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Groups > comp.soft-sys.math.mathematica > #1607
| From | Murray Eisenberg <murray@math.umass.edu> |
|---|---|
| Newsgroups | comp.soft-sys.math.mathematica |
| Subject | Re: How to plot derivative directly? |
| Date | 2011-04-12 09:53 +0000 |
| Organization | Steven M. Christensen and Associates, Inc and MathTensor, Inc. |
| Message-ID | <io17eb$i4j$1@smc.vnet.net> (permalink) |
The trouble, as you probably realize, is that when Plot feeds in a value
of x to its first argument, you are now trying to take the derivative of
a constant with respect to a constant.
Another way to do it is:
f[x_]:= x^3 - 6 (x + 1)^2 + x - 7
Plot[f'[x],{x,-3,8}]
Or, perhaps a bit better f the function is much more complicated:
Plot[Evaluate[f'[x],{x,-3,8}]
On 4/11/2011 7:05 AM, =8Aer=FDch Jakub wrote:
> Dear mathgroup,
>
> it seems to me, that response to my question shall be very simple,
> but I cannot find it. :-(
>
> I want to plot the derivative of the function. I would like to do it
> directly, something like:
>
> Plot[D[x^3 - 6 (x + 1)^2 + x - 7, x],{x,-3,8}]
>
> It returns: General::ivar: "-2.99978 is not a valid variable."
>
> I can understand that it is because local variable x from Plot command
> interferes with the x variable from the D[].
>
> Yes I can bypass the problem by:
> deriv = D[x^3 - 6 (x + 1)^2 + x - 7, x]
> Plot[deriv, {x, -3, 8}]
>
> which is fully functional, but as far as I know Mathematica, there must
> be some simple solution how to do it directly inside the Plot[].
>
> Thanks in advance for kick-off
>
> Jakub
>
--
Murray Eisenberg murray@math.umass.edu
Mathematics & Statistics Dept.
Lederle Graduate Research Tower phone 413 549-1020 (H)
University of Massachusetts 413 545-2859 (W)
710 North Pleasant Street fax 413 545-1801
Amherst, MA 01003-9305
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Re: How to plot derivative directly? Murray Eisenberg <murray@math.umass.edu> - 2011-04-12 09:53 +0000
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