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| Started by | sigismond kmiecik <sigismond.kmiecik@wanadoo.fr> |
|---|---|
| First post | 2011-06-21 12:36 +0000 |
| Last post | 2011-06-21 12:36 +0000 |
| Articles | 1 — 1 participant |
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How to transform a functional expression into a general expression sigismond kmiecik <sigismond.kmiecik@wanadoo.fr> - 2011-06-21 12:36 +0000
| From | sigismond kmiecik <sigismond.kmiecik@wanadoo.fr> |
|---|---|
| Date | 2011-06-21 12:36 +0000 |
| Subject | How to transform a functional expression into a general expression |
| Message-ID | <itq382$nck$1@smc.vnet.net> |
Hello to all I will take a simple example. How can you easily transform using Mathematica the following functional expression y = 3/2 x + 1 into its general equivalent: 3 x - 2 y + 2 = 0 This general form exists because y == 3/2 x + 1 // FullSimplify returns True. Is the answer given valid whatever the complexity of the initial equality expression known to be true (with up to three unknown variables). Thanks Sigismond Kmiecik
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