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Re: Solve / Reduce isolating results.

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>   {SQ1 -> 5292,  XX -> 0.25}
> ... I want positive numbers & NOT Complex..

Hi.  Just to be different... I just added XX > 0 to your original equations:


equ={(1/6)*((SQ1*196)*2)^3-(1/6)*((((2.75+XX)*((3.75+XX)*21^2))*100)*2)^3==1.2902698935932682*^18,

(1/6)*((SQ1*100)*2)^3-(1/6)*((((2.75+XX)*((3.75+XX)*21^2))*36)*2)^3==1.883856772422697*^17,
 XX>0} //Rationalize[#,0]& //Simplify

{
30118144/3 (-128520857088+SQ1^3-11390625 (11/4+XX)^3 (15/4+XX)^3)==0,
(4000000 SQ1^3)/3==197605142784 (953344+27 (11/4+XX)^3 (15/4+XX)^3),
XX>0
}

t=Solve[equ,{SQ1,XX},Reals]

{{SQ1->5292,XX->1/4}}

= = = = = = = = = =
HTH  : >)
Dana DeLouis
= = = = = = = = = =


On Apr 29, 7:35 am, "Lea Rebanks" <lreba...@netvigator.com> wrote:
> Dear All,
>
> Given the enclosed code - see below.
> Please could someone help me setup the code to Solve / Reduce for these 2
> missing values only required
>
>   {SQ1 -> 5292,
>     XX -> 0.25}
>
> (I don't want multiple results.) I want positive numbers & NOT Complex..
>
> Many thanks for your help & attention, really appreciated. Please see below.
>
> Best regards,
> Lea...
> ...................................................................
>
> Clear[SQ1]
> Clear[XX]
> Solve[{(1/6)*((SQ1*196)*2)^3 -
>          (1/6)*((((2.75 + XX)*((3.75 + XX)*21^2))*100)*2)^3 ==
>        1.2902698935932682*^18, (1/6)*((SQ1*100)*2)^3 -
>          (1/6)*((((2.75 + XX)*((3.75 + XX)*21^2))*36)*2)^3 ==
>        1.883856772422697*^17}, {SQ1, XX}]

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Re: Solve / Reduce isolating results. Dana DeLouis <dana.del@gmail.com> - 2011-05-04 10:36 +0000

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