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Limit[f[x], x->a] vs. f[a]. When are they equal?

Started byRichard Fateman <fateman@cs.berkeley.edu>
First post2011-04-23 11:49 +0000
Last post2011-04-23 11:49 +0000
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  Limit[f[x], x->a]   vs. f[a].  When are they equal? Richard Fateman <fateman@cs.berkeley.edu> - 2011-04-23 11:49 +0000

#1841 — Limit[f[x], x->a] vs. f[a]. When are they equal?

FromRichard Fateman <fateman@cs.berkeley.edu>
Date2011-04-23 11:49 +0000
SubjectLimit[f[x], x->a] vs. f[a]. When are they equal?
Message-ID<iouecl$6g9$1@smc.vnet.net>
Let c=ComplexInfinity

then Mathematica (7.0) "knows" that Sin[c] is Indeterminate

but Limit[Sin[x],x->c]  is not evaluated.

I would have thought that if  f[a] is known, Limit[f[x],x->a] is
also known.

RJF

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