never run its simulation long enough to see it reach that terminal state just show the error in H, not that H^(<H^>) is non-Halting. Now, if you mean that H never halts when given <H^> <H^> as a input, then that is something different, that just shows that in that case, H has just proven that it fails to be a decider for that input.
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| From | Ben Bacarisse <ben.usenet@bsb.me.uk> |
|---|---|
| Date | 2021-08-08 01:34 +0100 |
| Subject | Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. |
| Message-ID | <87zgtslqpv.fsf@bsb.me.uk> |
| In reply to | #37676 |
olcott <NoOne@NoWhere.com> writes: > On 8/5/2021 9:36 PM, Ben Bacarisse wrote: >> olcott <NoOne@NoWhere.com> writes: >> >>> On 8/5/2021 5:14 PM, Ben Bacarisse wrote: >>>> olcott <NoOne@NoWhere.com> writes: >> >>>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qy ∞ >>>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn >>>>> >>>>> The question is not: Does Ĥ halt on its input? >>>> Yes it is. >>> >>> The question is: >>> Does the Ĥ specified by the first ⟨Ĥ⟩ halt on its input ⟨Ĥ⟩ ? >>> The ansswer to this question is provably no! >> The question is: does Ĥ applied to ⟨Ĥ⟩ halt. It does: >> >>> Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn THIS IS NOT A CONTRADICTION >> Indeed. There is no contradiction. Just an Ĥ that does not meet Linz >> spec. > > Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. > Because it is correct it meets the Linz spec. I find it startling that you think that, but then it seems you don't yet know what the key words mean: > if M applied to wM does not halt > means if the execution of the machine of the first ⟨Ĥ⟩ on its input of > the seocond ⟨Ĥ⟩ does not halt then ⊢* Ĥ.qn No. Would you like to know "what M applied to wM does not halt" means? Do you need help to see that "Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qn" is clearly a case of "M applied to wM halts"? -- Ben.
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| From | olcott <NoOne@NoWhere.com> |
|---|---|
| Date | 2021-08-09 17:32 -0500 |
| Subject | Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. |
| Message-ID | <4JOdnRS2SLR7MYz8nZ2dnUU7-YnNnZ2d@giganews.com> |
| In reply to | #37719 |
On 8/7/2021 7:34 PM, Ben Bacarisse wrote:
> olcott <NoOne@NoWhere.com> writes:
>
>> On 8/5/2021 9:36 PM, Ben Bacarisse wrote:
>>> olcott <NoOne@NoWhere.com> writes:
>>>
>>>> On 8/5/2021 5:14 PM, Ben Bacarisse wrote:
>>>>> olcott <NoOne@NoWhere.com> writes:
>>>
>>>>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qy ∞
>>>>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn
>>>>>>
>>>>>> The question is not: Does Ĥ halt on its input?
>>>>> Yes it is.
>>>>
>>>> The question is:
>>>> Does the Ĥ specified by the first ⟨Ĥ⟩ halt on its input ⟨Ĥ⟩ ?
>>>> The ansswer to this question is provably no!
>>> The question is: does Ĥ applied to ⟨Ĥ⟩ halt. It does:
>>>
>>>> Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn THIS IS NOT A CONTRADICTION
>>> Indeed. There is no contradiction. Just an Ĥ that does not meet Linz
>>> spec.
>>
>> Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction.
>> Because it is correct it meets the Linz spec.
>
> I find it startling that you think that, but then it seems you don't yet
> know what the key words mean:
>
>> if M applied to wM does not halt
>> means if the execution of the machine of the first ⟨Ĥ⟩ on its input of
>> the seocond ⟨Ĥ⟩ does not halt then ⊢* Ĥ.qn
>
> No. Would you like to know "what M applied to wM does not halt" means?
> Do you need help to see that "Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qn" is clearly a case of "M
> applied to wM halts"?
>
the Turing machine halting problem. Simply stated, the problem
is: given the description of a Turing machine M and an input w,
does M, when started in the initial configuration q0w, perform a
computation that eventually halts? (Linz:1990:317).
Ĥ.q0 wM ⊢* Ĥ.qx wM wM ⊢* Ĥ.qy ∞
Ĥ.q0 wM ⊢* Ĥ.qx wM wM ⊢* Ĥ.qn
When Ĥ is applied to ⟨Ĥ⟩ the description of the Turing Machine and its
input are specified as: ⟨Ĥ⟩ ⟨Ĥ⟩ for the embedded halt decider at Ĥ.qx.
When Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn this is not a final state of the simulated
input it is a final state of the executed Ĥ.
--
Copyright 2021 Pete Olcott
"Great spirits have always encountered violent opposition from mediocre
minds." Einstein
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| From | Richard Damon <Richard@Damon-Family.org> |
|---|---|
| Date | 2021-08-09 21:14 -0400 |
| Subject | Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. |
| Message-ID | <2qkQI.22663$Fx8.8260@fx45.iad> |
| In reply to | #37744 |
On 8/9/21 6:32 PM, olcott wrote: > On 8/7/2021 7:34 PM, Ben Bacarisse wrote: >> olcott <NoOne@NoWhere.com> writes: >> >>> On 8/5/2021 9:36 PM, Ben Bacarisse wrote: >>>> olcott <NoOne@NoWhere.com> writes: >>>> >>>>> On 8/5/2021 5:14 PM, Ben Bacarisse wrote: >>>>>> olcott <NoOne@NoWhere.com> writes: >>>> >>>>>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qy ∞ >>>>>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn >>>>>>> >>>>>>> The question is not: Does Ĥ halt on its input? >>>>>> Yes it is. >>>>> >>>>> The question is: >>>>> Does the Ĥ specified by the first ⟨Ĥ⟩ halt on its input ⟨Ĥ⟩ ? >>>>> The ansswer to this question is provably no! >>>> The question is: does Ĥ applied to ⟨Ĥ⟩ halt. It does: >>>> >>>>> Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn THIS IS NOT A CONTRADICTION >>>> Indeed. There is no contradiction. Just an Ĥ that does not meet Linz >>>> spec. >>> >>> Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. >>> Because it is correct it meets the Linz spec. >> >> I find it startling that you think that, but then it seems you don't yet >> know what the key words mean: >> >>> if M applied to wM does not halt >>> means if the execution of the machine of the first ⟨Ĥ⟩ on its input of >>> the seocond ⟨Ĥ⟩ does not halt then ⊢* Ĥ.qn >> >> No. Would you like to know "what M applied to wM does not halt" means? >> Do you need help to see that "Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qn" is clearly a case of "M >> applied to wM halts"? >> > > the Turing machine halting problem. Simply stated, the problem > is: given the description of a Turing machine M and an input w, > does M, when started in the initial configuration q0w, perform a > computation that eventually halts? (Linz:1990:317). > > Ĥ.q0 wM ⊢* Ĥ.qx wM wM ⊢* Ĥ.qy ∞ > Ĥ.q0 wM ⊢* Ĥ.qx wM wM ⊢* Ĥ.qn > > When Ĥ is applied to ⟨Ĥ⟩ the description of the Turing Machine and its > input are specified as: ⟨Ĥ⟩ ⟨Ĥ⟩ for the embedded halt decider at Ĥ.qx. > > When Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn this is not a final state of the simulated > input it is a final state of the executed Ĥ. > > H^.qn IS the Halting state of the H^ machine that is being run, which is what really counts. The fact that the simulated version of H^ had its simulation aborted means that the fact that this simulation didn't reach a halting state does NOT prove that machine is non-halting. The fact that a copy of the ACTUAL machine Halts, proves that it IS halting.
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| From | Ben Bacarisse <ben.usenet@bsb.me.uk> |
|---|---|
| Date | 2021-08-11 01:42 +0100 |
| Subject | Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. |
| Message-ID | <87zgtoizgp.fsf@bsb.me.uk> |
| In reply to | #37744 |
olcott <NoOne@NoWhere.com> writes: > On 8/7/2021 7:34 PM, Ben Bacarisse wrote: >> olcott <NoOne@NoWhere.com> writes: >> >>> On 8/5/2021 9:36 PM, Ben Bacarisse wrote: >>>> olcott <NoOne@NoWhere.com> writes: >>>> >>>>> On 8/5/2021 5:14 PM, Ben Bacarisse wrote: >>>>>> olcott <NoOne@NoWhere.com> writes: >>>> >>>>>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qy ∞ >>>>>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn >>>>>>> >>>>>>> The question is not: Does Ĥ halt on its input? >>>>>> Yes it is. >>>>> >>>>> The question is: >>>>> Does the Ĥ specified by the first ⟨Ĥ⟩ halt on its input ⟨Ĥ⟩ ? >>>>> The ansswer to this question is provably no! >>>> The question is: does Ĥ applied to ⟨Ĥ⟩ halt. It does: >>>> >>>>> Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn THIS IS NOT A CONTRADICTION >>>> Indeed. There is no contradiction. Just an Ĥ that does not meet Linz >>>> spec. >>> >>> Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. >>> Because it is correct it meets the Linz spec. >> I find it startling that you think that, but then it seems you don't yet >> know what the key words mean: >> >>> if M applied to wM does not halt >>> means if the execution of the machine of the first ⟨Ĥ⟩ on its input of >>> the seocond ⟨Ĥ⟩ does not halt then ⊢* Ĥ.qn >> No. Would you like to know "what M applied to wM does not halt" means? >> Do you need help to see that "Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qn" is clearly a case of "M >> applied to wM halts"? > > the Turing machine halting problem. Simply stated, the problem > is: given the description of a Turing machine M and an input w, > does M, when started in the initial configuration q0w, perform a > computation that eventually halts? (Linz:1990:317). Yes. I was offering to help you understand the key words in that text. > Ĥ.q0 wM ⊢* Ĥ.qx wM wM ⊢* Ĥ.qy ∞ > Ĥ.q0 wM ⊢* Ĥ.qx wM wM ⊢* Ĥ.qn You've missed off the key lines yet again. Is that deliberate? They are the lines that show you are wrong so I am suspicious that you keep omitting them. > When Ĥ is applied to ⟨Ĥ⟩ the description of the Turing Machine and its > input are specified as: ⟨Ĥ⟩ ⟨Ĥ⟩ for the embedded halt decider at Ĥ.qx. Ungrammatical. > When Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn this is not a final state of the simulated > input it is a final state of the executed Ĥ. Yes. You don't seem to know why that's wrong. If you'd like to know, ask me questions. If you want to keep just saying things for the fun of it, you are doing just fine without any help. -- Ben.
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| From | olcott <NoOne@NoWhere.com> |
|---|---|
| Date | 2021-08-10 19:46 -0500 |
| Subject | Re: Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. |
| Message-ID | <brCdnZyB6OOdg478nZ2dnUU7-ePNnZ2d@giganews.com> |
| In reply to | #37768 |
On 8/10/2021 7:42 PM, Ben Bacarisse wrote: > olcott <NoOne@NoWhere.com> writes: > >> On 8/7/2021 7:34 PM, Ben Bacarisse wrote: >>> olcott <NoOne@NoWhere.com> writes: >>> >>>> On 8/5/2021 9:36 PM, Ben Bacarisse wrote: >>>>> olcott <NoOne@NoWhere.com> writes: >>>>> >>>>>> On 8/5/2021 5:14 PM, Ben Bacarisse wrote: >>>>>>> olcott <NoOne@NoWhere.com> writes: >>>>> >>>>>>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qy ∞ >>>>>>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn >>>>>>>> >>>>>>>> The question is not: Does Ĥ halt on its input? >>>>>>> Yes it is. >>>>>> >>>>>> The question is: >>>>>> Does the Ĥ specified by the first ⟨Ĥ⟩ halt on its input ⟨Ĥ⟩ ? >>>>>> The ansswer to this question is provably no! >>>>> The question is: does Ĥ applied to ⟨Ĥ⟩ halt. It does: >>>>> >>>>>> Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn THIS IS NOT A CONTRADICTION >>>>> Indeed. There is no contradiction. Just an Ĥ that does not meet Linz >>>>> spec. >>>> >>>> Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn is correct and forms no contradiction. >>>> Because it is correct it meets the Linz spec. >>> I find it startling that you think that, but then it seems you don't yet >>> know what the key words mean: >>> >>>> if M applied to wM does not halt >>>> means if the execution of the machine of the first ⟨Ĥ⟩ on its input of >>>> the seocond ⟨Ĥ⟩ does not halt then ⊢* Ĥ.qn >>> No. Would you like to know "what M applied to wM does not halt" means? >>> Do you need help to see that "Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.qn" is clearly a case of "M >>> applied to wM halts"? >> >> the Turing machine halting problem. Simply stated, the problem >> is: given the description of a Turing machine M and an input w, >> does M, when started in the initial configuration q0w, perform a >> computation that eventually halts? (Linz:1990:317). > > Yes. I was offering to help you understand the key words in that text. > >> Ĥ.q0 wM ⊢* Ĥ.qx wM wM ⊢* Ĥ.qy ∞ >> Ĥ.q0 wM ⊢* Ĥ.qx wM wM ⊢* Ĥ.qn > > You've missed off the key lines yet again. Is that deliberate? They > are the lines that show you are wrong so I am suspicious that you keep > omitting them. > >> When Ĥ is applied to ⟨Ĥ⟩ the description of the Turing Machine and its >> input are specified as: ⟨Ĥ⟩ ⟨Ĥ⟩ for the embedded halt decider at Ĥ.qx. > > Ungrammatical. > >> When Ĥ.qx ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn this is not a final state of the simulated >> input it is a final state of the executed Ĥ. > > Yes. You don't seem to know why that's wrong. Because it is not wrong and you are lying and you can't possibly correctly show otherwise. > If you'd like to know, > ask me questions. If you want to keep just saying things for the fun of > it, you are doing just fine without any help. > -- Copyright 2021 Pete Olcott "Great spirits have always encountered violent opposition from mediocre minds." Einstein
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