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Groups > comp.soft-sys.math.mathematica > #3660
| From | Andrzej Kozlowski <akoz@mimuw.edu.pl> |
|---|---|
| Newsgroups | comp.soft-sys.math.mathematica |
| Subject | Re: MultinormalDistribution Question |
| Date | 2011-07-11 11:01 +0000 |
| Organization | Steven M. Christensen and Associates, Inc and MathTensor, Inc. |
| Message-ID | <ivel76$89d$1@smc.vnet.net> (permalink) |
| References | <201107100901.FAA24634@smc.vnet.net> |
First, your covariance matrix is not symmetric definite. I think you probably meant:
CapSigma = {{sigma1^2, rho*sigma1*sigma2}, {rho*sigma1*sigma2,
sigma2^2}}
Assuming that, you can get the conditional expectation from the definition:
Integrate[y PDF[dist, {6.3, y}], {y, -Infinity, Infinity}]/
PDF[MarginalDistribution[dist, 1], 6.3]
5.6
Alternatively, you can use Mathematica 8 built in NExpectation function:
NExpectation[y \[Conditioned] 6.299 <= x <= 6.301, {x, y} \[Distributed] dist]
5.6
Once you have the conditional expectation, you can compute the conditional variance, e.g.
Chop[Integrate[(y - 5.6)^2*PDF[dist, {6.3, y}], {y, -Infinity, Infinity}]/PDF[MarginalDistribution[dist, 1], 6.3]]
0.0256
Andrzej Kozlowski
On 10 Jul 2011, at 11:01, Steve wrote:
> Hello,
>
> Can someone help me with this ?
>
> I have 2 normal distributions; dist1 describes x and dist2 describes
> y. Each are fully defined and are correlated to one another by the
> correlation coefficient. How can I detemine the mean and standard
> deviation of the expected normal distribution that is associated with
> a given x value from dist1 ?
>
> An example:
> mean1 = 5.8
> sigma1 =0 .2
>
> mean2 = 5.3
> sigma2 = 0.2
>
> Correlation Coefficient, rho = 0.6
>
> Given an x value of 6.3 (from dist1) what is the corresponding mean
> and standard deviation of y ?
>
> I can view the combined density function from the following:
>
> Mu = {mean1, mean2}
> CapSigma = {{sigma1^2, rho*sigma1*sigma2} , {rho, rho*sigma1*sigma2}
> dist = MultinormalDistribution[Mu,CapSigma]
> pdf = PDF[dist,{x,y}]
> plot1 = Plot3D[pdf, {x,4,7},{y,4,7}, PlotRange->All]
>
> but can't see how to determine the mean and the standard deviation of
> y for a given value of x, like 6.3
>
> Any help would be appreciated.
>
> Thanks,
>
> --Steve
>
>
>
>
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Re: MultinormalDistribution Question Andrzej Kozlowski <akoz@mimuw.edu.pl> - 2011-07-11 11:01 +0000
Re: MultinormalDistribution Question Steve <s123@epix.net> - 2011-07-17 10:03 +0000
Re: MultinormalDistribution Question Ray Koopman <koopman@sfu.ca> - 2011-07-19 10:54 +0000
Re: MultinormalDistribution Question Ray Koopman <koopman@sfu.ca> - 2011-07-20 10:36 +0000
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