Groups > comp.soft-sys.math.mathematica > #3140

Re: " for z>0

From	Vivek Joshi <vivekjjoshi29@gmail.com>
Newsgroups	comp.soft-sys.math.mathematica
Subject	Re: " for z>0
Date	2011-06-17 04:08 +0000
Organization	Steven M. Christensen and Associates, Inc and MathTensor, Inc.
Message-ID	<itek0o$s4f$1@smc.vnet.net> (permalink)
References	<201106160800.EAA13210@smc.vnet.net>

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You can use ComplexExpand[...], But is this what you are looking for ?

In[17]:= Simplify[Conjugate[Sqrt[-(t Cos[2 kx] Cos[ky])+Cos[kx]+M]],-(t
Cos[2 kx] Cos[ky])+Cos[kx]+M>0]//ComplexExpand

Out[17]= ((M+Cos[kx]-t Cos[2 kx] Cos[ky])^2)^(1/4) Cos[1/2 Arg[M+Cos[kx]-t
Cos[2 kx] Cos[ky]]]-I ((M+Cos[kx]-t Cos[2 kx] Cos[ky])^2)^(1/4) Sin[1/2
Arg[M+Cos[kx]-t Cos[2 kx] Cos[ky]]]

Vivek J. Joshi

On Thu, Jun 16, 2011 at 4:00 AM, liblenovo <liblenovo@gmail.com> wrote:

> In[86]:=Simplify[Conjugate[Sqrt[-(t Cos[2 kx] Cos[ky]) + Cos[kx] +
> M] ], -(t Cos[2 kx] Cos[ky]) + Cos[kx] + M > 0]
>
> Out[86]= Sqrt[-t cos(2 kx) cos(ky)+cos(kx)+M]^\[Conjugate]
>
> I don't want that  ^\[Conjugate], why it is there?
>
>

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Re: " for z>0 Vivek Joshi <vivekjjoshi29@gmail.com> - 2011-06-17 04:08 +0000

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