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| Started by | Alan <alan.isaac@gmail.com> |
|---|---|
| First post | 2011-05-01 10:22 +0000 |
| Last post | 2011-05-01 10:22 +0000 |
| Articles | 1 — 1 participant |
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Re: and color via PlotStyle Alan <alan.isaac@gmail.com> - 2011-05-01 10:22 +0000
| From | Alan <alan.isaac@gmail.com> |
|---|---|
| Date | 2011-05-01 10:22 +0000 |
| Subject | Re: and color via PlotStyle |
| Message-ID | <ipjc8c$j1d$1@smc.vnet.net> |
On Friday, April 29, 2011 7:33:39 AM UTC-4, Bill Rowe wrote: > [version 1] works as you are expecting only because the argument to > Plot is an explicit list. This is the only case where Plot uses > multiple colors. (Warning: Mathematica novice ahead.) I do not understand this statement. Do you mean the key is that Plot sees a head of List rather than of ReplaceAll? But as a novice I want to know, why does Plot see the ReplaceAll? What is the rule that determines whether or not a command will evaluate its argument before acting on it? > Plot always evaluates its arguments by > first substituting a numeric value for the independent variable > and only after that is the expression evaluated. The consequence > it for the argument above, Plot does not see a list of > expressions. Instead it sees a list of numeric values which is > treated as a single function with multiple values and > consequently plotted in a single color. Can you please restate that. I'm finding it opaque. (Also, is there no way to assign multiple colors to a mutiple valued function?) > There is no inconsistency in the behavior of Plot. The behavior > I am describing is well documented even if not always well understood. Can you please point to the documentation you have in mind here. Thanks! Alan Isaac
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